{"id":92781,"date":"2025-06-01T11:32:27","date_gmt":"2025-06-01T11:32:27","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=92781"},"modified":"2025-06-01T11:32:27","modified_gmt":"2025-06-01T11:32:27","slug":"container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/","title":{"rendered":"Container I contains a mixture of 2 liters of oil and 3 liters of wate"},"content":{"rendered":"

Container I contains a mixture of 2 liters of oil and 3 liters of water. Container II contains a mixture of 6 liters of oil and 7 liters of water. 50% of the mixture of container I and 25% of the mixture of container II are transferred to container III. What is the proportion of oil and water in container III ?<\/p>\n

[amp_mcq option1=”4 : 5″ option2=”5 : 4″ option3=”13 : 10″ option4=”10 : 13″ correct=”option4″]<\/p>\n

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\n
This question was previously asked in<\/div>\n
UPSC CISF-AC-EXE – 2020<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct proportion of oil and water in container III is 10 : 13.
\n<\/section>\n
\n– Container I has 2 L oil and 3 L water (total 5 L). 50% of this mixture is transferred, which is 2.5 L. This 2.5 L contains 50% of the oil from container I (0.5 * 2 L = 1 L oil) and 50% of the water from container I (0.5 * 3 L = 1.5 L water).
\n– Container II has 6 L oil and 7 L water (total 13 L). 25% of this mixture is transferred, which is 13\/4 L = 3.25 L. This 3.25 L contains 25% of the oil from container II (0.25 * 6 L = 1.5 L oil) and 25% of the water from container II (0.25 * 7 L = 1.75 L water).
\n– Container III receives the transferred amounts. Total oil in container III = 1 L (from I) + 1.5 L (from II) = 2.5 L. Total water in container III = 1.5 L (from I) + 1.75 L (from II) = 3.25 L.
\n– The proportion of oil to water in container III is 2.5 L : 3.25 L.
\n– To simplify the ratio, we can multiply both parts by 100 to remove decimals: 250 : 325.
\n– Dividing both by their greatest common divisor, 25: 250\/25 = 10 and 325\/25 = 13.
\n– The ratio is 10 : 13.
\n<\/section>\n
\nWhen a portion of a mixture is taken out, the ratio of components in the taken portion is the same as the ratio in the original mixture. The amount of each component transferred is calculated based on this ratio and the total amount transferred.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Container I contains a mixture of 2 liters of oil and 3 liters of water. Container II contains a mixture of 6 liters of oil and 7 liters of water. 50% of the mixture of container I and 25% of the mixture of container II are transferred to container III. What is the proportion of … <\/p>\n

Detailed SolutionContainer I contains a mixture of 2 liters of oil and 3 liters of wate<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1288,1102],"class_list":["post-92781","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1288","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nContainer I contains a mixture of 2 liters of oil and 3 liters of wate<\/title>\n<meta name=\"description\" content=\"The correct proportion of oil and water in container III is 10 : 13. - Container I has 2 L oil and 3 L water (total 5 L). 50% of this mixture is transferred, which is 2.5 L. This 2.5 L contains 50% of the oil from container I (0.5 * 2 L = 1 L oil) and 50% of the water from container I (0.5 * 3 L = 1.5 L water). - Container II has 6 L oil and 7 L water (total 13 L). 25% of this mixture is transferred, which is 13\/4 L = 3.25 L. This 3.25 L contains 25% of the oil from container II (0.25 * 6 L = 1.5 L oil) and 25% of the water from container II (0.25 * 7 L = 1.75 L water). - Container III receives the transferred amounts. Total oil in container III = 1 L (from I) + 1.5 L (from II) = 2.5 L. Total water in container III = 1.5 L (from I) + 1.75 L (from II) = 3.25 L. - The proportion of oil to water in container III is 2.5 L : 3.25 L. - To simplify the ratio, we can multiply both parts by 100 to remove decimals: 250 : 325. - Dividing both by their greatest common divisor, 25: 250\/25 = 10 and 325\/25 = 13. - The ratio is 10 : 13.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Container I contains a mixture of 2 liters of oil and 3 liters of wate\" \/>\n<meta property=\"og:description\" content=\"The correct proportion of oil and water in container III is 10 : 13. - Container I has 2 L oil and 3 L water (total 5 L). 50% of this mixture is transferred, which is 2.5 L. This 2.5 L contains 50% of the oil from container I (0.5 * 2 L = 1 L oil) and 50% of the water from container I (0.5 * 3 L = 1.5 L water). - Container II has 6 L oil and 7 L water (total 13 L). 25% of this mixture is transferred, which is 13\/4 L = 3.25 L. This 3.25 L contains 25% of the oil from container II (0.25 * 6 L = 1.5 L oil) and 25% of the water from container II (0.25 * 7 L = 1.75 L water). - Container III receives the transferred amounts. Total oil in container III = 1 L (from I) + 1.5 L (from II) = 2.5 L. Total water in container III = 1.5 L (from I) + 1.75 L (from II) = 3.25 L. - The proportion of oil to water in container III is 2.5 L : 3.25 L. - To simplify the ratio, we can multiply both parts by 100 to remove decimals: 250 : 325. - Dividing both by their greatest common divisor, 25: 250\/25 = 10 and 325\/25 = 13. - The ratio is 10 : 13.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:32:27+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Container I contains a mixture of 2 liters of oil and 3 liters of wate","description":"The correct proportion of oil and water in container III is 10 : 13. - Container I has 2 L oil and 3 L water (total 5 L). 50% of this mixture is transferred, which is 2.5 L. This 2.5 L contains 50% of the oil from container I (0.5 * 2 L = 1 L oil) and 50% of the water from container I (0.5 * 3 L = 1.5 L water). - Container II has 6 L oil and 7 L water (total 13 L). 25% of this mixture is transferred, which is 13\/4 L = 3.25 L. This 3.25 L contains 25% of the oil from container II (0.25 * 6 L = 1.5 L oil) and 25% of the water from container II (0.25 * 7 L = 1.75 L water). - Container III receives the transferred amounts. Total oil in container III = 1 L (from I) + 1.5 L (from II) = 2.5 L. Total water in container III = 1.5 L (from I) + 1.75 L (from II) = 3.25 L. - The proportion of oil to water in container III is 2.5 L : 3.25 L. - To simplify the ratio, we can multiply both parts by 100 to remove decimals: 250 : 325. - Dividing both by their greatest common divisor, 25: 250\/25 = 10 and 325\/25 = 13. - The ratio is 10 : 13.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/","og_locale":"en_US","og_type":"article","og_title":"Container I contains a mixture of 2 liters of oil and 3 liters of wate","og_description":"The correct proportion of oil and water in container III is 10 : 13. - Container I has 2 L oil and 3 L water (total 5 L). 50% of this mixture is transferred, which is 2.5 L. This 2.5 L contains 50% of the oil from container I (0.5 * 2 L = 1 L oil) and 50% of the water from container I (0.5 * 3 L = 1.5 L water). - Container II has 6 L oil and 7 L water (total 13 L). 25% of this mixture is transferred, which is 13\/4 L = 3.25 L. This 3.25 L contains 25% of the oil from container II (0.25 * 6 L = 1.5 L oil) and 25% of the water from container II (0.25 * 7 L = 1.75 L water). - Container III receives the transferred amounts. Total oil in container III = 1 L (from I) + 1.5 L (from II) = 2.5 L. Total water in container III = 1.5 L (from I) + 1.75 L (from II) = 3.25 L. - The proportion of oil to water in container III is 2.5 L : 3.25 L. - To simplify the ratio, we can multiply both parts by 100 to remove decimals: 250 : 325. - Dividing both by their greatest common divisor, 25: 250\/25 = 10 and 325\/25 = 13. - The ratio is 10 : 13.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:32:27+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/","url":"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/","name":"Container I contains a mixture of 2 liters of oil and 3 liters of wate","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:32:27+00:00","dateModified":"2025-06-01T11:32:27+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct proportion of oil and water in container III is 10 : 13. - Container I has 2 L oil and 3 L water (total 5 L). 50% of this mixture is transferred, which is 2.5 L. This 2.5 L contains 50% of the oil from container I (0.5 * 2 L = 1 L oil) and 50% of the water from container I (0.5 * 3 L = 1.5 L water). - Container II has 6 L oil and 7 L water (total 13 L). 25% of this mixture is transferred, which is 13\/4 L = 3.25 L. This 3.25 L contains 25% of the oil from container II (0.25 * 6 L = 1.5 L oil) and 25% of the water from container II (0.25 * 7 L = 1.75 L water). - Container III receives the transferred amounts. Total oil in container III = 1 L (from I) + 1.5 L (from II) = 2.5 L. Total water in container III = 1.5 L (from I) + 1.75 L (from II) = 3.25 L. - The proportion of oil to water in container III is 2.5 L : 3.25 L. - To simplify the ratio, we can multiply both parts by 100 to remove decimals: 250 : 325. - Dividing both by their greatest common divisor, 25: 250\/25 = 10 and 325\/25 = 13. - The ratio is 10 : 13.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/container-i-contains-a-mixture-of-2-liters-of-oil-and-3-liters-of-wate\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CISF-AC-EXE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cisf-ac-exe\/"},{"@type":"ListItem","position":3,"name":"Container I contains a mixture of 2 liters of oil and 3 liters of wate"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92781","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=92781"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92781\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=92781"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=92781"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=92781"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}