Buckminster fullerene, which looks like a football, is an allotropic form of
UPSC NDA-2
42. Which one of the following alloys contains a non-metal as one of its c
Which one of the following alloys contains a non-metal as one of its constituent ?
43. Galvanization is a method of protecting iron from rusting by coating w
Galvanization is a method of protecting iron from rusting by coating with a thin layer of
44. Sita, 1·5 m high, stands before a plane mirror fixed on a wall to view
Sita, 1·5 m high, stands before a plane mirror fixed on a wall to view her full image. What should be the minimum height of the plane mirror so that Sita can view her image fully ?
45. The heating element in an electric iron is usually made of
The heating element in an electric iron is usually made of
46. The potential difference between the two end terminals of an electric
The potential difference between the two end terminals of an electric heater is 220 V and the current through it is 0·5 A. What would be the current through the heater if the potential difference across the terminals of the heater is reduced to 120 V ?
– First, calculate the resistance (R) of the heater using the initial conditions: V1 = 220 V, I1 = 0.5 A.
– R = V1 / I1 = 220 V / 0.5 A = 440 ohms.
– Now, use this resistance to find the new current (I2) when the potential difference (V2) is 120 V.
– V2 = I2 * R
– 120 V = I2 * 440 ohms
– I2 = 120 V / 440 ohms = 12 / 44 A = 3 / 11 A.
– Calculating the decimal value: 3 / 11 ≈ 0.2727 A.
47. The flash of lightning is seen before the thunderstorm is heard. It ve
The flash of lightning is seen before the thunderstorm is heard. It verifies that
– Light (the flash) and sound (the thunder) are both produced by the same event.
– We see the light almost instantly because the speed of light in air is extremely high (approximately 3 x 10^8 m/s).
– We hear the thunder later because the speed of sound in air is much lower (approximately 343 m/s at 20°C).
– The time delay between seeing the flash and hearing the thunder is directly proportional to the distance of the thunderstorm.
48. The streaming of light beams coming from the Sun through trees is said
The streaming of light beams coming from the Sun through trees is said to have suggested that light travels in straight line. The particles on the path of light beams are visible to us because
– When light encounters particles in the air, such as dust, smoke, or water droplets, it interacts with them.
– Scattering occurs when light waves are deflected in various directions by these particles.
– Some of the scattered light is directed towards our eyes, making the path of the light beam visible.
– This phenomenon is related to the Tyndall effect, which is the scattering of light by particles in a colloid or suspension.
49. A microphone converts
A microphone converts
– Its function is to capture sound (which consists of variations in air pressure) and transform it into a corresponding electrical voltage or current signal.
– Different types of microphones use different principles (e.g., electromagnetic induction in dynamic microphones, capacitance change in condenser microphones) to achieve this conversion.
– The electrical signal produced by a microphone can then be amplified, recorded, or transmitted.
50. A bullet of mass 10 g is horizontally fired with velocity 300 m s$^{-1
A bullet of mass 10 g is horizontally fired with velocity 300 m s$^{-1}$ from a pistol of mass 1 kg. What is the recoil velocity of the pistol?
– The total momentum of the system (pistol + bullet) before firing is zero, as both are at rest.
– According to the conservation of momentum, the total momentum of the system after firing must also be zero.
– Let $m_b$ and $v_b$ be the mass and velocity of the bullet, and $m_p$ and $v_p$ be the mass and recoil velocity of the pistol.
– Momentum before firing = 0
– Momentum after firing = $m_b v_b + m_p v_p$
– By conservation of momentum: $m_b v_b + m_p v_p = 0$
– Given: $m_b = 10 \text{ g} = 0.01 \text{ kg}$, $v_b = 300 \text{ m/s}$, $m_p = 1 \text{ kg}$.
– Substituting the values: $(0.01 \text{ kg})(300 \text{ m/s}) + (1 \text{ kg}) v_p = 0$
– $3 \text{ kg} \cdot \text{m/s} + v_p \text{ kg} = 0$
– $v_p = -3 \text{ m/s}$