{"id":93421,"date":"2025-06-01T11:50:13","date_gmt":"2025-06-01T11:50:13","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=93421"},"modified":"2025-06-01T11:50:13","modified_gmt":"2025-06-01T11:50:13","slug":"a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh\/","title":{"rendered":"A train with a length of 335 m is travelling at a speed of 90 km\/h. Wh"},"content":{"rendered":"

A train with a length of 335 m is travelling at a speed of 90 km\/h. What is the time taken by the train to pass a 290 m long platform?<\/p>\n

[amp_mcq option1=”25 s” option2=”23 s” option3=”20 s” option4=”30 s” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is 25 seconds.
\n<\/section>\n
\nTo pass a platform, a train must cover a distance equal to its own length plus the length of the platform.
\nTotal distance to be covered = Length of train + Length of platform.
\nTotal distance = 335 m + 290 m = 625 m.
\nThe speed of the train is given in km\/h, so we need to convert it to m\/s to be consistent with the distance unit (meters) and time unit (seconds).
\nSpeed = 90 km\/h.
\nTo convert km\/h to m\/s, multiply by the factor (1000 m \/ 3600 s) = 5\/18.
\nSpeed in m\/s = 90 * (5\/18) m\/s = (90\/18) * 5 m\/s = 5 * 5 m\/s = 25 m\/s.
\nThe time taken is calculated using the formula: Time = Distance \/ Speed.
\nTime = 625 m \/ 25 m\/s.
\nTime = 25 seconds.
\n<\/section>\n
\nWhen a train crosses a stationary object with negligible length (like a pole or a man), the distance covered is just the length of the train. When it crosses an object with considerable length (like a bridge or a platform), the distance is the sum of the train’s length and the object’s length. The conversion factor 5\/18 comes from $1 \\text{ km} = 1000 \\text{ m}$ and $1 \\text{ hour} = 3600 \\text{ seconds}$, so $1 \\text{ km\/h} = \\frac{1000}{3600} \\text{ m\/s} = \\frac{5}{18} \\text{ m\/s}$.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A train with a length of 335 m is travelling at a speed of 90 km\/h. What is the time taken by the train to pass a 290 m long platform? [amp_mcq option1=”25 s” option2=”23 s” option3=”20 s” option4=”30 s” correct=”option1″] This question was previously asked in UPSC CISF-AC-EXE – 2024 Download PDFAttempt Online The … <\/p>\n

Detailed SolutionA train with a length of 335 m is travelling at a speed of 90 km\/h. Wh<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1103,1102],"class_list":["post-93421","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1103","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nA train with a length of 335 m is travelling at a speed of 90 km\/h. Wh<\/title>\n<meta name=\"description\" content=\"The correct answer is 25 seconds. To pass a platform, a train must cover a distance equal to its own length plus the length of the platform. Total distance to be covered = Length of train + Length of platform. Total distance = 335 m + 290 m = 625 m. The speed of the train is given in km\/h, so we need to convert it to m\/s to be consistent with the distance unit (meters) and time unit (seconds). Speed = 90 km\/h. To convert km\/h to m\/s, multiply by the factor (1000 m \/ 3600 s) = 5\/18. Speed in m\/s = 90 * (5\/18) m\/s = (90\/18) * 5 m\/s = 5 * 5 m\/s = 25 m\/s. The time taken is calculated using the formula: Time = Distance \/ Speed. Time = 625 m \/ 25 m\/s. Time = 25 seconds.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A train with a length of 335 m is travelling at a speed of 90 km\/h. Wh\" \/>\n<meta property=\"og:description\" content=\"The correct answer is 25 seconds. To pass a platform, a train must cover a distance equal to its own length plus the length of the platform. Total distance to be covered = Length of train + Length of platform. Total distance = 335 m + 290 m = 625 m. The speed of the train is given in km\/h, so we need to convert it to m\/s to be consistent with the distance unit (meters) and time unit (seconds). Speed = 90 km\/h. To convert km\/h to m\/s, multiply by the factor (1000 m \/ 3600 s) = 5\/18. Speed in m\/s = 90 * (5\/18) m\/s = (90\/18) * 5 m\/s = 5 * 5 m\/s = 25 m\/s. The time taken is calculated using the formula: Time = Distance \/ Speed. Time = 625 m \/ 25 m\/s. Time = 25 seconds.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:50:13+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A train with a length of 335 m is travelling at a speed of 90 km\/h. Wh","description":"The correct answer is 25 seconds. To pass a platform, a train must cover a distance equal to its own length plus the length of the platform. Total distance to be covered = Length of train + Length of platform. Total distance = 335 m + 290 m = 625 m. The speed of the train is given in km\/h, so we need to convert it to m\/s to be consistent with the distance unit (meters) and time unit (seconds). Speed = 90 km\/h. To convert km\/h to m\/s, multiply by the factor (1000 m \/ 3600 s) = 5\/18. Speed in m\/s = 90 * (5\/18) m\/s = (90\/18) * 5 m\/s = 5 * 5 m\/s = 25 m\/s. The time taken is calculated using the formula: Time = Distance \/ Speed. Time = 625 m \/ 25 m\/s. Time = 25 seconds.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh\/","og_locale":"en_US","og_type":"article","og_title":"A train with a length of 335 m is travelling at a speed of 90 km\/h. Wh","og_description":"The correct answer is 25 seconds. To pass a platform, a train must cover a distance equal to its own length plus the length of the platform. Total distance to be covered = Length of train + Length of platform. Total distance = 335 m + 290 m = 625 m. The speed of the train is given in km\/h, so we need to convert it to m\/s to be consistent with the distance unit (meters) and time unit (seconds). Speed = 90 km\/h. To convert km\/h to m\/s, multiply by the factor (1000 m \/ 3600 s) = 5\/18. Speed in m\/s = 90 * (5\/18) m\/s = (90\/18) * 5 m\/s = 5 * 5 m\/s = 25 m\/s. The time taken is calculated using the formula: Time = Distance \/ Speed. Time = 625 m \/ 25 m\/s. Time = 25 seconds.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:50:13+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-train-with-a-length-of-335-m-is-travelling-at-a-speed-of-90-km-h-wh\/","name":"A train with a length of 335 m is travelling at a speed of 90 km\/h. Wh","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:50:13+00:00","dateModified":"2025-06-01T11:50:13+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is 25 seconds. To pass a platform, a train must cover a distance equal to its own length plus the length of the platform. Total distance to be covered = Length of train + Length of platform. Total distance = 335 m + 290 m = 625 m. The speed of the train is given in km\/h, so we need to convert it to m\/s to be consistent with the distance unit (meters) and time unit (seconds). Speed = 90 km\/h. To convert km\/h to m\/s, multiply by the factor (1000 m \/ 3600 s) = 5\/18. Speed in m\/s = 90 * (5\/18) m\/s = (90\/18) * 5 m\/s = 5 * 5 m\/s = 25 m\/s. The time taken is calculated using the formula: Time = Distance \/ Speed. Time = 625 m \/ 25 m\/s. 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