{"id":92800,"date":"2025-06-01T11:32:50","date_gmt":"2025-06-01T11:32:50","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=92800"},"modified":"2025-06-01T11:32:50","modified_gmt":"2025-06-01T11:32:50","slug":"how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o\/","title":{"rendered":"How many moles of water would be produced by the complete combustion o"},"content":{"rendered":"

How many moles of water would be produced by the complete combustion of one mole of natural gas, CH\u2084, in excess of oxygen ?<\/p>\n

[amp_mcq option1=”1″ option2=”2″ option3=”3″ option4=”4″ correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2020<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe complete combustion of natural gas, which is primarily methane (CH\u2084), in excess oxygen is represented by the balanced chemical equation:
\nCH\u2084(g) + 2O\u2082(g) \u2192 CO\u2082(g) + 2H\u2082O(g or l)
\nThe coefficients in the balanced equation represent the relative number of moles of reactants and products. According to the equation, one mole of methane (CH\u2084) reacts with two moles of oxygen (O\u2082) to produce one mole of carbon dioxide (CO\u2082) and two moles of water (H\u2082O).
\n<\/section>\n
\nThe stoichiometry of a balanced chemical equation gives the mole ratios of reactants and products. For the combustion of methane, 1 mole of CH\u2084 produces 2 moles of H\u2082O.
\n<\/section>\n
\nCombustion is a rapid reaction between a substance with an oxidant, usually oxygen, to produce heat and light. Complete combustion occurs when there is sufficient oxygen, yielding carbon dioxide and water as products for hydrocarbons like methane. Incomplete combustion occurs with insufficient oxygen, producing carbon monoxide and\/or carbon. The question specifies “complete combustion in excess of oxygen”, ensuring the reaction proceeds as shown in the balanced equation.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

How many moles of water would be produced by the complete combustion of one mole of natural gas, CH\u2084, in excess of oxygen ? [amp_mcq option1=”1″ option2=”2″ option3=”3″ option4=”4″ correct=”option2″] This question was previously asked in UPSC CISF-AC-EXE – 2020 Download PDFAttempt Online The complete combustion of natural gas, which is primarily methane (CH\u2084), in … <\/p>\n

Detailed SolutionHow many moles of water would be produced by the complete combustion o<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1288,1096,1330],"class_list":["post-92800","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1288","tag-chemistry","tag-hydrocarbons","no-featured-image-padding"],"yoast_head":"\nHow many moles of water would be produced by the complete combustion o<\/title>\n<meta name=\"description\" content=\"The complete combustion of natural gas, which is primarily methane (CH\u2084), in excess oxygen is represented by the balanced chemical equation: CH\u2084(g) + 2O\u2082(g) \u2192 CO\u2082(g) + 2H\u2082O(g or l) The coefficients in the balanced equation represent the relative number of moles of reactants and products. According to the equation, one mole of methane (CH\u2084) reacts with two moles of oxygen (O\u2082) to produce one mole of carbon dioxide (CO\u2082) and two moles of water (H\u2082O). The stoichiometry of a balanced chemical equation gives the mole ratios of reactants and products. For the combustion of methane, 1 mole of CH\u2084 produces 2 moles of H\u2082O.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"How many moles of water would be produced by the complete combustion o\" \/>\n<meta property=\"og:description\" content=\"The complete combustion of natural gas, which is primarily methane (CH\u2084), in excess oxygen is represented by the balanced chemical equation: CH\u2084(g) + 2O\u2082(g) \u2192 CO\u2082(g) + 2H\u2082O(g or l) The coefficients in the balanced equation represent the relative number of moles of reactants and products. According to the equation, one mole of methane (CH\u2084) reacts with two moles of oxygen (O\u2082) to produce one mole of carbon dioxide (CO\u2082) and two moles of water (H\u2082O). The stoichiometry of a balanced chemical equation gives the mole ratios of reactants and products. For the combustion of methane, 1 mole of CH\u2084 produces 2 moles of H\u2082O.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:32:50+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"How many moles of water would be produced by the complete combustion o","description":"The complete combustion of natural gas, which is primarily methane (CH\u2084), in excess oxygen is represented by the balanced chemical equation: CH\u2084(g) + 2O\u2082(g) \u2192 CO\u2082(g) + 2H\u2082O(g or l) The coefficients in the balanced equation represent the relative number of moles of reactants and products. According to the equation, one mole of methane (CH\u2084) reacts with two moles of oxygen (O\u2082) to produce one mole of carbon dioxide (CO\u2082) and two moles of water (H\u2082O). The stoichiometry of a balanced chemical equation gives the mole ratios of reactants and products. For the combustion of methane, 1 mole of CH\u2084 produces 2 moles of H\u2082O.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o\/","og_locale":"en_US","og_type":"article","og_title":"How many moles of water would be produced by the complete combustion o","og_description":"The complete combustion of natural gas, which is primarily methane (CH\u2084), in excess oxygen is represented by the balanced chemical equation: CH\u2084(g) + 2O\u2082(g) \u2192 CO\u2082(g) + 2H\u2082O(g or l) The coefficients in the balanced equation represent the relative number of moles of reactants and products. According to the equation, one mole of methane (CH\u2084) reacts with two moles of oxygen (O\u2082) to produce one mole of carbon dioxide (CO\u2082) and two moles of water (H\u2082O). The stoichiometry of a balanced chemical equation gives the mole ratios of reactants and products. For the combustion of methane, 1 mole of CH\u2084 produces 2 moles of H\u2082O.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:32:50+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o\/","url":"https:\/\/exam.pscnotes.com\/mcq\/how-many-moles-of-water-would-be-produced-by-the-complete-combustion-o\/","name":"How many moles of water would be produced by the complete combustion o","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:32:50+00:00","dateModified":"2025-06-01T11:32:50+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The complete combustion of natural gas, which is primarily methane (CH\u2084), in excess oxygen is represented by the balanced chemical equation: CH\u2084(g) + 2O\u2082(g) \u2192 CO\u2082(g) + 2H\u2082O(g or l) The coefficients in the balanced equation represent the relative number of moles of reactants and products. According to the equation, one mole of methane (CH\u2084) reacts with two moles of oxygen (O\u2082) to produce one mole of carbon dioxide (CO\u2082) and two moles of water (H\u2082O). The stoichiometry of a balanced chemical equation gives the mole ratios of reactants and products. 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