{"id":93453,"date":"2025-06-01T11:50:39","date_gmt":"2025-06-01T11:50:39","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=93453"},"modified":"2025-06-01T11:50:39","modified_gmt":"2025-06-01T11:50:39","slug":"the-decimal-value-of-4a9-2b-is","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/","title":{"rendered":"The decimal value of 4A9.2B is"},"content":{"rendered":"

The decimal value of 4A9.2B is<\/p>\n

[amp_mcq option1=”1193.1679″ option2=”119.31679″ option3=”11.931679″ option4=”1.1931679″ correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is A) 1193.1679. To convert a hexadecimal number (base 16) to a decimal number (base 10), we multiply each digit by 16 raised to the power of its position (starting from 0 for the digit before the decimal point, increasing to the left, and decreasing to the right). The hexadecimal digits are 0-9 and A-F (representing 10-15).
\nFor 4A9.2B:
\nInteger part: 4A9 = 4 * 16^2 + A (10) * 16^1 + 9 * 16^0
\n= 4 * 256 + 10 * 16 + 9 * 1
\n= 1024 + 160 + 9 = 1193
\nFractional part: .2B = 2 * 16^-1 + B (11) * 16^-2
\n= 2 \/ 16 + 11 \/ 256
\n= 1 \/ 8 + 11 \/ 256
\n= 32 \/ 256 + 11 \/ 256 = 43 \/ 256
\nConvert 43\/256 to decimal: 43 \u00f7 256 \u2248 0.16796875
\nCombining the integer and fractional parts: 1193 + 0.16796875 = 1193.16796875. This matches option A when rounded to four decimal places.
\n<\/section>\n
\nHexadecimal to decimal conversion involves summing the products of each digit’s value and 16 raised to the power corresponding to its position relative to the decimal point.
\n<\/section>\n
\nThe positions are assigned positive integers starting from 0 moving left from the decimal point (e.g., 16^0, 16^1, 16^2…) and negative integers moving right from the decimal point (e.g., 16^-1, 16^-2…).
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The decimal value of 4A9.2B is [amp_mcq option1=”1193.1679″ option2=”119.31679″ option3=”11.931679″ option4=”1.1931679″ correct=”option1″] This question was previously asked in UPSC CISF-AC-EXE – 2024 Download PDFAttempt Online The correct answer is A) 1193.1679. To convert a hexadecimal number (base 16) to a decimal number (base 10), we multiply each digit by 16 raised to the power of … <\/p>\n

Detailed SolutionThe decimal value of 4A9.2B is<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1103,1102],"class_list":["post-93453","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1103","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nThe decimal value of 4A9.2B is<\/title>\n<meta name=\"description\" content=\"The correct answer is A) 1193.1679. To convert a hexadecimal number (base 16) to a decimal number (base 10), we multiply each digit by 16 raised to the power of its position (starting from 0 for the digit before the decimal point, increasing to the left, and decreasing to the right). The hexadecimal digits are 0-9 and A-F (representing 10-15). For 4A9.2B: Integer part: 4A9 = 4 * 16^2 + A (10) * 16^1 + 9 * 16^0 = 4 * 256 + 10 * 16 + 9 * 1 = 1024 + 160 + 9 = 1193 Fractional part: .2B = 2 * 16^-1 + B (11) * 16^-2 = 2 \/ 16 + 11 \/ 256 = 1 \/ 8 + 11 \/ 256 = 32 \/ 256 + 11 \/ 256 = 43 \/ 256 Convert 43\/256 to decimal: 43 \u00f7 256 \u2248 0.16796875 Combining the integer and fractional parts: 1193 + 0.16796875 = 1193.16796875. This matches option A when rounded to four decimal places. Hexadecimal to decimal conversion involves summing the products of each digit's value and 16 raised to the power corresponding to its position relative to the decimal point.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The decimal value of 4A9.2B is\" \/>\n<meta property=\"og:description\" content=\"The correct answer is A) 1193.1679. To convert a hexadecimal number (base 16) to a decimal number (base 10), we multiply each digit by 16 raised to the power of its position (starting from 0 for the digit before the decimal point, increasing to the left, and decreasing to the right). The hexadecimal digits are 0-9 and A-F (representing 10-15). For 4A9.2B: Integer part: 4A9 = 4 * 16^2 + A (10) * 16^1 + 9 * 16^0 = 4 * 256 + 10 * 16 + 9 * 1 = 1024 + 160 + 9 = 1193 Fractional part: .2B = 2 * 16^-1 + B (11) * 16^-2 = 2 \/ 16 + 11 \/ 256 = 1 \/ 8 + 11 \/ 256 = 32 \/ 256 + 11 \/ 256 = 43 \/ 256 Convert 43\/256 to decimal: 43 \u00f7 256 \u2248 0.16796875 Combining the integer and fractional parts: 1193 + 0.16796875 = 1193.16796875. This matches option A when rounded to four decimal places. Hexadecimal to decimal conversion involves summing the products of each digit's value and 16 raised to the power corresponding to its position relative to the decimal point.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:50:39+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The decimal value of 4A9.2B is","description":"The correct answer is A) 1193.1679. To convert a hexadecimal number (base 16) to a decimal number (base 10), we multiply each digit by 16 raised to the power of its position (starting from 0 for the digit before the decimal point, increasing to the left, and decreasing to the right). The hexadecimal digits are 0-9 and A-F (representing 10-15). For 4A9.2B: Integer part: 4A9 = 4 * 16^2 + A (10) * 16^1 + 9 * 16^0 = 4 * 256 + 10 * 16 + 9 * 1 = 1024 + 160 + 9 = 1193 Fractional part: .2B = 2 * 16^-1 + B (11) * 16^-2 = 2 \/ 16 + 11 \/ 256 = 1 \/ 8 + 11 \/ 256 = 32 \/ 256 + 11 \/ 256 = 43 \/ 256 Convert 43\/256 to decimal: 43 \u00f7 256 \u2248 0.16796875 Combining the integer and fractional parts: 1193 + 0.16796875 = 1193.16796875. This matches option A when rounded to four decimal places. Hexadecimal to decimal conversion involves summing the products of each digit's value and 16 raised to the power corresponding to its position relative to the decimal point.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/","og_locale":"en_US","og_type":"article","og_title":"The decimal value of 4A9.2B is","og_description":"The correct answer is A) 1193.1679. To convert a hexadecimal number (base 16) to a decimal number (base 10), we multiply each digit by 16 raised to the power of its position (starting from 0 for the digit before the decimal point, increasing to the left, and decreasing to the right). The hexadecimal digits are 0-9 and A-F (representing 10-15). For 4A9.2B: Integer part: 4A9 = 4 * 16^2 + A (10) * 16^1 + 9 * 16^0 = 4 * 256 + 10 * 16 + 9 * 1 = 1024 + 160 + 9 = 1193 Fractional part: .2B = 2 * 16^-1 + B (11) * 16^-2 = 2 \/ 16 + 11 \/ 256 = 1 \/ 8 + 11 \/ 256 = 32 \/ 256 + 11 \/ 256 = 43 \/ 256 Convert 43\/256 to decimal: 43 \u00f7 256 \u2248 0.16796875 Combining the integer and fractional parts: 1193 + 0.16796875 = 1193.16796875. This matches option A when rounded to four decimal places. Hexadecimal to decimal conversion involves summing the products of each digit's value and 16 raised to the power corresponding to its position relative to the decimal point.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:50:39+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/","name":"The decimal value of 4A9.2B is","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:50:39+00:00","dateModified":"2025-06-01T11:50:39+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is A) 1193.1679. To convert a hexadecimal number (base 16) to a decimal number (base 10), we multiply each digit by 16 raised to the power of its position (starting from 0 for the digit before the decimal point, increasing to the left, and decreasing to the right). The hexadecimal digits are 0-9 and A-F (representing 10-15). For 4A9.2B: Integer part: 4A9 = 4 * 16^2 + A (10) * 16^1 + 9 * 16^0 = 4 * 256 + 10 * 16 + 9 * 1 = 1024 + 160 + 9 = 1193 Fractional part: .2B = 2 * 16^-1 + B (11) * 16^-2 = 2 \/ 16 + 11 \/ 256 = 1 \/ 8 + 11 \/ 256 = 32 \/ 256 + 11 \/ 256 = 43 \/ 256 Convert 43\/256 to decimal: 43 \u00f7 256 \u2248 0.16796875 Combining the integer and fractional parts: 1193 + 0.16796875 = 1193.16796875. This matches option A when rounded to four decimal places. Hexadecimal to decimal conversion involves summing the products of each digit's value and 16 raised to the power corresponding to its position relative to the decimal point.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-decimal-value-of-4a9-2b-is\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CISF-AC-EXE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cisf-ac-exe\/"},{"@type":"ListItem","position":3,"name":"The decimal value of 4A9.2B is"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/93453","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=93453"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/93453\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=93453"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=93453"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=93453"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}