[amp_mcq option1=”100″ option2=”1000″ option3=”5000″ option4=”at 15°C of the sewage of a town is 100 kg/day. If the 5 day B.O.D. per head at 15°C for standard sewage is 0.1 kg/day, the population equivalent is A. 100 B. 1000 C. 5000 D. 10000″ correct=”option2″]
The correct answer is B. 1000.
The population equivalent (PE) is a measure of the organic load of wastewater. It is calculated by dividing the five-day biochemical oxygen demand (BOD5) of the wastewater by the five-day BOD5 per capita of standard sewage. The five-day BOD5 is a measure of the amount of oxygen that is required to decompose the organic matter in the wastewater. The five-day BOD5 per capita of standard sewage is 0.1 kg/day.
In this case, the five-day BOD5 of the sewage of the town is 100 kg/day. Therefore, the population equivalent is 1000.
Option A is incorrect because the population equivalent is not equal to the five-day BOD5 of the sewage.
Option C is incorrect because the population equivalent is not equal to the five-day BOD5 per capita of standard sewage.
Option D is incorrect because the population equivalent is not equal to 10000.