Two cubes, each of volume 125 cm are joined end to end. The surface area of the resulting cuboid is :

The correct answer is (c) 200 cm.

The surface area of a cuboid is given by the formula $2(lb+bh+lh)$, where $l$, $b$, and $h$ are the length, breadth, and height of the cuboid.

In this case, the length and breadth of the cuboid are equal to the side length of each cube, which is $\sqrt[3]{125}=5$ cm. The height of the cuboid is the sum of the side lengths of the two cubes, which is $10$ cm.

Therefore, the surface area of the cuboid is $2(5\times5+5\times10+10\times5)=200$ cm.

Option