In the series 3, 9, 15,………….what will be the 21st term?

117
121
123
129

The answer is $\boxed{\text{D}}$.

The given series is an arithmetic progression with a common difference of $6$. This means that each term is $6$ more than the term before it. The first term is $3$, so the 21st term is equal to $3 + (21 – 1) \times 6 = 129$.

Option A is incorrect because $117$ is not a term in

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the given series.

Option B is incorrect because $121$ is not a term in the given series.

Option C is incorrect because $123$ is not a term in the given series.

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