{"id":92786,"date":"2025-06-01T11:32:34","date_gmt":"2025-06-01T11:32:34","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=92786"},"modified":"2025-06-01T11:32:34","modified_gmt":"2025-06-01T11:32:34","slug":"r-walks-a-long-distance-every-sunday-he-walks-2-km-towards-the-north","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/r-walks-a-long-distance-every-sunday-he-walks-2-km-towards-the-north\/","title":{"rendered":"R walks a long distance every Sunday. He walks 2 km towards the north"},"content":{"rendered":"

R walks a long distance every Sunday. He walks 2 km towards the north from his house and then turns right; he walks another 2 km and again turns right; next he walks 5 km and turns left; he further walks 2 km and stops. He rests for some time and returns home following a straight route without any turning point. What is the distance R walks after he has rested ?<\/p>\n

[amp_mcq option1=”11 km” option2=”7 km” option3=”6 km” option4=”5 km” correct=”option4″]<\/p>\n

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This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2020<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe distance R walks after he has rested is 5 km.
\n<\/section>\n
\n– Let R’s house be the starting point (0,0).
\n– 1. Walks 2 km towards North: Reaches point (0, 2).
\n– 2. Turns right (East) and walks 2 km: Reaches point (0+2, 2) = (2, 2).
\n– 3. Turns right (South) and walks 5 km: Reaches point (2, 2-5) = (2, -3).
\n– 4. Turns left (East) and walks 2 km: Reaches point (2+2, -3) = (4, -3).
\n– R stops at the point (4, -3). This point is 4 km East and 3 km South of his house (0,0).
\n– He returns home following a straight route from (4, -3) to (0,0).
\n– This is the distance between these two points, which can be calculated using the distance formula or by recognizing it as the hypotenuse of a right triangle with legs of length 4 km and 3 km.
\n– Distance = $\\sqrt{(4-0)^2 + (-3-0)^2} = \\sqrt{4^2 + (-3)^2} = \\sqrt{16 + 9} = \\sqrt{25} = 5$ km.
\n– The distance R walks after he has rested is the length of this straight return journey, which is 5 km.
\n<\/section>\n
\nDirection and distance problems can be solved by representing the movements on a coordinate plane. The final position relative to the starting point can then be determined, and the straight-line distance calculated using the Pythagorean theorem.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

R walks a long distance every Sunday. He walks 2 km towards the north from his house and then turns right; he walks another 2 km and again turns right; next he walks 5 km and turns left; he further walks 2 km and stops. He rests for some time and returns home following a … <\/p>\n

Detailed SolutionR walks a long distance every Sunday. He walks 2 km towards the north<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1288,1102],"class_list":["post-92786","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1288","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nR walks a long distance every Sunday. He walks 2 km towards the north<\/title>\n<meta name=\"description\" content=\"The distance R walks after he has rested is 5 km. - Let R's house be the starting point (0,0). - 1. Walks 2 km towards North: Reaches point (0, 2). - 2. Turns right (East) and walks 2 km: Reaches point (0+2, 2) = (2, 2). - 3. Turns right (South) and walks 5 km: Reaches point (2, 2-5) = (2, -3). - 4. Turns left (East) and walks 2 km: Reaches point (2+2, -3) = (4, -3). - R stops at the point (4, -3). This point is 4 km East and 3 km South of his house (0,0). - He returns home following a straight route from (4, -3) to (0,0). - This is the distance between these two points, which can be calculated using the distance formula or by recognizing it as the hypotenuse of a right triangle with legs of length 4 km and 3 km. - Distance = $sqrt{(4-0)^2 + (-3-0)^2} = sqrt{4^2 + (-3)^2} = sqrt{16 + 9} = sqrt{25} = 5$ km. - The distance R walks after he has rested is the length of this straight return journey, which is 5 km.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/r-walks-a-long-distance-every-sunday-he-walks-2-km-towards-the-north\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"R walks a long distance every Sunday. He walks 2 km towards the north\" \/>\n<meta property=\"og:description\" content=\"The distance R walks after he has rested is 5 km. - Let R's house be the starting point (0,0). - 1. Walks 2 km towards North: Reaches point (0, 2). - 2. Turns right (East) and walks 2 km: Reaches point (0+2, 2) = (2, 2). - 3. Turns right (South) and walks 5 km: Reaches point (2, 2-5) = (2, -3). - 4. Turns left (East) and walks 2 km: Reaches point (2+2, -3) = (4, -3). - R stops at the point (4, -3). This point is 4 km East and 3 km South of his house (0,0). - He returns home following a straight route from (4, -3) to (0,0). - This is the distance between these two points, which can be calculated using the distance formula or by recognizing it as the hypotenuse of a right triangle with legs of length 4 km and 3 km. - Distance = $sqrt{(4-0)^2 + (-3-0)^2} = sqrt{4^2 + (-3)^2} = sqrt{16 + 9} = sqrt{25} = 5$ km. - The distance R walks after he has rested is the length of this straight return journey, which is 5 km.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/r-walks-a-long-distance-every-sunday-he-walks-2-km-towards-the-north\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:32:34+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"R walks a long distance every Sunday. He walks 2 km towards the north","description":"The distance R walks after he has rested is 5 km. - Let R's house be the starting point (0,0). - 1. Walks 2 km towards North: Reaches point (0, 2). - 2. Turns right (East) and walks 2 km: Reaches point (0+2, 2) = (2, 2). - 3. Turns right (South) and walks 5 km: Reaches point (2, 2-5) = (2, -3). - 4. Turns left (East) and walks 2 km: Reaches point (2+2, -3) = (4, -3). - R stops at the point (4, -3). This point is 4 km East and 3 km South of his house (0,0). - He returns home following a straight route from (4, -3) to (0,0). - This is the distance between these two points, which can be calculated using the distance formula or by recognizing it as the hypotenuse of a right triangle with legs of length 4 km and 3 km. - Distance = $sqrt{(4-0)^2 + (-3-0)^2} = sqrt{4^2 + (-3)^2} = sqrt{16 + 9} = sqrt{25} = 5$ km. - The distance R walks after he has rested is the length of this straight return journey, which is 5 km.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/r-walks-a-long-distance-every-sunday-he-walks-2-km-towards-the-north\/","og_locale":"en_US","og_type":"article","og_title":"R walks a long distance every Sunday. 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