[amp_mcq option1=”common emitter” option2=”common collector” option3=”common base” option4=”none of the above” correct=”option3″]
Transistors
2. A transistor is connected in CB mode. If it is not connected in CE mode with same bias voltages, the values of IE, IB and IC will ___________
[amp_mcq option1=”remain the same” option2=”increase” option3=”decrease” option4=”none of the above” correct=”option2″]
3. The collector of a transistor is ___________ doped
[amp_mcq option1=”heavily” option2=”moderately” option3=”lightly” option4=”none of the above” correct=”option1″]
Detailed SolutionThe collector of a transistor is ___________ doped
4. If Q of an LC circuit increases, then bandwidth ___________
[amp_mcq option1=”Increases” option2=”Decreases” option3=”Remains the same” option4=”Insufficient data” correct=”option1″]
Detailed SolutionIf Q of an LC circuit increases, then bandwidth ___________
5. A tuned amplifier is generally operated in ___________ operation
[amp_mcq option1=”Class A” option2=”Class C” option3=”Class B” option4=”None of the above” correct=”option3″]
Detailed SolutionA tuned amplifier is generally operated in ___________ operation
6. The phase difference between the input and output voltages in a common base arrangement is ___________
[amp_mcq option1=”180°” option2=”90°” option3=”270°” option4=”0°” correct=”option1″]
7. Operating point represents ___________
[amp_mcq option1=”Values of IC and VCE when signal is applied” option2=”The magnitude of signal” option3=”Zero signal values of IC and VCE” option4=”None of the above” correct=”option1″]
8. The voltage gain in a transistor connected in ___________ arrangement is the highest
[amp_mcq option1=”common base” option2=”common collector” option3=”common emitter” option4=”none of the above” correct=”option3″]
9. In a transistor, the base current is about ___________ of emitter current
[amp_mcq option1=”25%” option2=”20%” option3=”35%” option4=”5%” correct=”option3″]
Detailed SolutionIn a transistor, the base current is about ___________ of emitter current
10. IC = [a/(1 – a )] IB + [. . . . . . . . /(1 – a)]?
[amp_mcq option1=”ICBO” option2=”ICEO” option3=”IC” option4=”IE” correct=”option1″]
Detailed SolutionIC = [a/(1 – a )] IB + [. . . . . . . . /(1 – a)]?