At time 1.10 pm the angle between two arms of a clock is

The correct answer is (c).

At 1.10 pm, the hour hand is between 1 and 2, so it is pointing at an angle of $\frac{1}{12} \times 360^\circ = 30^\circ$. The minute hand is pointing at 10, so it is pointing at an angle of $\frac{10}{60} \times 360^\circ = 60^\circ$. The angle between the two hands