Signal processing

21. If $$F\left( s \right) = L\left| {f\left( t \right)} \right| = {K \over {\left( {s + 1} \right)\left( {{s^2} + 4} \right)}},$$ then $$\mathop {\lim }\limits_{t \to \infty } f\left( t \right)$$ is given by

$${K over 4}$$
Zero
Infinite
Undefined

Detailed SolutionIf $$F\left( s \right) = L\left|

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{f\left( t \right)} \right| = {K \over {\left( {s + 1} \right)\left( {{s^2} + 4} \right)}},$$ then $$\mathop {\lim }\limits_{t \to \infty } f\left( t \right)$$ is given by

22. A system with input x[n] and output y[n] is given as $$y\left( n \right) = \left( {\sin {5 \over 6}\pi n} \right)x\left( n \right).$$ The system is

Linear, stable and invertible
Non-linear, stable and non-invertible
Linear, stable and non-invertible
Linear, unstable and invertible

Detailed SolutionA system with input x[n] and output y[n] is given as

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$$y\left( n \right) = \left( {\sin {5 \over 6}\pi n} \right)x\left( n \right).$$ The system is

23. The Fourier transform of a voltage signal x(t) is X(f). The unit of |X(f)| is

Volt
Volt-sec
Volt/sec
Volt2

Detailed SolutionThe

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Fourier transform of a voltage signal x(t) is X(f). The unit of |X(f)| is

24. A rectangular pulse of duration T is applied to a filter matched to this input. The output of the filter is a

Rectangular pulse of duration T
Rectangular pulse of duration 2T
Triangular pulse
Sine function

Detailed

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SolutionA rectangular pulse of duration T is applied to a filter matched to this input. The output of the filter is a

25. If L[f(t)] = F(s), then L[f(t – T)] is equal to

esTF(s)
e-sTF(s)
$${{Fleft( s ight)} over {1 + {e^{sT}}}}$$
$${{Fleft( s ight)} over {1 - {e^{ - sT}}}}$$

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42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube
then L[f(t – T)] is equal to" class="read-more button" href="https://exam.pscnotes.com/mcq/if-lft-fs-then-lft-t-is-equal-to/#more-47390">Detailed SolutionIf L[f(t)] = F(s), then L[f(t – T)] is equal to

26. A signal $$2\cos \left( {{{2\pi } \over 3}t} \right) – \cos \left( {\pi t} \right)$$ is the input to an LTI system with the transfer function $$H\left( s \right) = {e^s} + {e^{ – s}}$$ If Ck denote the kth coefficient in the exponential Fourier series of the output signal, then C3 is equal to

0
1
2
3

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s}}$$ If Ck denote the kth coefficient in the exponential Fourier series of the output signal, then C3 is equal to" class="read-more
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button" href="https://exam.pscnotes.com/mcq/a-signal-2cos-left-2pi-over-3t-right-cos-left-pi-t-right-is-the-input-to-an-lti-system-with-the-transfer-function-hleft-s-right-es-e-s-if-c/#more-47360">Detailed SolutionA signal $$2\cos \left( {{{2\pi } \over 3}t} \right) – \cos \left( {\pi t} \right)$$ is the input to an LTI system with the transfer function $$H\left( s \right) = {e^s} + {e^{ – s}}$$ If Ck denote the kth coefficient in the exponential Fourier series of the output signal, then C3 is equal to

27. If $$sL\left[ {f\left( t \right)} \right] = {\omega \over {\left( {{s^2} + {\omega ^2}} \right)}},$$ then the value of $$\mathop {\lim }\limits_{t \to \infty } f\left( t \right)$$

Cannot be determined
Is zero
Is unity
Is infinite

Detailed SolutionIf $$sL\left[ {f\left( t \right)} \right] = {\omega \over {\left( {{s^2} + {\omega ^2}} \right)}},$$ then

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the value of $$\mathop {\lim }\limits_{t \to \infty } f\left( t \right)$$

28. A signal containing only two frequency components (3 kHz and 6 kHz) is sampled at the rate of 8 kHz, and then passed through a low pass filter with a cut-off frequency of 8 kHz. The filter output

Is an undistorted version of the original signal
Contains only the 3 kHz component
Contains the 3 kHz component and a spurious component of 2 kHz

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containing only two frequency components (3 kHz and 6 kHz) is sampled at the rate of 8 kHz, and then passed through a low pass filter with a cut-off frequency of 8 kHz. The filter output" class="read-more button" href="https://exam.pscnotes.com/mcq/a-signal-containing-only-two-frequency-components-3-khz-and-6-khz-is-sampled-at-the-rate-of-8-khz-and-then-passed-through-a-low-pass-filter-with-a-cut-off-frequency-of-8-khz-the-filter-output/#more-47112">Detailed SolutionA signal containing only two frequency components (3 kHz and 6 kHz) is sampled at the rate of 8 kHz, and then passed through a low pass filter with a cut-off frequency of 8 kHz. The filter output

29. A Hilbert transformer is a

Non-linear system
Non-causal system
Time-varying system
Low-pass system

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a" class="read-more button" href="https://exam.pscnotes.com/mcq/a-hilbert-transformer-is-a/#more-46960">Detailed SolutionA Hilbert transformer is a

30. The transfer function of a discrete time LTI system is given by $$H\left( z \right) = {{2 – {3 \over 4}{z^{ – 1}}} \over {1 – {3 \over 4}{z^{ – 1}} + {1 \over 8}{z^{ – 2}}}}$$ Consider the following statements: S1 : The system is stable and causal for $$ROC:\left| z \right| > {1 \over 2}$$ S2 : The system is stable but not causal for $$ROC:\left| z \right| < {1 \over 4}$$ S3 : The system is neither stable nor causal for $$ROC:{1 \over 4} < \left| z \right| < {1 \over 2}$$ Which one of the following statements is valid?

Both S1 and S2 are true
Both S2 and S3 true
Both S1 and S3 are true
S1, S2 and S3 are all true

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LTI system is given by $$H\left( z \right) = {{2 – {3 \over 4}{z^{ – 1}}} \over {1 – {3 \over 4}{z^{ – 1}} + {1 \over 8}{z^{ – 2}}}}$$ Consider the following statements: S1 : The system is stable and causal for $$ROC:\left| z \right| > {1 \over 2}$$ S2 : The system is stable but not causal for $$ROC:\left| z \right| < {1 \over 4}$$ S3 : The system is neither stable nor causal for $$ROC:{1 \over 4} < \left| z \right| < {1 \over 2}$$ Which one of the following statements is valid?" class="read-more button" href="https://exam.pscnotes.com/mcq/the-transfer-function-of-a-discrete-time-lti-system-is-given-by-hleft-z-right-2-3-over-4z-1-over-1-3-over-4z-1-1-over-8z-2-consider-the-follo/#more-46919">Detailed SolutionThe transfer
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function of a discrete time LTI system is given by $$H\left( z \right) = {{2 – {3 \over 4}{z^{ – 1}}} \over {1 – {3 \over 4}{z^{ – 1}} + {1 \over 8}{z^{ – 2}}}}$$ Consider the following statements: S1 : The system is stable and causal for $$ROC:\left| z \right| > {1 \over 2}$$ S2 : The system is stable but not causal for $$ROC:\left| z \right| < {1 \over 4}$$ S3 : The system is neither stable nor causal for $$ROC:{1 \over 4} < \left| z \right| < {1 \over 2}$$ Which one of the following statements is valid?

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