The correct answer is $\boxed{\text{A. }0.207}$.
The maximum bending moment in a simply supported beam with two equal overhangs occurs at the support, and is equal to $wL^2/8$, where $w$ is the uniform load per unit length and $L$ is the total length of the beam. The ratio of the length of the overhang to the total length of the beam is $a/L$.
To minimize the maximum bending moment, we need to minimize $a/L$. The minimum value of $a/L$ is 0.207, which occurs when $a=0.207L$.
Here is a diagram of a simply supported beam with two equal overhangs:
[Diagram of a simply supported beam with two equal overhangs]
The maximum bending moment occurs at the support, and is equal to $wL^2/8$. The ratio of the length of the overhang to the total length of the beam is $a/L$.
The following are brief explanations of each option:
- Option A: $a/L=0.207$. This is the minimum value of $a/L$, and it minimizes the maximum bending moment.
- Option B: $a/L=0.307$. This is a larger value of $a/L$ than Option A, and it will 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube