Consider the sequence x[n] = {-4 – j5, 1 + j2, 4} The conjugate antisymmetric part of the sequence is

{-4 - j2.5, j2, 4 - j2.5}
{-j2.5, 1, j2.5}
{-j5, j2, 0}
{-4, 1, 4}

The correct answer is A.

The conjugate antisymmetric part of a sequence is defined as follows:

$$x_{an} = \overline{x_{-n}}$$

where $\overline{x}$ denotes the complex conjugate of $x$.

In this case, we have:

$$x[n] = {-4 – j5, 1 + j2, 4}$$

Therefore, the conjugate antisymmetric part of the sequence is:

$$x_{an} = \overline{x_{-n}} = {-4 + j5, 1 – j2, 4}$$

which can be simplified to:

$$x_{an} = {-4 – j2.5, j2, 4 – j2.5}$$

Here is a brief explanation of each option:

  • Option A: This is the correct answer. It is the 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube
conjugate antisymmetric part of the sequence, as defined above.
  • Option B: This is not the correct answer. It is the conjugate symmetric part of the sequence, which is defined as follows:
  • $$x_{an} = \overline{x_{n}}$$

    • Option C: This is not the correct answer. It is the real part of the sequence.
    • Option D: This is not the correct answer. It is the imaginary part of the sequence.
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