{"id":92640,"date":"2025-06-01T11:29:41","date_gmt":"2025-06-01T11:29:41","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=92640"},"modified":"2025-06-01T11:29:41","modified_gmt":"2025-06-01T11:29:41","slug":"a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/","title":{"rendered":"A man rows at 6 km\/hr in still water and with the same effort he rows"},"content":{"rendered":"<p>A man rows at 6 km\/hr in still water and with the same effort he rows 4.5 km\/hr against the stream of a river. What is the speed if he rows (with the same effort) along the stream of the river?<\/p>\n<p>[amp_mcq option1=&#8221;7\u00bd km\/hr&#8221; option2=&#8221;7 km\/hr&#8221; option3=&#8221;6\u00bd km\/hr&#8221; option4=&#8221;6\u00bc km\/hr&#8221; correct=&#8221;option1&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CISF-AC-EXE &#8211; 2019<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-cisf-ac-exe-2019.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-cisf-ac-exe-2019\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nLet v be the speed of the man in still water and u be the speed of the river stream.<br \/>\nSpeed of man in still water, v = 6 km\/hr.<\/p>\n<p>Speed against the stream (upstream speed) = Speed in still water &#8211; Speed of stream = v &#8211; u.<br \/>\nWe are given that the speed against the stream is 4.5 km\/hr.<br \/>\nv &#8211; u = 4.5<br \/>\nSubstitute the value of v:<br \/>\n6 &#8211; u = 4.5<br \/>\nu = 6 &#8211; 4.5 = 1.5 km\/hr.<br \/>\nThe speed of the river stream is 1.5 km\/hr.<\/p>\n<p>We need to find the speed if he rows along the stream (downstream speed) with the same effort. The effort remaining the same means his speed relative to the water is still v.<br \/>\nSpeed along the stream (downstream speed) = Speed in still water + Speed of stream = v + u.<br \/>\nSubstitute the values of v and u:<br \/>\nDownstream speed = 6 + 1.5 = 7.5 km\/hr.<\/p>\n<p>The question asks for the speed in one of the given options. 7.5 km\/hr is equivalent to 7 and a half km\/hr.<br \/>\n7.5 = 7 + 0.5 = 7 + 1\/2 = 7\u00bd km\/hr.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\n&#8211; Speed upstream = Speed in still water &#8211; Speed of stream.<br \/>\n&#8211; Speed downstream = Speed in still water + Speed of stream.<br \/>\n&#8211; The effort remaining the same implies the speed of the man relative to the water (speed in still water) is constant.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nIf upstream speed and downstream speed are given, the speed in still water and speed of the stream can be found:<br \/>\nSpeed in still water = (Downstream speed + Upstream speed) \/ 2<br \/>\nSpeed of stream = (Downstream speed &#8211; Upstream speed) \/ 2<br \/>\nIn this case, we found v=6 and u=1.5.<br \/>\nUpstream speed = 6 &#8211; 1.5 = 4.5 km\/hr (Given).<br \/>\nDownstream speed = 6 + 1.5 = 7.5 km\/hr (Calculated).<br \/>\nCheck using the formulas:<br \/>\nSpeed in still water = (7.5 + 4.5) \/ 2 = 12 \/ 2 = 6 km\/hr (Matches given v).<br \/>\nSpeed of stream = (7.5 &#8211; 4.5) \/ 2 = 3 \/ 2 = 1.5 km\/hr (Matches calculated u).<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>A man rows at 6 km\/hr in still water and with the same effort he rows 4.5 km\/hr against the stream of a river. What is the speed if he rows (with the same effort) along the stream of the river? [amp_mcq option1=&#8221;7\u00bd km\/hr&#8221; option2=&#8221;7 km\/hr&#8221; option3=&#8221;6\u00bd km\/hr&#8221; option4=&#8221;6\u00bc km\/hr&#8221; correct=&#8221;option1&#8243;] This question was previously &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"A man rows at 6 km\/hr in still water and with the same effort he rows\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/#more-92640\">Detailed Solution<span class=\"screen-reader-text\">A man rows at 6 km\/hr in still water and with the same effort he rows<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1089],"tags":[1119,1102],"class_list":["post-92640","post","type-post","status-publish","format-standard","hentry","category-upsc-cisf-ac-exe","tag-1119","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A man rows at 6 km\/hr in still water and with the same effort he rows<\/title>\n<meta name=\"description\" content=\"Let v be the speed of the man in still water and u be the speed of the river stream. Speed of man in still water, v = 6 km\/hr. Speed against the stream (upstream speed) = Speed in still water - Speed of stream = v - u. We are given that the speed against the stream is 4.5 km\/hr. v - u = 4.5 Substitute the value of v: 6 - u = 4.5 u = 6 - 4.5 = 1.5 km\/hr. The speed of the river stream is 1.5 km\/hr. We need to find the speed if he rows along the stream (downstream speed) with the same effort. The effort remaining the same means his speed relative to the water is still v. Speed along the stream (downstream speed) = Speed in still water + Speed of stream = v + u. Substitute the values of v and u: Downstream speed = 6 + 1.5 = 7.5 km\/hr. The question asks for the speed in one of the given options. 7.5 km\/hr is equivalent to 7 and a half km\/hr. 7.5 = 7 + 0.5 = 7 + 1\/2 = 7\u00bd km\/hr. - Speed upstream = Speed in still water - Speed of stream. - Speed downstream = Speed in still water + Speed of stream. - The effort remaining the same implies the speed of the man relative to the water (speed in still water) is constant.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A man rows at 6 km\/hr in still water and with the same effort he rows\" \/>\n<meta property=\"og:description\" content=\"Let v be the speed of the man in still water and u be the speed of the river stream. Speed of man in still water, v = 6 km\/hr. Speed against the stream (upstream speed) = Speed in still water - Speed of stream = v - u. We are given that the speed against the stream is 4.5 km\/hr. v - u = 4.5 Substitute the value of v: 6 - u = 4.5 u = 6 - 4.5 = 1.5 km\/hr. The speed of the river stream is 1.5 km\/hr. We need to find the speed if he rows along the stream (downstream speed) with the same effort. The effort remaining the same means his speed relative to the water is still v. Speed along the stream (downstream speed) = Speed in still water + Speed of stream = v + u. Substitute the values of v and u: Downstream speed = 6 + 1.5 = 7.5 km\/hr. The question asks for the speed in one of the given options. 7.5 km\/hr is equivalent to 7 and a half km\/hr. 7.5 = 7 + 0.5 = 7 + 1\/2 = 7\u00bd km\/hr. - Speed upstream = Speed in still water - Speed of stream. - Speed downstream = Speed in still water + Speed of stream. - The effort remaining the same implies the speed of the man relative to the water (speed in still water) is constant.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:29:41+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A man rows at 6 km\/hr in still water and with the same effort he rows","description":"Let v be the speed of the man in still water and u be the speed of the river stream. Speed of man in still water, v = 6 km\/hr. Speed against the stream (upstream speed) = Speed in still water - Speed of stream = v - u. We are given that the speed against the stream is 4.5 km\/hr. v - u = 4.5 Substitute the value of v: 6 - u = 4.5 u = 6 - 4.5 = 1.5 km\/hr. The speed of the river stream is 1.5 km\/hr. We need to find the speed if he rows along the stream (downstream speed) with the same effort. The effort remaining the same means his speed relative to the water is still v. Speed along the stream (downstream speed) = Speed in still water + Speed of stream = v + u. Substitute the values of v and u: Downstream speed = 6 + 1.5 = 7.5 km\/hr. The question asks for the speed in one of the given options. 7.5 km\/hr is equivalent to 7 and a half km\/hr. 7.5 = 7 + 0.5 = 7 + 1\/2 = 7\u00bd km\/hr. - Speed upstream = Speed in still water - Speed of stream. - Speed downstream = Speed in still water + Speed of stream. - The effort remaining the same implies the speed of the man relative to the water (speed in still water) is constant.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/","og_locale":"en_US","og_type":"article","og_title":"A man rows at 6 km\/hr in still water and with the same effort he rows","og_description":"Let v be the speed of the man in still water and u be the speed of the river stream. Speed of man in still water, v = 6 km\/hr. Speed against the stream (upstream speed) = Speed in still water - Speed of stream = v - u. We are given that the speed against the stream is 4.5 km\/hr. v - u = 4.5 Substitute the value of v: 6 - u = 4.5 u = 6 - 4.5 = 1.5 km\/hr. The speed of the river stream is 1.5 km\/hr. We need to find the speed if he rows along the stream (downstream speed) with the same effort. The effort remaining the same means his speed relative to the water is still v. Speed along the stream (downstream speed) = Speed in still water + Speed of stream = v + u. Substitute the values of v and u: Downstream speed = 6 + 1.5 = 7.5 km\/hr. The question asks for the speed in one of the given options. 7.5 km\/hr is equivalent to 7 and a half km\/hr. 7.5 = 7 + 0.5 = 7 + 1\/2 = 7\u00bd km\/hr. - Speed upstream = Speed in still water - Speed of stream. - Speed downstream = Speed in still water + Speed of stream. - The effort remaining the same implies the speed of the man relative to the water (speed in still water) is constant.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:29:41+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/","name":"A man rows at 6 km\/hr in still water and with the same effort he rows","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:29:41+00:00","dateModified":"2025-06-01T11:29:41+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Let v be the speed of the man in still water and u be the speed of the river stream. Speed of man in still water, v = 6 km\/hr. Speed against the stream (upstream speed) = Speed in still water - Speed of stream = v - u. We are given that the speed against the stream is 4.5 km\/hr. v - u = 4.5 Substitute the value of v: 6 - u = 4.5 u = 6 - 4.5 = 1.5 km\/hr. The speed of the river stream is 1.5 km\/hr. We need to find the speed if he rows along the stream (downstream speed) with the same effort. The effort remaining the same means his speed relative to the water is still v. Speed along the stream (downstream speed) = Speed in still water + Speed of stream = v + u. Substitute the values of v and u: Downstream speed = 6 + 1.5 = 7.5 km\/hr. The question asks for the speed in one of the given options. 7.5 km\/hr is equivalent to 7 and a half km\/hr. 7.5 = 7 + 0.5 = 7 + 1\/2 = 7\u00bd km\/hr. - Speed upstream = Speed in still water - Speed of stream. - Speed downstream = Speed in still water + Speed of stream. - The effort remaining the same implies the speed of the man relative to the water (speed in still water) is constant.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-man-rows-at-6-km-hr-in-still-water-and-with-the-same-effort-he-rows\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CISF-AC-EXE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cisf-ac-exe\/"},{"@type":"ListItem","position":3,"name":"A man rows at 6 km\/hr in still water and with the same effort he rows"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92640","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=92640"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92640\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=92640"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=92640"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=92640"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}