{"id":93090,"date":"2025-06-01T11:40:49","date_gmt":"2025-06-01T11:40:49","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=93090"},"modified":"2025-06-01T11:40:49","modified_gmt":"2025-06-01T11:40:49","slug":"a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra\/","title":{"rendered":"A mother gives pocket money to her three children A, B and C in the ra"},"content":{"rendered":"

A mother gives pocket money to her three children A, B and C in the ratio 3 : 4 : 5 respectively. Then the father gives \u20b9 40 to each child. As a result, the pocket money of A, B and C now has the ratio 5 : 6 : 7 respectively. How much does C get from her mother ?<\/p>\n

[amp_mcq option1=”\u20b9 80″ option2=”\u20b9 100″ option3=”\u20b9 120″ option4=”\u20b9 60″ correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2022<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is B) \u20b9100.
\nLet the initial pocket money from the mother for children A, B, and C be 3x, 4x, and 5x respectively.
\nAfter the father gives \u20b940 to each child, their pocket money becomes:
\nA: 3x + 40
\nB: 4x + 40
\nC: 5x + 40
\nThe new ratio of their pocket money is 5:6:7.
\nWe can set up a proportion using any two children’s new amounts and their corresponding ratio:
\n(3x + 40) \/ (4x + 40) = 5 \/ 6
\nCross-multiply:
\n6(3x + 40) = 5(4x + 40)
\n18x + 240 = 20x + 200
\n240 – 200 = 20x – 18x
\n40 = 2x
\nx = 20
\nThe question asks for how much C gets from her mother, which is the initial amount for C.
\nInitial amount for C = 5x = 5 * 20 = \u20b9100.
\n<\/section>\n
\n– Represent the initial amounts using a common variable based on the ratio.
\n– Add the fixed amount received from the father to each child’s money.
\n– Use the new ratio to form an equation and solve for the variable.
\n– Calculate the initial amount for C using the value of the variable.
\n<\/section>\n
\nWe can verify the new amounts and their ratio:
\nA: 3(20) + 40 = 60 + 40 = 100
\nB: 4(20) + 40 = 80 + 40 = 120
\nC: 5(20) + 40 = 100 + 40 = 140
\nThe new ratio is 100:120:140, which simplifies to 10:12:14, and further to 5:6:7, confirming the value of x is correct.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A mother gives pocket money to her three children A, B and C in the ratio 3 : 4 : 5 respectively. Then the father gives \u20b9 40 to each child. As a result, the pocket money of A, B and C now has the ratio 5 : 6 : 7 respectively. How much does … <\/p>\n

Detailed SolutionA mother gives pocket money to her three children A, B and C in the ra<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1108,1102],"class_list":["post-93090","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1108","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nA mother gives pocket money to her three children A, B and C in the ra<\/title>\n<meta name=\"description\" content=\"The correct answer is B) \u20b9100. Let the initial pocket money from the mother for children A, B, and C be 3x, 4x, and 5x respectively. After the father gives \u20b940 to each child, their pocket money becomes: A: 3x + 40 B: 4x + 40 C: 5x + 40 The new ratio of their pocket money is 5:6:7. We can set up a proportion using any two children's new amounts and their corresponding ratio: (3x + 40) \/ (4x + 40) = 5 \/ 6 Cross-multiply: 6(3x + 40) = 5(4x + 40) 18x + 240 = 20x + 200 240 - 200 = 20x - 18x 40 = 2x x = 20 The question asks for how much C gets from her mother, which is the initial amount for C. Initial amount for C = 5x = 5 * 20 = \u20b9100. - Represent the initial amounts using a common variable based on the ratio. - Add the fixed amount received from the father to each child's money. - Use the new ratio to form an equation and solve for the variable. - Calculate the initial amount for C using the value of the variable.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A mother gives pocket money to her three children A, B and C in the ra\" \/>\n<meta property=\"og:description\" content=\"The correct answer is B) \u20b9100. Let the initial pocket money from the mother for children A, B, and C be 3x, 4x, and 5x respectively. After the father gives \u20b940 to each child, their pocket money becomes: A: 3x + 40 B: 4x + 40 C: 5x + 40 The new ratio of their pocket money is 5:6:7. We can set up a proportion using any two children's new amounts and their corresponding ratio: (3x + 40) \/ (4x + 40) = 5 \/ 6 Cross-multiply: 6(3x + 40) = 5(4x + 40) 18x + 240 = 20x + 200 240 - 200 = 20x - 18x 40 = 2x x = 20 The question asks for how much C gets from her mother, which is the initial amount for C. Initial amount for C = 5x = 5 * 20 = \u20b9100. - Represent the initial amounts using a common variable based on the ratio. - Add the fixed amount received from the father to each child's money. - Use the new ratio to form an equation and solve for the variable. - Calculate the initial amount for C using the value of the variable.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:40:49+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A mother gives pocket money to her three children A, B and C in the ra","description":"The correct answer is B) \u20b9100. Let the initial pocket money from the mother for children A, B, and C be 3x, 4x, and 5x respectively. After the father gives \u20b940 to each child, their pocket money becomes: A: 3x + 40 B: 4x + 40 C: 5x + 40 The new ratio of their pocket money is 5:6:7. We can set up a proportion using any two children's new amounts and their corresponding ratio: (3x + 40) \/ (4x + 40) = 5 \/ 6 Cross-multiply: 6(3x + 40) = 5(4x + 40) 18x + 240 = 20x + 200 240 - 200 = 20x - 18x 40 = 2x x = 20 The question asks for how much C gets from her mother, which is the initial amount for C. Initial amount for C = 5x = 5 * 20 = \u20b9100. - Represent the initial amounts using a common variable based on the ratio. - Add the fixed amount received from the father to each child's money. - Use the new ratio to form an equation and solve for the variable. - Calculate the initial amount for C using the value of the variable.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra\/","og_locale":"en_US","og_type":"article","og_title":"A mother gives pocket money to her three children A, B and C in the ra","og_description":"The correct answer is B) \u20b9100. Let the initial pocket money from the mother for children A, B, and C be 3x, 4x, and 5x respectively. After the father gives \u20b940 to each child, their pocket money becomes: A: 3x + 40 B: 4x + 40 C: 5x + 40 The new ratio of their pocket money is 5:6:7. We can set up a proportion using any two children's new amounts and their corresponding ratio: (3x + 40) \/ (4x + 40) = 5 \/ 6 Cross-multiply: 6(3x + 40) = 5(4x + 40) 18x + 240 = 20x + 200 240 - 200 = 20x - 18x 40 = 2x x = 20 The question asks for how much C gets from her mother, which is the initial amount for C. Initial amount for C = 5x = 5 * 20 = \u20b9100. - Represent the initial amounts using a common variable based on the ratio. - Add the fixed amount received from the father to each child's money. - Use the new ratio to form an equation and solve for the variable. - Calculate the initial amount for C using the value of the variable.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:40:49+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-mother-gives-pocket-money-to-her-three-children-a-b-and-c-in-the-ra\/","name":"A mother gives pocket money to her three children A, B and C in the ra","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:40:49+00:00","dateModified":"2025-06-01T11:40:49+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is B) \u20b9100. Let the initial pocket money from the mother for children A, B, and C be 3x, 4x, and 5x respectively. After the father gives \u20b940 to each child, their pocket money becomes: A: 3x + 40 B: 4x + 40 C: 5x + 40 The new ratio of their pocket money is 5:6:7. We can set up a proportion using any two children's new amounts and their corresponding ratio: (3x + 40) \/ (4x + 40) = 5 \/ 6 Cross-multiply: 6(3x + 40) = 5(4x + 40) 18x + 240 = 20x + 200 240 - 200 = 20x - 18x 40 = 2x x = 20 The question asks for how much C gets from her mother, which is the initial amount for C. 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