{"id":92305,"date":"2025-06-01T11:20:21","date_gmt":"2025-06-01T11:20:21","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=92305"},"modified":"2025-06-01T11:20:21","modified_gmt":"2025-06-01T11:20:21","slug":"aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/","title":{"rendered":"Aneesh borrowed some money at the rate of 5% per annum for the first 3"},"content":{"rendered":"

Aneesh borrowed some money at the rate of 5% per annum for the first 3 years, 8% per annum for the next 7 years and 12% per annum for the period beyond 10 years. If the total interest paid by him at the end of 13 years is \u20b9 5,350, how much money did Aneesh borrow, if the interest is charged as simple interest?<\/p>\n

[amp_mcq option1=”\u20b9 5,000″ option2=”\u20b9 5,500″ option3=”\u20b9 5,100″ option4=”\u20b9 5,800″ correct=”option1″]<\/p>\n

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This question was previously asked in<\/div>\n
UPSC CBI DSP LDCE – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nLet the principal amount borrowed be P. The total time period is 13 years. The simple interest rate changes over periods:
\nPeriod 1: Rate (R1) = 5% p.a., Time (T1) = 3 years.
\nSimple Interest for Period 1 (SI1) = (P * R1 * T1) \/ 100 = (P * 5 * 3) \/ 100 = 15P \/ 100.
\nPeriod 2: Rate (R2) = 8% p.a., Time (T2) = next 7 years. Total time elapsed = 3 + 7 = 10 years.
\nSimple Interest for Period 2 (SI2) = (P * R2 * T2) \/ 100 = (P * 8 * 7) \/ 100 = 56P \/ 100.
\nPeriod 3: Rate (R3) = 12% p.a., Time (T3) = period beyond 10 years until 13 years. T3 = 13 – 10 = 3 years.
\nSimple Interest for Period 3 (SI3) = (P * R3 * T3) \/ 100 = (P * 12 * 3) \/ 100 = 36P \/ 100.
\nThe total interest paid is the sum of simple interests for each period.
\nTotal SI = SI1 + SI2 + SI3 = (15P \/ 100) + (56P \/ 100) + (36P \/ 100) = (15P + 56P + 36P) \/ 100 = 107P \/ 100.
\nGiven that the total interest paid is \u20b9 5,350.
\n107P \/ 100 = 5350.
\n107P = 5350 * 100.
\nP = (5350 * 100) \/ 107.
\nSince 5350 = 107 * 50, we have:
\nP = (107 * 50 * 100) \/ 107 = 50 * 100 = \u20b9 5,000.
\nThe amount borrowed was \u20b9 5,000.
\n<\/section>\n
\nIn simple interest, the interest for each period is calculated on the original principal amount. When the rate changes over different periods, the total simple interest is the sum of the interest accumulated during each period with its respective rate and duration.
\n<\/section>\n
\nThis method applies specifically to simple interest. For compound interest, the principal would change after each period as accumulated interest is added to the principal.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Aneesh borrowed some money at the rate of 5% per annum for the first 3 years, 8% per annum for the next 7 years and 12% per annum for the period beyond 10 years. If the total interest paid by him at the end of 13 years is \u20b9 5,350, how much money did Aneesh … <\/p>\n

Detailed SolutionAneesh borrowed some money at the rate of 5% per annum for the first 3<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1086],"tags":[1105,1102],"class_list":["post-92305","post","type-post","status-publish","format-standard","hentry","category-upsc-cbi-dsp-ldce","tag-1105","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nAneesh borrowed some money at the rate of 5% per annum for the first 3<\/title>\n<meta name=\"description\" content=\"Let the principal amount borrowed be P. The total time period is 13 years. The simple interest rate changes over periods: Period 1: Rate (R1) = 5% p.a., Time (T1) = 3 years. Simple Interest for Period 1 (SI1) = (P * R1 * T1) \/ 100 = (P * 5 * 3) \/ 100 = 15P \/ 100. Period 2: Rate (R2) = 8% p.a., Time (T2) = next 7 years. Total time elapsed = 3 + 7 = 10 years. Simple Interest for Period 2 (SI2) = (P * R2 * T2) \/ 100 = (P * 8 * 7) \/ 100 = 56P \/ 100. Period 3: Rate (R3) = 12% p.a., Time (T3) = period beyond 10 years until 13 years. T3 = 13 - 10 = 3 years. Simple Interest for Period 3 (SI3) = (P * R3 * T3) \/ 100 = (P * 12 * 3) \/ 100 = 36P \/ 100. The total interest paid is the sum of simple interests for each period. Total SI = SI1 + SI2 + SI3 = (15P \/ 100) + (56P \/ 100) + (36P \/ 100) = (15P + 56P + 36P) \/ 100 = 107P \/ 100. Given that the total interest paid is \u20b9 5,350. 107P \/ 100 = 5350. 107P = 5350 * 100. P = (5350 * 100) \/ 107. Since 5350 = 107 * 50, we have: P = (107 * 50 * 100) \/ 107 = 50 * 100 = \u20b9 5,000. The amount borrowed was \u20b9 5,000. In simple interest, the interest for each period is calculated on the original principal amount. When the rate changes over different periods, the total simple interest is the sum of the interest accumulated during each period with its respective rate and duration.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Aneesh borrowed some money at the rate of 5% per annum for the first 3\" \/>\n<meta property=\"og:description\" content=\"Let the principal amount borrowed be P. The total time period is 13 years. The simple interest rate changes over periods: Period 1: Rate (R1) = 5% p.a., Time (T1) = 3 years. Simple Interest for Period 1 (SI1) = (P * R1 * T1) \/ 100 = (P * 5 * 3) \/ 100 = 15P \/ 100. Period 2: Rate (R2) = 8% p.a., Time (T2) = next 7 years. Total time elapsed = 3 + 7 = 10 years. Simple Interest for Period 2 (SI2) = (P * R2 * T2) \/ 100 = (P * 8 * 7) \/ 100 = 56P \/ 100. Period 3: Rate (R3) = 12% p.a., Time (T3) = period beyond 10 years until 13 years. T3 = 13 - 10 = 3 years. Simple Interest for Period 3 (SI3) = (P * R3 * T3) \/ 100 = (P * 12 * 3) \/ 100 = 36P \/ 100. The total interest paid is the sum of simple interests for each period. Total SI = SI1 + SI2 + SI3 = (15P \/ 100) + (56P \/ 100) + (36P \/ 100) = (15P + 56P + 36P) \/ 100 = 107P \/ 100. Given that the total interest paid is \u20b9 5,350. 107P \/ 100 = 5350. 107P = 5350 * 100. P = (5350 * 100) \/ 107. Since 5350 = 107 * 50, we have: P = (107 * 50 * 100) \/ 107 = 50 * 100 = \u20b9 5,000. The amount borrowed was \u20b9 5,000. In simple interest, the interest for each period is calculated on the original principal amount. When the rate changes over different periods, the total simple interest is the sum of the interest accumulated during each period with its respective rate and duration.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T11:20:21+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Aneesh borrowed some money at the rate of 5% per annum for the first 3","description":"Let the principal amount borrowed be P. The total time period is 13 years. The simple interest rate changes over periods: Period 1: Rate (R1) = 5% p.a., Time (T1) = 3 years. Simple Interest for Period 1 (SI1) = (P * R1 * T1) \/ 100 = (P * 5 * 3) \/ 100 = 15P \/ 100. Period 2: Rate (R2) = 8% p.a., Time (T2) = next 7 years. Total time elapsed = 3 + 7 = 10 years. Simple Interest for Period 2 (SI2) = (P * R2 * T2) \/ 100 = (P * 8 * 7) \/ 100 = 56P \/ 100. Period 3: Rate (R3) = 12% p.a., Time (T3) = period beyond 10 years until 13 years. T3 = 13 - 10 = 3 years. Simple Interest for Period 3 (SI3) = (P * R3 * T3) \/ 100 = (P * 12 * 3) \/ 100 = 36P \/ 100. The total interest paid is the sum of simple interests for each period. Total SI = SI1 + SI2 + SI3 = (15P \/ 100) + (56P \/ 100) + (36P \/ 100) = (15P + 56P + 36P) \/ 100 = 107P \/ 100. Given that the total interest paid is \u20b9 5,350. 107P \/ 100 = 5350. 107P = 5350 * 100. P = (5350 * 100) \/ 107. Since 5350 = 107 * 50, we have: P = (107 * 50 * 100) \/ 107 = 50 * 100 = \u20b9 5,000. The amount borrowed was \u20b9 5,000. In simple interest, the interest for each period is calculated on the original principal amount. When the rate changes over different periods, the total simple interest is the sum of the interest accumulated during each period with its respective rate and duration.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/","og_locale":"en_US","og_type":"article","og_title":"Aneesh borrowed some money at the rate of 5% per annum for the first 3","og_description":"Let the principal amount borrowed be P. The total time period is 13 years. The simple interest rate changes over periods: Period 1: Rate (R1) = 5% p.a., Time (T1) = 3 years. Simple Interest for Period 1 (SI1) = (P * R1 * T1) \/ 100 = (P * 5 * 3) \/ 100 = 15P \/ 100. Period 2: Rate (R2) = 8% p.a., Time (T2) = next 7 years. Total time elapsed = 3 + 7 = 10 years. Simple Interest for Period 2 (SI2) = (P * R2 * T2) \/ 100 = (P * 8 * 7) \/ 100 = 56P \/ 100. Period 3: Rate (R3) = 12% p.a., Time (T3) = period beyond 10 years until 13 years. T3 = 13 - 10 = 3 years. Simple Interest for Period 3 (SI3) = (P * R3 * T3) \/ 100 = (P * 12 * 3) \/ 100 = 36P \/ 100. The total interest paid is the sum of simple interests for each period. Total SI = SI1 + SI2 + SI3 = (15P \/ 100) + (56P \/ 100) + (36P \/ 100) = (15P + 56P + 36P) \/ 100 = 107P \/ 100. Given that the total interest paid is \u20b9 5,350. 107P \/ 100 = 5350. 107P = 5350 * 100. P = (5350 * 100) \/ 107. Since 5350 = 107 * 50, we have: P = (107 * 50 * 100) \/ 107 = 50 * 100 = \u20b9 5,000. The amount borrowed was \u20b9 5,000. In simple interest, the interest for each period is calculated on the original principal amount. When the rate changes over different periods, the total simple interest is the sum of the interest accumulated during each period with its respective rate and duration.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T11:20:21+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/","url":"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/","name":"Aneesh borrowed some money at the rate of 5% per annum for the first 3","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T11:20:21+00:00","dateModified":"2025-06-01T11:20:21+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Let the principal amount borrowed be P. The total time period is 13 years. The simple interest rate changes over periods: Period 1: Rate (R1) = 5% p.a., Time (T1) = 3 years. Simple Interest for Period 1 (SI1) = (P * R1 * T1) \/ 100 = (P * 5 * 3) \/ 100 = 15P \/ 100. Period 2: Rate (R2) = 8% p.a., Time (T2) = next 7 years. Total time elapsed = 3 + 7 = 10 years. Simple Interest for Period 2 (SI2) = (P * R2 * T2) \/ 100 = (P * 8 * 7) \/ 100 = 56P \/ 100. Period 3: Rate (R3) = 12% p.a., Time (T3) = period beyond 10 years until 13 years. T3 = 13 - 10 = 3 years. Simple Interest for Period 3 (SI3) = (P * R3 * T3) \/ 100 = (P * 12 * 3) \/ 100 = 36P \/ 100. The total interest paid is the sum of simple interests for each period. Total SI = SI1 + SI2 + SI3 = (15P \/ 100) + (56P \/ 100) + (36P \/ 100) = (15P + 56P + 36P) \/ 100 = 107P \/ 100. Given that the total interest paid is \u20b9 5,350. 107P \/ 100 = 5350. 107P = 5350 * 100. P = (5350 * 100) \/ 107. Since 5350 = 107 * 50, we have: P = (107 * 50 * 100) \/ 107 = 50 * 100 = \u20b9 5,000. The amount borrowed was \u20b9 5,000. In simple interest, the interest for each period is calculated on the original principal amount. When the rate changes over different periods, the total simple interest is the sum of the interest accumulated during each period with its respective rate and duration.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/aneesh-borrowed-some-money-at-the-rate-of-5-per-annum-for-the-first-3\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CBI DSP LDCE","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-cbi-dsp-ldce\/"},{"@type":"ListItem","position":3,"name":"Aneesh borrowed some money at the rate of 5% per annum for the first 3"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92305","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=92305"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/92305\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=92305"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=92305"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=92305"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}