[amp_mcq option1=”its power factor will deteriorate” option2=”its power factor will increase” option3=”its power factor will remain unaffected” option4=”its power factor will be zero” correct=”option1″]
Detailed SolutionIf a transformer is switched on to a voltage more than the rated voltage
[amp_mcq option1=”on full-load” option2=”on overload” option3=”on leading power factor” option4=”on zero power factor” correct=”option1″]
Detailed SolutionA transformer can have regulation closer to zero
[amp_mcq option1=”copper loss” option2=”magnetising current” option3=”magnetising current and loss” option4=”efficiency of the transformer” correct=”option2″]
Detailed SolutionNo-load on a transformer is carried out to determine
[amp_mcq option1=”temperature rise” option2=”dielectric strength of oil” option3=”voltage ratio” option4=”copper loss” correct=”option1″]
Detailed SolutionThe maximum load that a power transformer can carry is limited by its
[amp_mcq option1=”$${{\text{B}}_{\max }}$$” option2=”$${{\text{B}}_{\max }}^{1.6}$$” option3=”$${{\text{B}}_{\max }}^{1.85}$$” option4=”$${{\text{B}}_{\max }}^{2.4}$$” correct=”option2″]
Detailed SolutionHysteresis loss in a transformer varies as (Bmax = maximum flux density)
[amp_mcq option1=”Circular type” option2=”Sandwich type” option3=”Cylindrical type” option4=”Rectangular type” correct=”option3″]
Detailed SolutionWhich type of winding is used in 3phase shell-type transformer?
[amp_mcq option1=”decreases the rotor current” option2=”increases the rotor current” option3=”rotor current becomes zero” option4=”rotor current rernains same” correct=”option1″]
[amp_mcq option1=”eddy current loss will decrease” option2=”eddy current loss will increase” option3=”eddy current loss will remain unchanged” option4=”none of the above” correct=”option2″]
Detailed SolutionFor given applied voltage, with the increase in frequency of the applied voltage
[amp_mcq option1=”Overfluxing protection” option2=”Buchholz relay” option3=”Overcurrent protection” option4=”All of the above” correct=”option4″]
[amp_mcq option1=”reduce hysteresis loss” option2=”reduce eddy current losses” option3=”reduce copper losses” option4=”reduce all above losses” correct=”option1″]