Doubling the operating frequency of an inductive circuit: A. has no effect on the inductive reactance B. doubles the amount of inductive reactance C. multiplies the inductive reactance by 6.28 D. cuts the inductive reactance in half E. None of the above

The correct answer is: B. doubles the amount of inductive reactance.

Inductive reactance is the opposition to the flow of alternating current (AC) in a circuit that contains an inductor. It is measured in ohms (Ω) and is given by the formula:

$X_L = 2\pi f L$

where:

• $X_L$ is the inductive reactance in ohms (Ω)
• $f$ is the frequency of the AC current in hertz (Hz)
• $L$ is the inductance of the inductor in henries (H)

As you can see from the formula, inductive reactance is directly proportional to the frequency of the AC current. This means that doubling the frequency of the AC current will double the inductive reactance.

Option A is incorrect because doubling the frequency of the AC current will double the inductive reactance, not have no effect on it.

Option C is incorrect because doubling the frequency of the AC current will double the inductive reactance, not multiply it by 6.28.

Option D is incorrect because doubling the frequency of the AC current will double the inductive reactance, not cut it in half.

Option E is incorrect because doubling the