The correct answer is $\boxed{\text{A. }275 \text{ J}}$.
The kinetic energy of an object is given by the formula:
$$E_k = \frac{1}{2}mv^2$$
where $m$ is the mass of the object and $v$ is its velocity.
In this case, we have $m = 22 \text{ kg}$ and $v = 5 \text{ m/s}$. Substituting these values into the formula, we get:
$$E_k = \frac{1}{2}(22 \text{ kg})(5 \text{ m/s})^2 = 275 \text{ J}$$
Therefore, the kinetic energy of the object is 275 J.
Option B is incorrect because it is half the correct answer. Option C is
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