2. The rate of change of displacement of a body with respect to its surrounding, is known A. Velocity B. Acceleration C. Speed D. None of these

Velocity
Acceleration
Speed
None of these

Detailed SolutionThe rate of change of

11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube

displacement of a body with respect to its surrounding, is known A. Velocity B. Acceleration C. Speed D. None of these

3. A cube on a smooth horizontal surface A. Cannot be in stable equilibrium B. Cannot be in neutral equilibrium C. Cannot be in unstable equilibrium D. Can be in any of these states

Cannot be in stable equilibrium
Cannot be in neutral equilibrium
Cannot be in unstable equilibrium
Can be in any of these states

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B. Cannot be in neutral equilibrium C. Cannot be in unstable equilibrium D. Can be in any of these states" class="read-more button" href="https://exam.pscnotes.com/mcq/a-cube-on-a-smooth-horizontal-surface-a-cannot-be-in-stable-equilibrium-b-cannot-be-in-neutral-equilibrium-c-cannot-be-in-unstable-equilibrium-d-can-be-in-any-of-these-states/#more-6852">Detailed SolutionA cube on a smooth horizontal surface A. Cannot be in stable equilibrium B. Cannot be in neutral equilibrium C. Cannot be in unstable equilibrium D. Can be in any of these states

4. The Law of Polygon of Forces states that A. If a polygon representing the forces acting at point in a body is closed, the forces are in equilibrium B. If forces acting on a point can be represented in magnitude and direction by the sides of a polygon taken in order, then the resultant of the forces will be represented in magnitude and direction by t C. If forces acting on a point can be represented of a polygon taken in order, their sides of a polygon taken in order, their resultant will be represented in magnitude and direction by the closing side D. If forces acting on a point can be represented in magnitude and direction by the sides of a polygon in order, the forces are in equilibrium

If a polygon representing the forces acting at point in a body is closed, the forces are in equilibrium
If forces acting on a point can be represented in magnitude and direction by the sides of a polygon taken in order, then the resultant of the forces will be represented in magnitude and direction by t
If forces acting on a point can be represented of a polygon taken in order, their sides of a polygon taken in order, their resultant will be represented in magnitude and direction by the closing side
If forces acting on a point can be represented in magnitude and direction by the sides of a polygon in order, the forces are in equilibrium

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polygon taken in order, then the resultant of the forces will be represented in magnitude and direction by t C. If forces acting on a point can be represented of a polygon taken in order, their sides of a polygon taken in order, their resultant will be represented in magnitude and direction by the closing side D. If forces acting on a point can be represented in magnitude and direction by the sides of a polygon in order, the forces are in equilibrium" class="read-more button" href="https://exam.pscnotes.com/mcq/the-law-of-polygon-of-forces-states-that-a-if-a-polygon-representing-the-forces-acting-at-point-in-a-body-is-closed-the-forces-are-in-equilibrium-b-if-forces-acting-on-a-point-can-be-represented-in/#more-6851">Detailed SolutionThe Law of Polygon of Forces states that A. If a polygon representing the forces acting at point in a body is closed, the forces are in equilibrium B. If forces acting on a point can be represented in magnitude and direction by the sides of a polygon taken in order, then the resultant of the forces will be represented in magnitude and direction by t C. If forces acting on a point can be represented of a polygon taken in order, their sides of a polygon taken in order, their resultant will be represented in magnitude and direction by the closing side D. If forces acting on a point can be represented in magnitude and direction by the sides of a polygon in order, the forces are in equilibrium

5. The dimensions of power are A. M2L2T-2 B. ML2T-3 C. M2LT-2 D. MLT-2

M2L2T-2
ML2T-3
M2LT-2
MLT-2

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href="https://exam.pscnotes.com/mcq/the-dimensions-of-power-are-a-m2l2t-2-b-ml2t-3-c-m2lt-2-d-mlt-2/#more-6850">Detailed SolutionThe dimensions of power are A. M2L2T-2 B. ML2T-3 C. M2LT-2 D. MLT-2

6. If two forces are in equilibrium, then the forces must (i) Be equal in magnitude (ii) Be opposite in sense (iii) Act along the same line A. (i) and (ii) B. (i) and (iii) C. Only (i) D. All (i), (ii) and (iii)

(i) and (ii)
(i) and (iii)
Only (i)
All (i), (ii) and (iii)

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in sense (iii) Act along the same line A. (i) and (ii) B. (i) and (iii) C. Only (i) D. All (i), (ii) and (iii)" class="read-more button" href="https://exam.pscnotes.com/mcq/if-two-forces-are-in-equilibrium-then-the-forces-must-i-be-equal-in-magnitude-ii-be-opposite-in-sense-iii-act-along-the-same-line-a-i-and-ii-b-i-and-iii-c-only-i-d-all-i-ii-a/#more-6849">Detailed SolutionIf two forces are in equilibrium, then the forces must (i) Be equal in magnitude (ii) Be opposite in sense (iii) Act along the same line A. (i) and (ii) B. (i) and (iii) C. Only (i) D. All (i), (ii) and (iii)

7. Cartesian form of the equation of catenary is A. y = c cosh $$\frac{{\text{x}}}{{\text{c}}}$$ B. y = c sinh $$\frac{{\text{x}}}{{\text{c}}}$$ C. y = c tan $$\frac{{\text{x}}}{{\text{c}}}$$ D. y = c sin $$\frac{{\text{x}}}{{\text{c}}}$$

y = c cosh $$rac{{ ext{x}}}{{ ext{c}}}$$
y = c sinh $$rac{{ ext{x}}}{{ ext{c}}}$$
y = c tan $$rac{{ ext{x}}}{{ ext{c}}}$$
y = c sin $$rac{{ ext{x}}}{{ ext{c}}}$$

Detailed SolutionCartesian form of the equation of

catenary is A. y = c cosh $$\frac{{\text{x}}}{{\text{c}}}$$ B. y = c sinh $$\frac{{\text{x}}}{{\text{c}}}$$ C. y = c tan $$\frac{{\text{x}}}{{\text{c}}}$$ D. y = c sin $$\frac{{\text{x}}}{{\text{c}}}$$

8. The instantaneous centre of a member lies at the point of intersection of two lines drawn at the ends of the member such that the lines are inclined to the direction of motion of the ends at A. 30° B. 45° C. 60° D. 90°

30°
45°
60°
90°

Detailed SolutionThe instantaneous centre

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of a member lies at the point of intersection of two lines drawn at the ends of the member such that the lines are inclined to the direction of motion of the ends at A. 30° B. 45° C. 60° D. 90°

9. The direction of projection should bisect the angle between the inclined plane and the vertical for a range of a projectile on inclined plane A. To be zero B. To be maximum C. To be minimum D. None of these

To be zero
To be maximum
To be minimum
None of these

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448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube be zero B. To be maximum C. To be minimum D. None of these" class="read-more button" href="https://exam.pscnotes.com/mcq/the-direction-of-projection-should-bisect-the-angle-between-the-inclined-plane-and-the-vertical-for-a-range-of-a-projectile-on-inclined-plane-a-to-be-zero-b-to-be-maximum-c-to-be-minimum-d-none-of/#more-6846">Detailed SolutionThe direction of projection should bisect the angle between the inclined plane and the vertical for a range of a projectile on inclined plane A. To be zero B. To be maximum C. To be minimum D. None of these

10. The frequency of oscillation on moon as compared to that on earth, will be A. 2.44 times more B. 2.44 times less C. 3 times less D. 3 times more

2.44 times more
2.44 times less
3 times less
3 times more

Detailed SolutionThe frequency of oscillation on moon as compared

75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube

to that on earth, will be A. 2.44 times more B. 2.44 times less C. 3 times less D. 3 times more

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