Who among the following was the founder of the Young Bengal Movement ?
UPSC NDA-2
2. Who among the following was the founder of the Avadh Kingdom in the 18
Who among the following was the founder of the Avadh Kingdom in the 18th century ?
3. Who among the following was believed to be a leader of the Sanyasis an
Who among the following was believed to be a leader of the Sanyasis and Fakirs conspiring against the British in 1857 ?
4. Who among the following can attend the meetings of both Houses of Parl
Who among the following can attend the meetings of both Houses of Parliament while not being a member of either House ?
5. Which one of the following statements about the Ilbert Bill is correct
Which one of the following statements about the Ilbert Bill is correct ?
6. The proposition ‘equal volumes of different gases contain equal number
The proposition ‘equal volumes of different gases contain equal numbers of molecules at the same temperature and pressure’ is known as
7. The compound C 6 H 12 O 4 contains
The compound C6H12O4 contains
Mass of C in one molecule = 6 * 12 = 72
Mass of H in one molecule = 12 * 1 = 12
Mass of O in one molecule = 4 * 16 = 64
Total mass of one molecule (or molar mass) = 72 + 12 + 64 = 148.
Let’s evaluate the options:
A) 22 atoms per mole: One molecule contains 6 + 12 + 4 = 22 atoms. One mole contains Avogadro’s number of molecules, so one mole contains 22 * Avogadro’s number of atoms, not just 22 atoms. Incorrect.
B) twice the mass percent of H as compared to the mass percent of C: Mass of C is 72, Mass of H is 12. Is %H = 2 * %C? (12/148)*100% vs 2 * (72/148)*100%. This simplifies to 12 vs 2*72=144. Clearly incorrect. Is %C = 2 * %H? 72 vs 2*12=24. Incorrect.
C) six times the mass percent of C as compared to the mass percent of H: This is poorly phrased but implies a ratio. Let’s check if %C = 6 * %H. Mass of C is 72, Mass of H is 12. 72 = 6 * 12. Yes, the mass of Carbon in the compound is six times the mass of Hydrogen. Since the mass percentages are (mass of element / total mass) * 100%, if Mass of C = 6 * Mass of H, then %C = 6 * %H. This holds true.
D) thrice the mass percent of H as compared to the mass percent of O: Mass of H is 12, Mass of O is 64. Is %O = 3 * %H? 64 vs 3*12=36. Incorrect. Is %H = 3 * %O? 12 vs 3*64. Incorrect.
Option C is the only statement that accurately reflects the mass composition of the compound, interpreting “six times the mass percent of C as compared to the mass percent of H” as the mass percent of C being six times the mass percent of H.
%C = (72/148) * 100% ≈ 48.65%
%H = (12/148) * 100% ≈ 8.11%
%O = (64/148) * 100% ≈ 43.24%
Check C: 6 * %H = 6 * 8.11% ≈ 48.66%, which is very close to %C (48.65%).
8. The species that has the same number of electrons as 35 17 Cl is
The species that has the same number of electrons as 3517Cl is
A) 3216S: Atomic number 16. Neutral Sulfur has 16 electrons.
B) 3416S+: Atomic number 16. Neutral Sulfur has 16 electrons. S⁺ means it lost 1 electron (16 – 1 = 15 electrons).
C) 4018Ar+: Atomic number 18. Neutral Argon has 18 electrons. Ar⁺ means it lost 1 electron (18 – 1 = 17 electrons).
D) 3516S2-: Atomic number 16. Neutral Sulfur has 16 electrons. S²⁻ means it gained 2 electrons (16 + 2 = 18 electrons).
Therefore, 4018Ar+ has 17 electrons, the same number as neutral 3517Cl. These species are isoelectronic.
9. The principal use of hydrofluoric acid is
The principal use of hydrofluoric acid is
10. Which compound, when dissolved in water, conducts electricity and form
Which compound, when dissolved in water, conducts electricity and forms a basic solution ?
A) HCl (Hydrochloric acid): A strong acid. Dissolves in water to form H⁺ and Cl⁻ ions, conducting electricity. Forms an acidic solution (high concentration of H⁺).
B) CH₃COOH (Acetic acid): A weak acid. Partially dissociates in water to form H⁺ and CH₃COO⁻ ions, conducting electricity weakly. Forms an acidic solution.
C) CH₃OH (Methanol): An alcohol. Does not ionize in water. Does not conduct electricity. Forms a neutral solution.
D) NaOH (Sodium hydroxide): A strong base. Dissolves in water to form Na⁺ and OH⁻ ions, conducting electricity well. Forms a basic solution (high concentration of OH⁻).
Only NaOH satisfies both conditions: conducting electricity (due to ion formation) and forming a basic solution (due to OH⁻ production).