{"id":93282,"date":"2025-06-01T11:46:29","date_gmt":"2025-06-01T11:46:29","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=93282"},"modified":"2025-06-01T11:46:29","modified_gmt":"2025-06-01T11:46:29","slug":"a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/","title":{"rendered":"A man takes a loan at 5% simple interest for a period of 2 years. He i"},"content":{"rendered":"<p>A man takes a loan at 5% simple interest for a period of 2 years. He immediately gives this money on loan at 5% compound interest for 2 years. What is the amount of loan he has taken if he makes a profit of \u20b9 2,100 ?<\/p>\n<p>[amp_mcq option1=&#8221;\u20b9 8,00,000&#8243; option2=&#8221;\u20b9 4,20,000&#8243; option3=&#8221;\u20b9 1,00,000&#8243; option4=&#8221;\u20b9 8,40,000&#8243; correct=&#8221;option4&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CISF-AC-EXE &#8211; 2023<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-cisf-ac-exe-2023.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-cisf-ac-exe-2023\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nLet the principal amount be P. The simple interest (SI) paid by the man for 2 years at 5% is SI = (P * 5 * 2) \/ 100 = 0.10P. The compound interest (CI) received by the man for 2 years at 5% is CI = P(1 + 5\/100)^2 &#8211; P = P(1.05)^2 &#8211; P = P(1.1025) &#8211; P = 0.1025P. The man&#8217;s profit is the difference between the CI received and the SI paid: Profit = CI &#8211; SI = 0.1025P &#8211; 0.10P = 0.0025P. Given the profit is \u20b9 2,100, we have 0.0025P = 2100. Solving for P: P = 2100 \/ 0.0025 = 2100 \/ (1\/400) = 2100 * 400 = \u20b9 8,40,000.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\n&#8211; Simple Interest formula: SI = PRT\/100.<br \/>\n&#8211; Compound Interest formula: CI = Amount &#8211; Principal = P(1 + R\/100)^T &#8211; P.<br \/>\n&#8211; The profit in this scenario is the difference between the interest earned (CI) and the interest paid (SI).<br \/>\n&#8211; Set up an equation with the profit difference equal to the given profit amount and solve for the principal P.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nThis question tests the understanding of simple and compound interest calculations and how to find the profit earned by an intermediary who borrows at one rate\/type and lends at another rate\/type. The difference in interest earned versus interest paid constitutes the profit.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>A man takes a loan at 5% simple interest for a period of 2 years. He immediately gives this money on loan at 5% compound interest for 2 years. What is the amount of loan he has taken if he makes a profit of \u20b9 2,100 ? [amp_mcq option1=&#8221;\u20b9 8,00,000&#8243; option2=&#8221;\u20b9 4,20,000&#8243; option3=&#8221;\u20b9 1,00,000&#8243; option4=&#8221;\u20b9 &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"A man takes a loan at 5% simple interest for a period of 2 years. He i\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/#more-93282\">Detailed Solution<span class=\"screen-reader-text\">A man takes a loan at 5% simple interest for a period of 2 years. He i<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1105,1102],"class_list":["post-93282","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1105","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A man takes a loan at 5% simple interest for a period of 2 years. He i<\/title>\n<meta name=\"description\" content=\"Let the principal amount be P. The simple interest (SI) paid by the man for 2 years at 5% is SI = (P * 5 * 2) \/ 100 = 0.10P. The compound interest (CI) received by the man for 2 years at 5% is CI = P(1 + 5\/100)^2 - P = P(1.05)^2 - P = P(1.1025) - P = 0.1025P. The man&#039;s profit is the difference between the CI received and the SI paid: Profit = CI - SI = 0.1025P - 0.10P = 0.0025P. Given the profit is \u20b9 2,100, we have 0.0025P = 2100. Solving for P: P = 2100 \/ 0.0025 = 2100 \/ (1\/400) = 2100 * 400 = \u20b9 8,40,000. - Simple Interest formula: SI = PRT\/100. - Compound Interest formula: CI = Amount - Principal = P(1 + R\/100)^T - P. - The profit in this scenario is the difference between the interest earned (CI) and the interest paid (SI). - Set up an equation with the profit difference equal to the given profit amount and solve for the principal P.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A man takes a loan at 5% simple interest for a period of 2 years. He i\" \/>\n<meta property=\"og:description\" content=\"Let the principal amount be P. The simple interest (SI) paid by the man for 2 years at 5% is SI = (P * 5 * 2) \/ 100 = 0.10P. The compound interest (CI) received by the man for 2 years at 5% is CI = P(1 + 5\/100)^2 - P = P(1.05)^2 - P = P(1.1025) - P = 0.1025P. The man&#039;s profit is the difference between the CI received and the SI paid: Profit = CI - SI = 0.1025P - 0.10P = 0.0025P. Given the profit is \u20b9 2,100, we have 0.0025P = 2100. Solving for P: P = 2100 \/ 0.0025 = 2100 \/ (1\/400) = 2100 * 400 = \u20b9 8,40,000. - Simple Interest formula: SI = PRT\/100. - Compound Interest formula: CI = Amount - Principal = P(1 + R\/100)^T - P. - The profit in this scenario is the difference between the interest earned (CI) and the interest paid (SI). - Set up an equation with the profit difference equal to the given profit amount and solve for the principal P.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:46:29+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A man takes a loan at 5% simple interest for a period of 2 years. He i","description":"Let the principal amount be P. The simple interest (SI) paid by the man for 2 years at 5% is SI = (P * 5 * 2) \/ 100 = 0.10P. The compound interest (CI) received by the man for 2 years at 5% is CI = P(1 + 5\/100)^2 - P = P(1.05)^2 - P = P(1.1025) - P = 0.1025P. The man's profit is the difference between the CI received and the SI paid: Profit = CI - SI = 0.1025P - 0.10P = 0.0025P. Given the profit is \u20b9 2,100, we have 0.0025P = 2100. Solving for P: P = 2100 \/ 0.0025 = 2100 \/ (1\/400) = 2100 * 400 = \u20b9 8,40,000. - Simple Interest formula: SI = PRT\/100. - Compound Interest formula: CI = Amount - Principal = P(1 + R\/100)^T - P. - The profit in this scenario is the difference between the interest earned (CI) and the interest paid (SI). - Set up an equation with the profit difference equal to the given profit amount and solve for the principal P.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/","og_locale":"en_US","og_type":"article","og_title":"A man takes a loan at 5% simple interest for a period of 2 years. He i","og_description":"Let the principal amount be P. The simple interest (SI) paid by the man for 2 years at 5% is SI = (P * 5 * 2) \/ 100 = 0.10P. The compound interest (CI) received by the man for 2 years at 5% is CI = P(1 + 5\/100)^2 - P = P(1.05)^2 - P = P(1.1025) - P = 0.1025P. The man's profit is the difference between the CI received and the SI paid: Profit = CI - SI = 0.1025P - 0.10P = 0.0025P. Given the profit is \u20b9 2,100, we have 0.0025P = 2100. Solving for P: P = 2100 \/ 0.0025 = 2100 \/ (1\/400) = 2100 * 400 = \u20b9 8,40,000. - Simple Interest formula: SI = PRT\/100. - Compound Interest formula: CI = Amount - Principal = P(1 + R\/100)^T - P. - The profit in this scenario is the difference between the interest earned (CI) and the interest paid (SI). - Set up an equation with the profit difference equal to the given profit amount and solve for the principal P.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:46:29+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/","name":"A man takes a loan at 5% simple interest for a period of 2 years. He i","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:46:29+00:00","dateModified":"2025-06-01T11:46:29+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Let the principal amount be P. The simple interest (SI) paid by the man for 2 years at 5% is SI = (P * 5 * 2) \/ 100 = 0.10P. The compound interest (CI) received by the man for 2 years at 5% is CI = P(1 + 5\/100)^2 - P = P(1.05)^2 - P = P(1.1025) - P = 0.1025P. The man's profit is the difference between the CI received and the SI paid: Profit = CI - SI = 0.1025P - 0.10P = 0.0025P. Given the profit is \u20b9 2,100, we have 0.0025P = 2100. Solving for P: P = 2100 \/ 0.0025 = 2100 \/ (1\/400) = 2100 * 400 = \u20b9 8,40,000. - Simple Interest formula: SI = PRT\/100. - Compound Interest formula: CI = Amount - Principal = P(1 + R\/100)^T - P. - The profit in this scenario is the difference between the interest earned (CI) and the interest paid (SI). - Set up an equation with the profit difference equal to the given profit amount and solve for the principal P.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-man-takes-a-loan-at-5-simple-interest-for-a-period-of-2-years-he-i\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CISF-AC-EXE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cisf-ac-exe\/"},{"@type":"ListItem","position":3,"name":"A man takes a loan at 5% simple interest for a period of 2 years. He i"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/93282","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=93282"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/93282\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=93282"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=93282"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=93282"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}