The average of four consecutive even numbers is The largest of these numbers will be:

The correct answer is (d).

Let $x$ be the smallest of the four consecutive even numbers. Then the other three numbers are $x+2$, $x+4$, and $x+6$. The average of these four numbers is $x+(x+2)+(x+4)+(x+6)/4=4x+12/4=x+3$. We are given that the average is 28, so $x+3=28$ and $x=25$. Therefore, the largest of the four consecutive even numbers is $x+6=\boxed{31}$.

Here is a brief explanation of each option:

• Option (a): 36 is not a consecutive even number.
• Option (b): 32 is not a consecutive even number.
• Option (c): 30 is not the largest of the four consecutive even
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