{"id":93419,"date":"2025-06-01T11:50:11","date_gmt":"2025-06-01T11:50:11","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=93419"},"modified":"2025-06-01T11:50:11","modified_gmt":"2025-06-01T11:50:11","slug":"an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/","title":{"rendered":"An amount is adequate to pay salaries to R for 20 days or to S for 30"},"content":{"rendered":"

An amount is adequate to pay salaries to R for 20 days or to S for 30 days. For how many days is the money enough to cover salaries of both of them together?<\/p>\n

[amp_mcq option1=”12 days” option2=”15 days” option3=”11 days” option4=”20 days” correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is 12 days.
\n<\/section>\n
\nThis is a work and time problem. We can determine the efficiency (or daily work rate) of R and S based on the number of days they take to complete the work (pay salaries).
\nLet the total amount of money (representing the total work) be M.
\nR can be paid for 20 days with M. So, R’s daily salary (work rate) = M\/20 per day.
\nS can be paid for 30 days with M. So, S’s daily salary (work rate) = M\/30 per day.
\nIf both R and S are paid together, their combined daily salary is R’s daily salary + S’s daily salary = M\/20 + M\/30.
\nTo find how many days (let’s call this D) the money M will last for both, we set M equal to the combined daily salary multiplied by D:
\nM = (M\/20 + M\/30) * D
\nDivide both sides by M (assuming M > 0):
\n1 = (1\/20 + 1\/30) * D
\nFind a common denominator for 1\/20 and 1\/30, which is 60:
\n1\/20 + 1\/30 = 3\/60 + 2\/60 = 5\/60 = 1\/12.
\nSo, 1 = (1\/12) * D
\nMultiply by 12 to find D:
\nD = 12 days.
\n<\/section>\n
\nThis problem can also be viewed as calculating the time taken by two individuals to complete a task together, given the time each takes individually. If R takes ‘a’ days and S takes ‘b’ days, the time taken together is given by the formula $\\frac{1}{\\frac{1}{a} + \\frac{1}{b}} = \\frac{ab}{a+b}$. In this case, a=20 and b=30. Time together = $\\frac{20 \\times 30}{20 + 30} = \\frac{600}{50} = 12$ days.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

An amount is adequate to pay salaries to R for 20 days or to S for 30 days. For how many days is the money enough to cover salaries of both of them together? [amp_mcq option1=”12 days” option2=”15 days” option3=”11 days” option4=”20 days” correct=”option1″] This question was previously asked in UPSC CISF-AC-EXE – 2024 Download … <\/p>\n

Detailed SolutionAn amount is adequate to pay salaries to R for 20 days or to S for 30<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1103,1102],"class_list":["post-93419","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1103","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nAn amount is adequate to pay salaries to R for 20 days or to S for 30<\/title>\n<meta name=\"description\" content=\"The correct answer is 12 days. This is a work and time problem. We can determine the efficiency (or daily work rate) of R and S based on the number of days they take to complete the work (pay salaries). Let the total amount of money (representing the total work) be M. R can be paid for 20 days with M. So, R's daily salary (work rate) = M\/20 per day. S can be paid for 30 days with M. So, S's daily salary (work rate) = M\/30 per day. If both R and S are paid together, their combined daily salary is R's daily salary + S's daily salary = M\/20 + M\/30. To find how many days (let's call this D) the money M will last for both, we set M equal to the combined daily salary multiplied by D: M = (M\/20 + M\/30) * D Divide both sides by M (assuming M > 0): 1 = (1\/20 + 1\/30) * D Find a common denominator for 1\/20 and 1\/30, which is 60: 1\/20 + 1\/30 = 3\/60 + 2\/60 = 5\/60 = 1\/12. So, 1 = (1\/12) * D Multiply by 12 to find D: D = 12 days.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"An amount is adequate to pay salaries to R for 20 days or to S for 30\" \/>\n<meta property=\"og:description\" content=\"The correct answer is 12 days. This is a work and time problem. We can determine the efficiency (or daily work rate) of R and S based on the number of days they take to complete the work (pay salaries). Let the total amount of money (representing the total work) be M. R can be paid for 20 days with M. So, R's daily salary (work rate) = M\/20 per day. S can be paid for 30 days with M. So, S's daily salary (work rate) = M\/30 per day. If both R and S are paid together, their combined daily salary is R's daily salary + S's daily salary = M\/20 + M\/30. To find how many days (let's call this D) the money M will last for both, we set M equal to the combined daily salary multiplied by D: M = (M\/20 + M\/30) * D Divide both sides by M (assuming M > 0): 1 = (1\/20 + 1\/30) * D Find a common denominator for 1\/20 and 1\/30, which is 60: 1\/20 + 1\/30 = 3\/60 + 2\/60 = 5\/60 = 1\/12. So, 1 = (1\/12) * D Multiply by 12 to find D: D = 12 days.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:50:11+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"An amount is adequate to pay salaries to R for 20 days or to S for 30","description":"The correct answer is 12 days. This is a work and time problem. We can determine the efficiency (or daily work rate) of R and S based on the number of days they take to complete the work (pay salaries). Let the total amount of money (representing the total work) be M. R can be paid for 20 days with M. So, R's daily salary (work rate) = M\/20 per day. S can be paid for 30 days with M. So, S's daily salary (work rate) = M\/30 per day. If both R and S are paid together, their combined daily salary is R's daily salary + S's daily salary = M\/20 + M\/30. To find how many days (let's call this D) the money M will last for both, we set M equal to the combined daily salary multiplied by D: M = (M\/20 + M\/30) * D Divide both sides by M (assuming M > 0): 1 = (1\/20 + 1\/30) * D Find a common denominator for 1\/20 and 1\/30, which is 60: 1\/20 + 1\/30 = 3\/60 + 2\/60 = 5\/60 = 1\/12. So, 1 = (1\/12) * D Multiply by 12 to find D: D = 12 days.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/","og_locale":"en_US","og_type":"article","og_title":"An amount is adequate to pay salaries to R for 20 days or to S for 30","og_description":"The correct answer is 12 days. This is a work and time problem. We can determine the efficiency (or daily work rate) of R and S based on the number of days they take to complete the work (pay salaries). Let the total amount of money (representing the total work) be M. R can be paid for 20 days with M. So, R's daily salary (work rate) = M\/20 per day. S can be paid for 30 days with M. So, S's daily salary (work rate) = M\/30 per day. If both R and S are paid together, their combined daily salary is R's daily salary + S's daily salary = M\/20 + M\/30. To find how many days (let's call this D) the money M will last for both, we set M equal to the combined daily salary multiplied by D: M = (M\/20 + M\/30) * D Divide both sides by M (assuming M > 0): 1 = (1\/20 + 1\/30) * D Find a common denominator for 1\/20 and 1\/30, which is 60: 1\/20 + 1\/30 = 3\/60 + 2\/60 = 5\/60 = 1\/12. So, 1 = (1\/12) * D Multiply by 12 to find D: D = 12 days.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:50:11+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/","url":"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/","name":"An amount is adequate to pay salaries to R for 20 days or to S for 30","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:50:11+00:00","dateModified":"2025-06-01T11:50:11+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is 12 days. This is a work and time problem. We can determine the efficiency (or daily work rate) of R and S based on the number of days they take to complete the work (pay salaries). Let the total amount of money (representing the total work) be M. R can be paid for 20 days with M. So, R's daily salary (work rate) = M\/20 per day. S can be paid for 30 days with M. So, S's daily salary (work rate) = M\/30 per day. If both R and S are paid together, their combined daily salary is R's daily salary + S's daily salary = M\/20 + M\/30. To find how many days (let's call this D) the money M will last for both, we set M equal to the combined daily salary multiplied by D: M = (M\/20 + M\/30) * D Divide both sides by M (assuming M > 0): 1 = (1\/20 + 1\/30) * D Find a common denominator for 1\/20 and 1\/30, which is 60: 1\/20 + 1\/30 = 3\/60 + 2\/60 = 5\/60 = 1\/12. So, 1 = (1\/12) * D Multiply by 12 to find D: D = 12 days.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/an-amount-is-adequate-to-pay-salaries-to-r-for-20-days-or-to-s-for-30\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CISF-AC-EXE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cisf-ac-exe\/"},{"@type":"ListItem","position":3,"name":"An amount is adequate to pay salaries to R for 20 days or to S for 30"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/93419","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=93419"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/93419\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=93419"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=93419"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=93419"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}