Doubling the operating frequency of a purely inductive circuit: A. doubles the amount of current through the inductors B. has no effect on the current through the inductors C. cuts the current through the inductors one-half D. increases the current, but by an amount that can be determined only by doing a complete analysis of the circuit E. None of the above

The correct answer is: D. increases the current, but by an amount that can be determined only by doing a complete analysis of the circuit.

The current through an inductor is proportional to the applied voltage and inversely proportional to the inductance. The inductance is a measure of how much an inductor resists changes in current. The higher the inductance, the less current will flow through the inductor for a given applied voltage.

The frequency of a circuit is the number of cycles per second that the current alternates. Doubling the frequency of a circuit doubles the number of cycles per second. This means that the current will alternate twice as often, and therefore the inductor will have twice as much time to resist the changes in current. This will cause the current to increase.

However, the amount of increase in current will depend on the other components in the circuit. For example, if the circuit also contains a resistor, the resistor will also resist the changes in current. This will cause the current to increase less than if there were no resistor in the circuit.

Therefore, the amount of increase in current can only be determined by doing a complete analysis of the circuit.

Here is a more detailed explanation of each option:

• Option A: Doubling the
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