A circuit has a Norton current of 10 mA and a Norton resistance of 10 kW. What is the Thevenin circuit? A. 1000 V and a series resistance of 10 k Ohm B. 100 V and a parallel resistance of 10 k Ohm C. 100 V and a series resistance of 10 k Ohm D. 1000 V and a parallel resistance of 10 kOhm E. None of the above

[amp_mcq option1=”1000 V and a series resistance of 10 k Ohm” option2=”100 V and a parallel resistance of 10 k Ohm” option3=”100 V and a series resistance of 10 k Ohm” option4=”1000 V and a parallel resistance of 10 kOhm E. None of the above” correct=”option1″]

The correct answer is: E. None of the above

A Norton equivalent circuit is a two-terminal circuit that is equivalent to a real circuit as far as current is concerned. It consists of a current source in parallel with a resistor. The current source has a current equal to the short-circuit current of the real circuit, and the resistor has a resistance equal to the open-circuit resistance of the real circuit.

A Thevenin equivalent circuit is a two-terminal circuit that is equivalent to a real circuit as far as voltage is concerned. It consists of a voltage source in series with a resistor. The voltage source has a voltage equal to the open-circuit voltage of the real circuit, and the resistor has a resistance equal to the output resistance of the real circuit.

In this case, the Norton current is 10 mA and the Norton resistance is 10 kW. This means that the Norton equivalent circuit is a current source of 10 mA in parallel with a resistor of 10 kW.

The Thevenin equivalent circuit is found by calculating the open-circuit voltage and the output resistance of the real circuit. The open-circuit voltage is the voltage across the terminals of the real circuit when no load is connected. The output resistance is the resistance between the terminals of the real circuit when a constant current is drawn from it.

In this case, the open-circuit voltage is not given, so it cannot be calculated. Therefore, the Thevenin equivalent circuit cannot be found.