{"id":92782,"date":"2025-06-01T11:32:29","date_gmt":"2025-06-01T11:32:29","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=92782"},"modified":"2025-06-01T11:32:29","modified_gmt":"2025-06-01T11:32:29","slug":"two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/","title":{"rendered":"Two teams named A and B do business together and their shares are in t"},"content":{"rendered":"

Two teams named A and B do business together and their shares are in the ratio of 2 : 1. Team A has got three members A1, A2 and A3 whose shares are in the ratio of 1 : 2 : 3. Team B has got four members B1, B2, B3 and B4 whose shares are in the ratio of 1 : 2 : 3 : 4. If the actual share of B3 is \u20b9 2,25,000, then what is the actual share of A2 ?<\/p>\n

[amp_mcq option1=”\u20b9 5,00,000″ option2=”\u20b9 4,00,000″ option3=”\u20b9 2,00,000″ option4=”\u20b9 1,00,000″ correct=”option1″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2020<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe actual share of A2 is \u20b9 5,00,000.
\n<\/section>\n
\n– The shares of Team A and Team B are in the ratio 2:1. Let the total business amount be 3k. Then Team A’s share is 2k and Team B’s share is k.
\n– Team A’s share (2k) is divided among A1, A2, A3 in the ratio 1:2:3. The total parts in this ratio are 1+2+3=6.
\n– A2’s share within Team A is (2\/6) of Team A’s total share = (1\/3) * 2k.
\n– Team B’s share (k) is divided among B1, B2, B3, B4 in the ratio 1:2:3:4. The total parts in this ratio are 1+2+3+4=10.
\n– B3’s share within Team B is (3\/10) of Team B’s total share = (3\/10) * k.
\n– We are given that the actual share of B3 is \u20b9 2,25,000.
\n– So, (3\/10) * k = 2,25,000.
\n– From this, we can find k: k = (2,25,000 * 10) \/ 3 = 2,250,000 \/ 3 = 7,50,000.
\n– Team B’s total share is \u20b9 7,50,000. Team A’s total share is 2k = 2 * 7,50,000 = \u20b9 15,00,000.
\n– Now we find A2’s share, which is (1\/3) of Team A’s share.
\n– A2’s share = (1\/3) * 15,00,000 = 5,00,000.
\n<\/section>\n
\nProblems involving nested ratios can be solved by representing the total shares of the larger groups (Teams A and B) and then distributing those shares according to the internal ratios of their members.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Two teams named A and B do business together and their shares are in the ratio of 2 : 1. Team A has got three members A1, A2 and A3 whose shares are in the ratio of 1 : 2 : 3. Team B has got four members B1, B2, B3 and B4 whose shares … <\/p>\n

Detailed SolutionTwo teams named A and B do business together and their shares are in t<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1288,1102],"class_list":["post-92782","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1288","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nTwo teams named A and B do business together and their shares are in t<\/title>\n<meta name=\"description\" content=\"The actual share of A2 is \u20b9 5,00,000. - The shares of Team A and Team B are in the ratio 2:1. Let the total business amount be 3k. Then Team A's share is 2k and Team B's share is k. - Team A's share (2k) is divided among A1, A2, A3 in the ratio 1:2:3. The total parts in this ratio are 1+2+3=6. - A2's share within Team A is (2\/6) of Team A's total share = (1\/3) * 2k. - Team B's share (k) is divided among B1, B2, B3, B4 in the ratio 1:2:3:4. The total parts in this ratio are 1+2+3+4=10. - B3's share within Team B is (3\/10) of Team B's total share = (3\/10) * k. - We are given that the actual share of B3 is \u20b9 2,25,000. - So, (3\/10) * k = 2,25,000. - From this, we can find k: k = (2,25,000 * 10) \/ 3 = 2,250,000 \/ 3 = 7,50,000. - Team B's total share is \u20b9 7,50,000. Team A's total share is 2k = 2 * 7,50,000 = \u20b9 15,00,000. - Now we find A2's share, which is (1\/3) of Team A's share. - A2's share = (1\/3) * 15,00,000 = 5,00,000.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Two teams named A and B do business together and their shares are in t\" \/>\n<meta property=\"og:description\" content=\"The actual share of A2 is \u20b9 5,00,000. - The shares of Team A and Team B are in the ratio 2:1. Let the total business amount be 3k. Then Team A's share is 2k and Team B's share is k. - Team A's share (2k) is divided among A1, A2, A3 in the ratio 1:2:3. The total parts in this ratio are 1+2+3=6. - A2's share within Team A is (2\/6) of Team A's total share = (1\/3) * 2k. - Team B's share (k) is divided among B1, B2, B3, B4 in the ratio 1:2:3:4. The total parts in this ratio are 1+2+3+4=10. - B3's share within Team B is (3\/10) of Team B's total share = (3\/10) * k. - We are given that the actual share of B3 is \u20b9 2,25,000. - So, (3\/10) * k = 2,25,000. - From this, we can find k: k = (2,25,000 * 10) \/ 3 = 2,250,000 \/ 3 = 7,50,000. - Team B's total share is \u20b9 7,50,000. Team A's total share is 2k = 2 * 7,50,000 = \u20b9 15,00,000. - Now we find A2's share, which is (1\/3) of Team A's share. - A2's share = (1\/3) * 15,00,000 = 5,00,000.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:32:29+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Two teams named A and B do business together and their shares are in t","description":"The actual share of A2 is \u20b9 5,00,000. - The shares of Team A and Team B are in the ratio 2:1. Let the total business amount be 3k. Then Team A's share is 2k and Team B's share is k. - Team A's share (2k) is divided among A1, A2, A3 in the ratio 1:2:3. The total parts in this ratio are 1+2+3=6. - A2's share within Team A is (2\/6) of Team A's total share = (1\/3) * 2k. - Team B's share (k) is divided among B1, B2, B3, B4 in the ratio 1:2:3:4. The total parts in this ratio are 1+2+3+4=10. - B3's share within Team B is (3\/10) of Team B's total share = (3\/10) * k. - We are given that the actual share of B3 is \u20b9 2,25,000. - So, (3\/10) * k = 2,25,000. - From this, we can find k: k = (2,25,000 * 10) \/ 3 = 2,250,000 \/ 3 = 7,50,000. - Team B's total share is \u20b9 7,50,000. Team A's total share is 2k = 2 * 7,50,000 = \u20b9 15,00,000. - Now we find A2's share, which is (1\/3) of Team A's share. - A2's share = (1\/3) * 15,00,000 = 5,00,000.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/","og_locale":"en_US","og_type":"article","og_title":"Two teams named A and B do business together and their shares are in t","og_description":"The actual share of A2 is \u20b9 5,00,000. - The shares of Team A and Team B are in the ratio 2:1. Let the total business amount be 3k. Then Team A's share is 2k and Team B's share is k. - Team A's share (2k) is divided among A1, A2, A3 in the ratio 1:2:3. The total parts in this ratio are 1+2+3=6. - A2's share within Team A is (2\/6) of Team A's total share = (1\/3) * 2k. - Team B's share (k) is divided among B1, B2, B3, B4 in the ratio 1:2:3:4. The total parts in this ratio are 1+2+3+4=10. - B3's share within Team B is (3\/10) of Team B's total share = (3\/10) * k. - We are given that the actual share of B3 is \u20b9 2,25,000. - So, (3\/10) * k = 2,25,000. - From this, we can find k: k = (2,25,000 * 10) \/ 3 = 2,250,000 \/ 3 = 7,50,000. - Team B's total share is \u20b9 7,50,000. Team A's total share is 2k = 2 * 7,50,000 = \u20b9 15,00,000. - Now we find A2's share, which is (1\/3) of Team A's share. - A2's share = (1\/3) * 15,00,000 = 5,00,000.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:32:29+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/","url":"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/","name":"Two teams named A and B do business together and their shares are in t","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:32:29+00:00","dateModified":"2025-06-01T11:32:29+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The actual share of A2 is \u20b9 5,00,000. - The shares of Team A and Team B are in the ratio 2:1. Let the total business amount be 3k. Then Team A's share is 2k and Team B's share is k. - Team A's share (2k) is divided among A1, A2, A3 in the ratio 1:2:3. The total parts in this ratio are 1+2+3=6. - A2's share within Team A is (2\/6) of Team A's total share = (1\/3) * 2k. - Team B's share (k) is divided among B1, B2, B3, B4 in the ratio 1:2:3:4. The total parts in this ratio are 1+2+3+4=10. - B3's share within Team B is (3\/10) of Team B's total share = (3\/10) * k. - We are given that the actual share of B3 is \u20b9 2,25,000. - So, (3\/10) * k = 2,25,000. - From this, we can find k: k = (2,25,000 * 10) \/ 3 = 2,250,000 \/ 3 = 7,50,000. - Team B's total share is \u20b9 7,50,000. Team A's total share is 2k = 2 * 7,50,000 = \u20b9 15,00,000. - Now we find A2's share, which is (1\/3) of Team A's share. - A2's share = (1\/3) * 15,00,000 = 5,00,000.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/two-teams-named-a-and-b-do-business-together-and-their-shares-are-in-t\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CISF-AC-EXE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cisf-ac-exe\/"},{"@type":"ListItem","position":3,"name":"Two teams named A and B do business together and their shares are in t"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92782","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=92782"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92782\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=92782"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=92782"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=92782"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}