If a microcomputer has a 64K memory, what are the hexadecimal notations for the first and last memory location? A. 0000, EEEE B. 0, 64 C. 0000, FFFF D. 0000, 9999 E. None of the above

The correct answer is C. 0000, FFFF.

A microcomputer with a 64K memory has 64 * 1024 = 65536 memory locations. In hexadecimal notation, this is 0000 to FFFF.

Option A is incorrect because EEEE is not a valid hexadecimal number.

Option B is incorrect because 0 is not a valid hexadecimal number.

Option D is incorrect because 9999 is not a valid hexadecimal number.

Option E is incorrect because C is the correct answer.