{"id":90977,"date":"2025-06-01T10:42:23","date_gmt":"2025-06-01T10:42:23","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90977"},"modified":"2025-06-01T10:42:23","modified_gmt":"2025-06-01T10:42:23","slug":"if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/","title":{"rendered":"If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?"},"content":{"rendered":"

If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?<\/p>\n

[amp_mcq option1=”6.33″ option2=”7.66″ option3=”9.33″ option4=”11.55″ correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CAPF – 2024<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe mean of $a$, $b$, and $c$ is approximately 7.66.
\n<\/section>\n
\nThe given equation is $19a + 19b + 19c = 437$.
\nWe can factor out the common term 19 from the left side of the equation:
\n$19(a + b + c) = 437$.
\nTo find the sum $a+b+c$, divide both sides by 19:
\n$a + b + c = \\frac{437}{19}$.
\nPerform the division:
\n$437 \\div 19$:
\n$19 \\times 2 = 38$. $43 – 38 = 5$. Bring down 7, making it 57.
\n$19 \\times 3 = 57$. $57 – 57 = 0$.
\nSo, $\\frac{437}{19} = 23$.
\nThe sum of $a$, $b$, and $c$ is $a+b+c = 23$.
\nThe mean (average) of $a$, $b$, and $c$ is defined as $\\frac{a+b+c}{3}$.
\nMean = $\\frac{23}{3}$.
\nTo express this as a decimal, divide 23 by 3:
\n$23 \\div 3 = 7$ with a remainder of 2. So, $\\frac{23}{3} = 7 \\frac{2}{3}$.
\nAs a decimal, $\\frac{2}{3} \\approx 0.666…$.
\nMean $\\approx 7.666…$.
\nLooking at the options, 7.66 is the closest approximation, likely rounded to two decimal places.
\n<\/section>\n
\nThe mean of a set of numbers is the sum of the numbers divided by the count of the numbers. In this case, the set is {a, b, c}, and there are 3 numbers. The calculation involved simple algebraic manipulation and division.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$? [amp_mcq option1=”6.33″ option2=”7.66″ option3=”9.33″ option4=”11.55″ correct=”option2″] This question was previously asked in UPSC CAPF – 2024 Download PDFAttempt Online The mean of $a$, $b$, and $c$ is approximately 7.66. The given equation is $19a + 19b + … <\/p>\n

Detailed SolutionIf $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1103,1102],"class_list":["post-90977","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1103","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nIf $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?<\/title>\n<meta name=\"description\" content=\"The mean of $a$, $b$, and $c$ is approximately 7.66. The given equation is $19a + 19b + 19c = 437$. We can factor out the common term 19 from the left side of the equation: $19(a + b + c) = 437$. To find the sum $a+b+c$, divide both sides by 19: $a + b + c = frac{437}{19}$. Perform the division: $437 div 19$: $19 times 2 = 38$. $43 - 38 = 5$. Bring down 7, making it 57. $19 times 3 = 57$. $57 - 57 = 0$. So, $frac{437}{19} = 23$. The sum of $a$, $b$, and $c$ is $a+b+c = 23$. The mean (average) of $a$, $b$, and $c$ is defined as $frac{a+b+c}{3}$. Mean = $frac{23}{3}$. To express this as a decimal, divide 23 by 3: $23 div 3 = 7$ with a remainder of 2. So, $frac{23}{3} = 7 frac{2}{3}$. As a decimal, $frac{2}{3} approx 0.666...$. Mean $approx 7.666...$. Looking at the options, 7.66 is the closest approximation, likely rounded to two decimal places.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?\" \/>\n<meta property=\"og:description\" content=\"The mean of $a$, $b$, and $c$ is approximately 7.66. The given equation is $19a + 19b + 19c = 437$. We can factor out the common term 19 from the left side of the equation: $19(a + b + c) = 437$. To find the sum $a+b+c$, divide both sides by 19: $a + b + c = frac{437}{19}$. Perform the division: $437 div 19$: $19 times 2 = 38$. $43 - 38 = 5$. Bring down 7, making it 57. $19 times 3 = 57$. $57 - 57 = 0$. So, $frac{437}{19} = 23$. The sum of $a$, $b$, and $c$ is $a+b+c = 23$. The mean (average) of $a$, $b$, and $c$ is defined as $frac{a+b+c}{3}$. Mean = $frac{23}{3}$. To express this as a decimal, divide 23 by 3: $23 div 3 = 7$ with a remainder of 2. So, $frac{23}{3} = 7 frac{2}{3}$. As a decimal, $frac{2}{3} approx 0.666...$. Mean $approx 7.666...$. Looking at the options, 7.66 is the closest approximation, likely rounded to two decimal places.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:42:23+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?","description":"The mean of $a$, $b$, and $c$ is approximately 7.66. The given equation is $19a + 19b + 19c = 437$. We can factor out the common term 19 from the left side of the equation: $19(a + b + c) = 437$. To find the sum $a+b+c$, divide both sides by 19: $a + b + c = frac{437}{19}$. Perform the division: $437 div 19$: $19 times 2 = 38$. $43 - 38 = 5$. Bring down 7, making it 57. $19 times 3 = 57$. $57 - 57 = 0$. So, $frac{437}{19} = 23$. The sum of $a$, $b$, and $c$ is $a+b+c = 23$. The mean (average) of $a$, $b$, and $c$ is defined as $frac{a+b+c}{3}$. Mean = $frac{23}{3}$. To express this as a decimal, divide 23 by 3: $23 div 3 = 7$ with a remainder of 2. So, $frac{23}{3} = 7 frac{2}{3}$. As a decimal, $frac{2}{3} approx 0.666...$. Mean $approx 7.666...$. Looking at the options, 7.66 is the closest approximation, likely rounded to two decimal places.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/","og_locale":"en_US","og_type":"article","og_title":"If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?","og_description":"The mean of $a$, $b$, and $c$ is approximately 7.66. The given equation is $19a + 19b + 19c = 437$. We can factor out the common term 19 from the left side of the equation: $19(a + b + c) = 437$. To find the sum $a+b+c$, divide both sides by 19: $a + b + c = frac{437}{19}$. Perform the division: $437 div 19$: $19 times 2 = 38$. $43 - 38 = 5$. Bring down 7, making it 57. $19 times 3 = 57$. $57 - 57 = 0$. So, $frac{437}{19} = 23$. The sum of $a$, $b$, and $c$ is $a+b+c = 23$. The mean (average) of $a$, $b$, and $c$ is defined as $frac{a+b+c}{3}$. Mean = $frac{23}{3}$. To express this as a decimal, divide 23 by 3: $23 div 3 = 7$ with a remainder of 2. So, $frac{23}{3} = 7 frac{2}{3}$. As a decimal, $frac{2}{3} approx 0.666...$. Mean $approx 7.666...$. Looking at the options, 7.66 is the closest approximation, likely rounded to two decimal places.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:42:23+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/","name":"If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:42:23+00:00","dateModified":"2025-06-01T10:42:23+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The mean of $a$, $b$, and $c$ is approximately 7.66. The given equation is $19a + 19b + 19c = 437$. We can factor out the common term 19 from the left side of the equation: $19(a + b + c) = 437$. To find the sum $a+b+c$, divide both sides by 19: $a + b + c = \\frac{437}{19}$. Perform the division: $437 \\div 19$: $19 \\times 2 = 38$. $43 - 38 = 5$. Bring down 7, making it 57. $19 \\times 3 = 57$. $57 - 57 = 0$. So, $\\frac{437}{19} = 23$. The sum of $a$, $b$, and $c$ is $a+b+c = 23$. The mean (average) of $a$, $b$, and $c$ is defined as $\\frac{a+b+c}{3}$. Mean = $\\frac{23}{3}$. To express this as a decimal, divide 23 by 3: $23 \\div 3 = 7$ with a remainder of 2. So, $\\frac{23}{3} = 7 \\frac{2}{3}$. As a decimal, $\\frac{2}{3} \\approx 0.666...$. Mean $\\approx 7.666...$. Looking at the options, 7.66 is the closest approximation, likely rounded to two decimal places.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-19a-19b-19c-437-then-what-is-the-mean-of-a-b-and-c\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"If $19a + 19b + 19c = 437$, then what is the mean of $a$, $b$ and $c$?"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90977","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=90977"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90977\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=90977"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=90977"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=90977"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}