{"id":90976,"date":"2025-06-01T10:42:21","date_gmt":"2025-06-01T10:42:21","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90976"},"modified":"2025-06-01T10:42:21","modified_gmt":"2025-06-01T10:42:21","slug":"there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/","title":{"rendered":"There was a hike in petrol price by 12%. By how much percentage should"},"content":{"rendered":"<p>There was a hike in petrol price by 12%. By how much percentage should a person decrease his petrol consumption such that there is no change in his expenditure on petrol ?<\/p>\n<p>[amp_mcq option1=&#8221;8.6%&#8221; option2=&#8221;9.8%&#8221; option3=&#8221;10.7%&#8221; option4=&#8221;12%&#8221; correct=&#8221;option3&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CAPF &#8211; 2024<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-capf-2024.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-capf-2024\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe person should decrease his petrol consumption by approximately 10.7%.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nLet the original price of petrol per unit be P and the original consumption be C units.<br \/>\nThe original expenditure on petrol = P * C.<br \/>\nThe petrol price hikes by 12%.<br \/>\nThe new price P&#8217; = P + 12% of P = P + 0.12P = 1.12P.<br \/>\nLet the new consumption be C&#8217;.<br \/>\nThe new expenditure on petrol = P&#8217; * C&#8217; = 1.12P * C&#8217;.<br \/>\nThe condition is that there is no change in expenditure.<br \/>\nOriginal expenditure = New expenditure<br \/>\nP * C = 1.12P * C&#8217;.<br \/>\nDivide both sides by P (assuming P > 0):<br \/>\nC = 1.12 * C&#8217;.<br \/>\nC&#8217; = $\\frac{C}{1.12}$.<br \/>\nThe decrease in consumption = Original Consumption &#8211; New Consumption = C &#8211; C&#8217;.<br \/>\nDecrease = $C &#8211; \\frac{C}{1.12} = C \\left(1 &#8211; \\frac{1}{1.12}\\right) = C \\left(\\frac{1.12 &#8211; 1}{1.12}\\right) = C \\left(\\frac{0.12}{1.12}\\right)$.<br \/>\nThe percentage decrease in consumption is $\\frac{\\text{Decrease in consumption}}{\\text{Original consumption}} \\times 100$.<br \/>\nPercentage decrease = $\\frac{C \\left(\\frac{0.12}{1.12}\\right)}{C} \\times 100 = \\frac{0.12}{1.12} \\times 100$.<br \/>\n$\\frac{0.12}{1.12} = \\frac{12}{112}$.<br \/>\nPercentage decrease = $\\frac{12}{112} \\times 100 = \\frac{3}{28} \\times 100 = \\frac{300}{28} = \\frac{75}{7}$.<br \/>\nNow calculate the value of $\\frac{75}{7}$ as a decimal:<br \/>\n$75 \\div 7 \\approx 10.714&#8230;$.<br \/>\nRounding to one decimal place, this is approximately 10.7%.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nIf a price increases by r%, the percentage decrease in consumption required to maintain the same expenditure is given by the formula $\\frac{r}{100+r} \\times 100$. In this case, r = 12.<br \/>\nPercentage decrease = $\\frac{12}{100+12} \\times 100 = \\frac{12}{112} \\times 100 = \\frac{3}{28} \\times 100 = \\frac{300}{28} = \\frac{75}{7}\\%$.<br \/>\nThis formula is a direct consequence of the relationship: Original Price * Original Consumption = New Price * New Consumption.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>There was a hike in petrol price by 12%. By how much percentage should a person decrease his petrol consumption such that there is no change in his expenditure on petrol ? [amp_mcq option1=&#8221;8.6%&#8221; option2=&#8221;9.8%&#8221; option3=&#8221;10.7%&#8221; option4=&#8221;12%&#8221; correct=&#8221;option3&#8243;] This question was previously asked in UPSC CAPF &#8211; 2024 Download PDFAttempt Online The person should decrease &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"There was a hike in petrol price by 12%. By how much percentage should\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/#more-90976\">Detailed Solution<span class=\"screen-reader-text\">There was a hike in petrol price by 12%. By how much percentage should<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1103,1102],"class_list":["post-90976","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1103","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>There was a hike in petrol price by 12%. By how much percentage should<\/title>\n<meta name=\"description\" content=\"The person should decrease his petrol consumption by approximately 10.7%. Let the original price of petrol per unit be P and the original consumption be C units. The original expenditure on petrol = P * C. The petrol price hikes by 12%. The new price P&#039; = P + 12% of P = P + 0.12P = 1.12P. Let the new consumption be C&#039;. The new expenditure on petrol = P&#039; * C&#039; = 1.12P * C&#039;. The condition is that there is no change in expenditure. Original expenditure = New expenditure P * C = 1.12P * C&#039;. Divide both sides by P (assuming P &gt; 0): C = 1.12 * C&#039;. C&#039; = $frac{C}{1.12}$. The decrease in consumption = Original Consumption - New Consumption = C - C&#039;. Decrease = $C - frac{C}{1.12} = C left(1 - frac{1}{1.12}right) = C left(frac{1.12 - 1}{1.12}right) = C left(frac{0.12}{1.12}right)$. The percentage decrease in consumption is $frac{text{Decrease in consumption}}{text{Original consumption}} times 100$. Percentage decrease = $frac{C left(frac{0.12}{1.12}right)}{C} times 100 = frac{0.12}{1.12} times 100$. $frac{0.12}{1.12} = frac{12}{112}$. Percentage decrease = $frac{12}{112} times 100 = frac{3}{28} times 100 = frac{300}{28} = frac{75}{7}$. Now calculate the value of $frac{75}{7}$ as a decimal: $75 div 7 approx 10.714...$. Rounding to one decimal place, this is approximately 10.7%.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"There was a hike in petrol price by 12%. By how much percentage should\" \/>\n<meta property=\"og:description\" content=\"The person should decrease his petrol consumption by approximately 10.7%. Let the original price of petrol per unit be P and the original consumption be C units. The original expenditure on petrol = P * C. The petrol price hikes by 12%. The new price P&#039; = P + 12% of P = P + 0.12P = 1.12P. Let the new consumption be C&#039;. The new expenditure on petrol = P&#039; * C&#039; = 1.12P * C&#039;. The condition is that there is no change in expenditure. Original expenditure = New expenditure P * C = 1.12P * C&#039;. Divide both sides by P (assuming P &gt; 0): C = 1.12 * C&#039;. C&#039; = $frac{C}{1.12}$. The decrease in consumption = Original Consumption - New Consumption = C - C&#039;. Decrease = $C - frac{C}{1.12} = C left(1 - frac{1}{1.12}right) = C left(frac{1.12 - 1}{1.12}right) = C left(frac{0.12}{1.12}right)$. The percentage decrease in consumption is $frac{text{Decrease in consumption}}{text{Original consumption}} times 100$. Percentage decrease = $frac{C left(frac{0.12}{1.12}right)}{C} times 100 = frac{0.12}{1.12} times 100$. $frac{0.12}{1.12} = frac{12}{112}$. Percentage decrease = $frac{12}{112} times 100 = frac{3}{28} times 100 = frac{300}{28} = frac{75}{7}$. Now calculate the value of $frac{75}{7}$ as a decimal: $75 div 7 approx 10.714...$. Rounding to one decimal place, this is approximately 10.7%.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:42:21+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"There was a hike in petrol price by 12%. By how much percentage should","description":"The person should decrease his petrol consumption by approximately 10.7%. Let the original price of petrol per unit be P and the original consumption be C units. The original expenditure on petrol = P * C. The petrol price hikes by 12%. The new price P' = P + 12% of P = P + 0.12P = 1.12P. Let the new consumption be C'. The new expenditure on petrol = P' * C' = 1.12P * C'. The condition is that there is no change in expenditure. Original expenditure = New expenditure P * C = 1.12P * C'. Divide both sides by P (assuming P > 0): C = 1.12 * C'. C' = $frac{C}{1.12}$. The decrease in consumption = Original Consumption - New Consumption = C - C'. Decrease = $C - frac{C}{1.12} = C left(1 - frac{1}{1.12}right) = C left(frac{1.12 - 1}{1.12}right) = C left(frac{0.12}{1.12}right)$. The percentage decrease in consumption is $frac{text{Decrease in consumption}}{text{Original consumption}} times 100$. Percentage decrease = $frac{C left(frac{0.12}{1.12}right)}{C} times 100 = frac{0.12}{1.12} times 100$. $frac{0.12}{1.12} = frac{12}{112}$. Percentage decrease = $frac{12}{112} times 100 = frac{3}{28} times 100 = frac{300}{28} = frac{75}{7}$. Now calculate the value of $frac{75}{7}$ as a decimal: $75 div 7 approx 10.714...$. Rounding to one decimal place, this is approximately 10.7%.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/","og_locale":"en_US","og_type":"article","og_title":"There was a hike in petrol price by 12%. By how much percentage should","og_description":"The person should decrease his petrol consumption by approximately 10.7%. Let the original price of petrol per unit be P and the original consumption be C units. The original expenditure on petrol = P * C. The petrol price hikes by 12%. The new price P' = P + 12% of P = P + 0.12P = 1.12P. Let the new consumption be C'. The new expenditure on petrol = P' * C' = 1.12P * C'. The condition is that there is no change in expenditure. Original expenditure = New expenditure P * C = 1.12P * C'. Divide both sides by P (assuming P > 0): C = 1.12 * C'. C' = $frac{C}{1.12}$. The decrease in consumption = Original Consumption - New Consumption = C - C'. Decrease = $C - frac{C}{1.12} = C left(1 - frac{1}{1.12}right) = C left(frac{1.12 - 1}{1.12}right) = C left(frac{0.12}{1.12}right)$. The percentage decrease in consumption is $frac{text{Decrease in consumption}}{text{Original consumption}} times 100$. Percentage decrease = $frac{C left(frac{0.12}{1.12}right)}{C} times 100 = frac{0.12}{1.12} times 100$. $frac{0.12}{1.12} = frac{12}{112}$. Percentage decrease = $frac{12}{112} times 100 = frac{3}{28} times 100 = frac{300}{28} = frac{75}{7}$. Now calculate the value of $frac{75}{7}$ as a decimal: $75 div 7 approx 10.714...$. Rounding to one decimal place, this is approximately 10.7%.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:42:21+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/","url":"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/","name":"There was a hike in petrol price by 12%. By how much percentage should","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:42:21+00:00","dateModified":"2025-06-01T10:42:21+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The person should decrease his petrol consumption by approximately 10.7%. Let the original price of petrol per unit be P and the original consumption be C units. The original expenditure on petrol = P * C. The petrol price hikes by 12%. The new price P' = P + 12% of P = P + 0.12P = 1.12P. Let the new consumption be C'. The new expenditure on petrol = P' * C' = 1.12P * C'. The condition is that there is no change in expenditure. Original expenditure = New expenditure P * C = 1.12P * C'. Divide both sides by P (assuming P > 0): C = 1.12 * C'. C' = $\\frac{C}{1.12}$. The decrease in consumption = Original Consumption - New Consumption = C - C'. Decrease = $C - \\frac{C}{1.12} = C \\left(1 - \\frac{1}{1.12}\\right) = C \\left(\\frac{1.12 - 1}{1.12}\\right) = C \\left(\\frac{0.12}{1.12}\\right)$. The percentage decrease in consumption is $\\frac{\\text{Decrease in consumption}}{\\text{Original consumption}} \\times 100$. Percentage decrease = $\\frac{C \\left(\\frac{0.12}{1.12}\\right)}{C} \\times 100 = \\frac{0.12}{1.12} \\times 100$. $\\frac{0.12}{1.12} = \\frac{12}{112}$. Percentage decrease = $\\frac{12}{112} \\times 100 = \\frac{3}{28} \\times 100 = \\frac{300}{28} = \\frac{75}{7}$. Now calculate the value of $\\frac{75}{7}$ as a decimal: $75 \\div 7 \\approx 10.714...$. Rounding to one decimal place, this is approximately 10.7%.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/there-was-a-hike-in-petrol-price-by-12-by-how-much-percentage-should\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"There was a hike in petrol price by 12%. By how much percentage should"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90976","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=90976"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90976\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=90976"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=90976"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=90976"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}