Who among the following was the founder of the Young Bengal Movement ?
[amp_mcq option1=”Henry Vivian Derozio” option2=”David Hare” option3=”Dwarkanath Tagore” option4=”Prasanna Kumar Tagore” correct=”option1″]
Who among the following was the founder of the Young Bengal Movement ?
[amp_mcq option1=”Henry Vivian Derozio” option2=”David Hare” option3=”Dwarkanath Tagore” option4=”Prasanna Kumar Tagore” correct=”option1″]
Who among the following was the founder of the Avadh Kingdom in the 18th century ?
[amp_mcq option1=”Murshid Quli Khan” option2=”Saadat Khan” option3=”Alivardi Khan” option4=”Sarfaraz Khan” correct=”option2″]
Who among the following was believed to be a leader of the Sanyasis and Fakirs conspiring against the British in 1857 ?
[amp_mcq option1=”Mangal Pandey” option2=”Bahadur Shah II” option3=”Queen Zeenat Mahal” option4=”Nana Sahib” correct=”option4″]
Who among the following can attend the meetings of both Houses of Parliament while not being a member of either House ?
[amp_mcq option1=”The Solicitor General of India” option2=”The Vice-President of India” option3=”The Comptroller and Auditor General of India” option4=”The Attorney General of India” correct=”option4″]
Which one of the following statements about the Ilbert Bill is correct ?
[amp_mcq option1=”It proposed that the Indian magistrates would try Europeans in criminal cases.” option2=”It allowed Indians to file criminal cases against Europeans.” option3=”It authorized Indian ICS officers to try Europeans in courts.” option4=”It was an agitation led by Ilbert in support of the nationalists.” correct=”option1″]
The proposition ‘equal volumes of different gases contain equal numbers of molecules at the same temperature and pressure’ is known as
[amp_mcq option1=”Avogadro’s hypothesis” option2=”Gay-Lussac’s hypothesis” option3=”Planck’s hypothesis” option4=”Kirchhoff’s theory” correct=”option1″]
The compound C6H12O4 contains
[amp_mcq option1=”22 atoms per mole” option2=”twice the mass percent of H as compared to the mass percent of C” option3=”six times the mass percent of C as compared to the mass percent of H” option4=”thrice the mass percent of H as compared to the mass percent of O” correct=”option3″]
Let’s evaluate the options:
A) 22 atoms per mole: One molecule contains 6 + 12 + 4 = 22 atoms. One mole contains Avogadro’s number of molecules, so one mole contains 22 * Avogadro’s number of atoms, not just 22 atoms. Incorrect.
B) twice the mass percent of H as compared to the mass percent of C: Mass of C is 72, Mass of H is 12. Is %H = 2 * %C? (12/148)*100% vs 2 * (72/148)*100%. This simplifies to 12 vs 2*72=144. Clearly incorrect. Is %C = 2 * %H? 72 vs 2*12=24. Incorrect.
C) six times the mass percent of C as compared to the mass percent of H: This is poorly phrased but implies a ratio. Let’s check if %C = 6 * %H. Mass of C is 72, Mass of H is 12. 72 = 6 * 12. Yes, the mass of Carbon in the compound is six times the mass of Hydrogen. Since the mass percentages are (mass of element / total mass) * 100%, if Mass of C = 6 * Mass of H, then %C = 6 * %H. This holds true.
D) thrice the mass percent of H as compared to the mass percent of O: Mass of H is 12, Mass of O is 64. Is %O = 3 * %H? 64 vs 3*12=36. Incorrect. Is %H = 3 * %O? 12 vs 3*64. Incorrect.
Option C is the only statement that accurately reflects the mass composition of the compound, interpreting “six times the mass percent of C as compared to the mass percent of H” as the mass percent of C being six times the mass percent of H.
The species that has the same number of electrons as 3517Cl is
[amp_mcq option1=”3216S” option2=”3416S+” option3=”4018Ar+” option4=”3516S2-” correct=”option3″]
The principal use of hydrofluoric acid is
[amp_mcq option1=”in etching glass” option2=”as a bleaching agent” option3=”as an extremely strong oxidizing agent” option4=”in the preparation of strong organic fluorine compounds” correct=”option1″]
Which compound, when dissolved in water, conducts electricity and forms a basic solution ?
[amp_mcq option1=”HCl” option2=”CH₃COOH” option3=”CH₃OH” option4=”NaOH” correct=”option4″]