{"id":92641,"date":"2025-06-01T11:29:42","date_gmt":"2025-06-01T11:29:42","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=92641"},"modified":"2025-06-01T11:29:42","modified_gmt":"2025-06-01T11:29:42","slug":"the-transportation-cost-charged-by-a-shipping-company-is-proportional","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/","title":{"rendered":"The transportation cost charged by a shipping company is proportional"},"content":{"rendered":"<p>The transportation cost charged by a shipping company is proportional to the square root of the distance and proportional to the volume of the parcel. If the distance is increased to 4 times, how much volume of the parcel can be transported with the same cost?<\/p>\n<p>[amp_mcq option1=&#8221;25%&#8221; option2=&#8221;50%&#8221; option3=&#8221;66%&#8221; option4=&#8221;75%&#8221; correct=&#8221;option2&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CISF-AC-EXE &#8211; 2019<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-cisf-ac-exe-2019.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-cisf-ac-exe-2019\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe correct answer is 50%.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nThe transportation cost (C) is proportional to the square root of the distance (D) and proportional to the volume (V). This can be written as C \u221d \u221aD * V, or C = k * \u221aD * V, where k is a constant.<\/p>\n<p>We are given that the cost remains the same (C\u2081 = C\u2082) while the distance is increased to 4 times (D\u2082 = 4D\u2081). We need to find the new volume (V\u2082) in terms of the original volume (V\u2081).<\/p>\n<p>Using the formula:<br \/>\nC\u2081 = k * \u221aD\u2081 * V\u2081<br \/>\nC\u2082 = k * \u221aD\u2082 * V\u2082<\/p>\n<p>Since C\u2081 = C\u2082, we have:<br \/>\nk * \u221aD\u2081 * V\u2081 = k * \u221aD\u2082 * V\u2082<br \/>\n\u221aD\u2081 * V\u2081 = \u221aD\u2082 * V\u2082<\/p>\n<p>Substitute D\u2082 = 4D\u2081:<br \/>\n\u221aD\u2081 * V\u2081 = \u221a(4D\u2081) * V\u2082<br \/>\n\u221aD\u2081 * V\u2081 = 2\u221aD\u2081 * V\u2082<\/p>\n<p>Assuming D\u2081 > 0, we can divide both sides by \u221aD\u2081:<br \/>\nV\u2081 = 2 * V\u2082<\/p>\n<p>Solving for V\u2082:<br \/>\nV\u2082 = V\u2081 \/ 2<\/p>\n<p>This means the new volume V\u2082 is half of the original volume V\u2081, which is 50%.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nThis type of problem involves understanding and applying direct and inverse proportionality relationships described in the problem statement. Keeping the cost constant requires adjusting the volume inversely proportionally to the square root of the distance.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>The transportation cost charged by a shipping company is proportional to the square root of the distance and proportional to the volume of the parcel. If the distance is increased to 4 times, how much volume of the parcel can be transported with the same cost? [amp_mcq option1=&#8221;25%&#8221; option2=&#8221;50%&#8221; option3=&#8221;66%&#8221; option4=&#8221;75%&#8221; correct=&#8221;option2&#8243;] This question was &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"The transportation cost charged by a shipping company is proportional\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/#more-92641\">Detailed Solution<span class=\"screen-reader-text\">The transportation cost charged by a shipping company is proportional<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1119,1102],"class_list":["post-92641","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1119","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>The transportation cost charged by a shipping company is proportional<\/title>\n<meta name=\"description\" content=\"The correct answer is 50%. The transportation cost (C) is proportional to the square root of the distance (D) and proportional to the volume (V). This can be written as C \u221d \u221aD * V, or C = k * \u221aD * V, where k is a constant. We are given that the cost remains the same (C\u2081 = C\u2082) while the distance is increased to 4 times (D\u2082 = 4D\u2081). We need to find the new volume (V\u2082) in terms of the original volume (V\u2081). Using the formula: C\u2081 = k * \u221aD\u2081 * V\u2081 C\u2082 = k * \u221aD\u2082 * V\u2082 Since C\u2081 = C\u2082, we have: k * \u221aD\u2081 * V\u2081 = k * \u221aD\u2082 * V\u2082 \u221aD\u2081 * V\u2081 = \u221aD\u2082 * V\u2082 Substitute D\u2082 = 4D\u2081: \u221aD\u2081 * V\u2081 = \u221a(4D\u2081) * V\u2082 \u221aD\u2081 * V\u2081 = 2\u221aD\u2081 * V\u2082 Assuming D\u2081 &gt; 0, we can divide both sides by \u221aD\u2081: V\u2081 = 2 * V\u2082 Solving for V\u2082: V\u2082 = V\u2081 \/ 2 This means the new volume V\u2082 is half of the original volume V\u2081, which is 50%.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The transportation cost charged by a shipping company is proportional\" \/>\n<meta property=\"og:description\" content=\"The correct answer is 50%. The transportation cost (C) is proportional to the square root of the distance (D) and proportional to the volume (V). This can be written as C \u221d \u221aD * V, or C = k * \u221aD * V, where k is a constant. We are given that the cost remains the same (C\u2081 = C\u2082) while the distance is increased to 4 times (D\u2082 = 4D\u2081). We need to find the new volume (V\u2082) in terms of the original volume (V\u2081). Using the formula: C\u2081 = k * \u221aD\u2081 * V\u2081 C\u2082 = k * \u221aD\u2082 * V\u2082 Since C\u2081 = C\u2082, we have: k * \u221aD\u2081 * V\u2081 = k * \u221aD\u2082 * V\u2082 \u221aD\u2081 * V\u2081 = \u221aD\u2082 * V\u2082 Substitute D\u2082 = 4D\u2081: \u221aD\u2081 * V\u2081 = \u221a(4D\u2081) * V\u2082 \u221aD\u2081 * V\u2081 = 2\u221aD\u2081 * V\u2082 Assuming D\u2081 &gt; 0, we can divide both sides by \u221aD\u2081: V\u2081 = 2 * V\u2082 Solving for V\u2082: V\u2082 = V\u2081 \/ 2 This means the new volume V\u2082 is half of the original volume V\u2081, which is 50%.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:29:42+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The transportation cost charged by a shipping company is proportional","description":"The correct answer is 50%. The transportation cost (C) is proportional to the square root of the distance (D) and proportional to the volume (V). This can be written as C \u221d \u221aD * V, or C = k * \u221aD * V, where k is a constant. We are given that the cost remains the same (C\u2081 = C\u2082) while the distance is increased to 4 times (D\u2082 = 4D\u2081). We need to find the new volume (V\u2082) in terms of the original volume (V\u2081). Using the formula: C\u2081 = k * \u221aD\u2081 * V\u2081 C\u2082 = k * \u221aD\u2082 * V\u2082 Since C\u2081 = C\u2082, we have: k * \u221aD\u2081 * V\u2081 = k * \u221aD\u2082 * V\u2082 \u221aD\u2081 * V\u2081 = \u221aD\u2082 * V\u2082 Substitute D\u2082 = 4D\u2081: \u221aD\u2081 * V\u2081 = \u221a(4D\u2081) * V\u2082 \u221aD\u2081 * V\u2081 = 2\u221aD\u2081 * V\u2082 Assuming D\u2081 > 0, we can divide both sides by \u221aD\u2081: V\u2081 = 2 * V\u2082 Solving for V\u2082: V\u2082 = V\u2081 \/ 2 This means the new volume V\u2082 is half of the original volume V\u2081, which is 50%.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/","og_locale":"en_US","og_type":"article","og_title":"The transportation cost charged by a shipping company is proportional","og_description":"The correct answer is 50%. The transportation cost (C) is proportional to the square root of the distance (D) and proportional to the volume (V). This can be written as C \u221d \u221aD * V, or C = k * \u221aD * V, where k is a constant. We are given that the cost remains the same (C\u2081 = C\u2082) while the distance is increased to 4 times (D\u2082 = 4D\u2081). We need to find the new volume (V\u2082) in terms of the original volume (V\u2081). Using the formula: C\u2081 = k * \u221aD\u2081 * V\u2081 C\u2082 = k * \u221aD\u2082 * V\u2082 Since C\u2081 = C\u2082, we have: k * \u221aD\u2081 * V\u2081 = k * \u221aD\u2082 * V\u2082 \u221aD\u2081 * V\u2081 = \u221aD\u2082 * V\u2082 Substitute D\u2082 = 4D\u2081: \u221aD\u2081 * V\u2081 = \u221a(4D\u2081) * V\u2082 \u221aD\u2081 * V\u2081 = 2\u221aD\u2081 * V\u2082 Assuming D\u2081 > 0, we can divide both sides by \u221aD\u2081: V\u2081 = 2 * V\u2082 Solving for V\u2082: V\u2082 = V\u2081 \/ 2 This means the new volume V\u2082 is half of the original volume V\u2081, which is 50%.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:29:42+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/","name":"The transportation cost charged by a shipping company is proportional","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:29:42+00:00","dateModified":"2025-06-01T11:29:42+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is 50%. The transportation cost (C) is proportional to the square root of the distance (D) and proportional to the volume (V). This can be written as C \u221d \u221aD * V, or C = k * \u221aD * V, where k is a constant. We are given that the cost remains the same (C\u2081 = C\u2082) while the distance is increased to 4 times (D\u2082 = 4D\u2081). We need to find the new volume (V\u2082) in terms of the original volume (V\u2081). Using the formula: C\u2081 = k * \u221aD\u2081 * V\u2081 C\u2082 = k * \u221aD\u2082 * V\u2082 Since C\u2081 = C\u2082, we have: k * \u221aD\u2081 * V\u2081 = k * \u221aD\u2082 * V\u2082 \u221aD\u2081 * V\u2081 = \u221aD\u2082 * V\u2082 Substitute D\u2082 = 4D\u2081: \u221aD\u2081 * V\u2081 = \u221a(4D\u2081) * V\u2082 \u221aD\u2081 * V\u2081 = 2\u221aD\u2081 * V\u2082 Assuming D\u2081 > 0, we can divide both sides by \u221aD\u2081: V\u2081 = 2 * V\u2082 Solving for V\u2082: V\u2082 = V\u2081 \/ 2 This means the new volume V\u2082 is half of the original volume V\u2081, which is 50%.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-transportation-cost-charged-by-a-shipping-company-is-proportional\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CISF-AC-EXE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cisf-ac-exe\/"},{"@type":"ListItem","position":3,"name":"The transportation cost charged by a shipping company is proportional"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92641","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=92641"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92641\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=92641"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=92641"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=92641"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}