98 m
490 m
980 m
1960 m
Answer is Wrong!
Answer is Right!
The correct answer is $\boxed{\text{B}}$.
The horizontal range of a projectile is given by the following formula:
$$R = \frac{v^2 \sin^2 \theta}{g}$$
where $v$ is the initial velocity, $\theta$ is the angle of projection, and $g$ is the acceleration due to gravity.
In this case, $v = 98 \text{ m/s}$ and $\theta = 45^\circ$. Plugging these values into the formula,
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