{"id":93244,"date":"2025-06-01T11:45:46","date_gmt":"2025-06-01T11:45:46","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=93244"},"modified":"2025-06-01T11:45:46","modified_gmt":"2025-06-01T11:45:46","slug":"a-person-of-mass-50-kg-is-standing-in-a-lift-if-the-lift-moves-in-upw","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-person-of-mass-50-kg-is-standing-in-a-lift-if-the-lift-moves-in-upw\/","title":{"rendered":"A person of mass 50 kg is standing in a lift. If the lift moves in upw"},"content":{"rendered":"

A person of mass 50 kg is standing in a lift. If the lift moves in upward direction with an acceleration of 1 m\/s\u00b2, then the weight of the person will be closest to :<\/p>\n

[amp_mcq option1=”490 N” option2=”540 N” option3=”440 N” option4=”50 N” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is B.
\n<\/section>\n
\nWhen a person is in a lift accelerating upwards, the apparent weight of the person is greater than their true weight. The forces acting on the person are the gravitational force (mg) downwards and the normal force (N) exerted by the lift floor upwards. According to Newton’s second law, the net force (N – mg) is equal to mass times acceleration (ma). Thus, the normal force N = mg + ma = m(g + a). This normal force is the apparent weight.
\n<\/section>\n
\nGiven mass m = 50 kg and upward acceleration a = 1 m\/s\u00b2. Using the standard value of g \u2248 9.8 m\/s\u00b2: Apparent weight N = 50 kg * (9.8 m\/s\u00b2 + 1 m\/s\u00b2) = 50 kg * 10.8 m\/s\u00b2 = 540 N. If we use g \u2248 10 m\/s\u00b2, N = 50 kg * (10 m\/s\u00b2 + 1 m\/s\u00b2) = 50 kg * 11 m\/s\u00b2 = 550 N. The option closest to 540 N (or 550 N) is 540 N.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A person of mass 50 kg is standing in a lift. If the lift moves in upward direction with an acceleration of 1 m\/s\u00b2, then the weight of the person will be closest to : [amp_mcq option1=”490 N” option2=”540 N” option3=”440 N” option4=”50 N” correct=”option2″] This question was previously asked in UPSC CISF-AC-EXE – 2023 … <\/p>\n

Detailed SolutionA person of mass 50 kg is standing in a lift. If the lift moves in upw<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1105,1129,1128],"class_list":["post-93244","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1105","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nA person of mass 50 kg is standing in a lift. If the lift moves in upw<\/title>\n<meta name=\"description\" content=\"The correct answer is B. When a person is in a lift accelerating upwards, the apparent weight of the person is greater than their true weight. The forces acting on the person are the gravitational force (mg) downwards and the normal force (N) exerted by the lift floor upwards. According to Newton's second law, the net force (N - mg) is equal to mass times acceleration (ma). Thus, the normal force N = mg + ma = m(g + a). This normal force is the apparent weight.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-person-of-mass-50-kg-is-standing-in-a-lift-if-the-lift-moves-in-upw\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A person of mass 50 kg is standing in a lift. If the lift moves in upw\" \/>\n<meta property=\"og:description\" content=\"The correct answer is B. When a person is in a lift accelerating upwards, the apparent weight of the person is greater than their true weight. The forces acting on the person are the gravitational force (mg) downwards and the normal force (N) exerted by the lift floor upwards. According to Newton's second law, the net force (N - mg) is equal to mass times acceleration (ma). Thus, the normal force N = mg + ma = m(g + a). This normal force is the apparent weight.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-person-of-mass-50-kg-is-standing-in-a-lift-if-the-lift-moves-in-upw\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:45:46+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A person of mass 50 kg is standing in a lift. 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