{"id":90972,"date":"2025-06-01T10:42:16","date_gmt":"2025-06-01T10:42:16","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90972"},"modified":"2025-06-01T10:42:16","modified_gmt":"2025-06-01T10:42:16","slug":"a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91\/","title":{"rendered":"A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91"},"content":{"rendered":"<p>A shopkeeper sold a product at 30% loss. Had his selling price been \u20b9150 more, he would have made a profit of 10%. What was the cost price ?<\/p>\n<p>[amp_mcq option1=&#8221;\u20b9375&#8243; option2=&#8221;\u20b9400&#8243; option3=&#8221;\u20b9425&#8243; option4=&#8221;\u20b9450&#8243; correct=&#8221;option1&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CAPF &#8211; 2024<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-capf-2024.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-capf-2024\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe cost price of the product was \u20b9375.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nLet CP be the cost price of the product.<br \/>\nInitially, the shopkeeper sold the product at a 30% loss.<br \/>\nSelling Price 1 (SP1) = CP &#8211; 30% of CP = CP &#8211; 0.30 * CP = 0.70 * CP.<br \/>\nIf the selling price had been \u20b9150 more, he would have made a profit of 10%.<br \/>\nSelling Price 2 (SP2) = SP1 + \u20b9150.<br \/>\nAlso, SP2 represents a 10% profit on the cost price.<br \/>\nSP2 = CP + 10% of CP = CP + 0.10 * CP = 1.10 * CP.<br \/>\nSo, we have the equation:<br \/>\n0.70 * CP + 150 = 1.10 * CP.<br \/>\nSubtract 0.70 * CP from both sides:<br \/>\n150 = 1.10 * CP &#8211; 0.70 * CP<br \/>\n150 = 0.40 * CP.<br \/>\nTo find CP, divide 150 by 0.40:<br \/>\nCP = $\\frac{150}{0.40} = \\frac{150}{\\frac{4}{10}} = \\frac{150 \\times 10}{4} = \\frac{1500}{4}$.<br \/>\nCP = 375.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nThe difference between the two selling prices (SP2 &#8211; SP1) is equal to the difference between the profit\/loss percentages applied to the cost price.<br \/>\nSP2 &#8211; SP1 = \u20b9150.<br \/>\nSP2 = CP + 10% profit = 1.10 CP.<br \/>\nSP1 = CP &#8211; 30% loss = 0.70 CP.<br \/>\nSP2 &#8211; SP1 = 1.10 CP &#8211; 0.70 CP = 0.40 CP.<br \/>\nSo, 0.40 CP = 150.<br \/>\nCP = 150 \/ 0.40 = 375.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>A shopkeeper sold a product at 30% loss. Had his selling price been \u20b9150 more, he would have made a profit of 10%. What was the cost price ? [amp_mcq option1=&#8221;\u20b9375&#8243; option2=&#8221;\u20b9400&#8243; option3=&#8221;\u20b9425&#8243; option4=&#8221;\u20b9450&#8243; correct=&#8221;option1&#8243;] This question was previously asked in UPSC CAPF &#8211; 2024 Download PDFAttempt Online The cost price of the product was &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91\/#more-90972\">Detailed Solution<span class=\"screen-reader-text\">A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1103,1102],"class_list":["post-90972","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1103","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91<\/title>\n<meta name=\"description\" content=\"The cost price of the product was \u20b9375. Let CP be the cost price of the product. Initially, the shopkeeper sold the product at a 30% loss. Selling Price 1 (SP1) = CP - 30% of CP = CP - 0.30 * CP = 0.70 * CP. If the selling price had been \u20b9150 more, he would have made a profit of 10%. Selling Price 2 (SP2) = SP1 + \u20b9150. Also, SP2 represents a 10% profit on the cost price. SP2 = CP + 10% of CP = CP + 0.10 * CP = 1.10 * CP. So, we have the equation: 0.70 * CP + 150 = 1.10 * CP. Subtract 0.70 * CP from both sides: 150 = 1.10 * CP - 0.70 * CP 150 = 0.40 * CP. To find CP, divide 150 by 0.40: CP = $frac{150}{0.40} = frac{150}{frac{4}{10}} = frac{150 times 10}{4} = frac{1500}{4}$. CP = 375.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-\u20b91\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91\" \/>\n<meta property=\"og:description\" content=\"The cost price of the product was \u20b9375. Let CP be the cost price of the product. Initially, the shopkeeper sold the product at a 30% loss. Selling Price 1 (SP1) = CP - 30% of CP = CP - 0.30 * CP = 0.70 * CP. If the selling price had been \u20b9150 more, he would have made a profit of 10%. Selling Price 2 (SP2) = SP1 + \u20b9150. Also, SP2 represents a 10% profit on the cost price. SP2 = CP + 10% of CP = CP + 0.10 * CP = 1.10 * CP. So, we have the equation: 0.70 * CP + 150 = 1.10 * CP. Subtract 0.70 * CP from both sides: 150 = 1.10 * CP - 0.70 * CP 150 = 0.40 * CP. To find CP, divide 150 by 0.40: CP = $frac{150}{0.40} = frac{150}{frac{4}{10}} = frac{150 times 10}{4} = frac{1500}{4}$. CP = 375.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-\u20b91\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:42:16+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91","description":"The cost price of the product was \u20b9375. Let CP be the cost price of the product. Initially, the shopkeeper sold the product at a 30% loss. Selling Price 1 (SP1) = CP - 30% of CP = CP - 0.30 * CP = 0.70 * CP. If the selling price had been \u20b9150 more, he would have made a profit of 10%. Selling Price 2 (SP2) = SP1 + \u20b9150. Also, SP2 represents a 10% profit on the cost price. SP2 = CP + 10% of CP = CP + 0.10 * CP = 1.10 * CP. So, we have the equation: 0.70 * CP + 150 = 1.10 * CP. Subtract 0.70 * CP from both sides: 150 = 1.10 * CP - 0.70 * CP 150 = 0.40 * CP. To find CP, divide 150 by 0.40: CP = $frac{150}{0.40} = frac{150}{frac{4}{10}} = frac{150 times 10}{4} = frac{1500}{4}$. CP = 375.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-\u20b91\/","og_locale":"en_US","og_type":"article","og_title":"A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91","og_description":"The cost price of the product was \u20b9375. Let CP be the cost price of the product. Initially, the shopkeeper sold the product at a 30% loss. Selling Price 1 (SP1) = CP - 30% of CP = CP - 0.30 * CP = 0.70 * CP. If the selling price had been \u20b9150 more, he would have made a profit of 10%. Selling Price 2 (SP2) = SP1 + \u20b9150. Also, SP2 represents a 10% profit on the cost price. SP2 = CP + 10% of CP = CP + 0.10 * CP = 1.10 * CP. So, we have the equation: 0.70 * CP + 150 = 1.10 * CP. Subtract 0.70 * CP from both sides: 150 = 1.10 * CP - 0.70 * CP 150 = 0.40 * CP. To find CP, divide 150 by 0.40: CP = $frac{150}{0.40} = frac{150}{frac{4}{10}} = frac{150 times 10}{4} = frac{1500}{4}$. CP = 375.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-\u20b91\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:42:16+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91\/","name":"A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:42:16+00:00","dateModified":"2025-06-01T10:42:16+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The cost price of the product was \u20b9375. Let CP be the cost price of the product. Initially, the shopkeeper sold the product at a 30% loss. Selling Price 1 (SP1) = CP - 30% of CP = CP - 0.30 * CP = 0.70 * CP. If the selling price had been \u20b9150 more, he would have made a profit of 10%. Selling Price 2 (SP2) = SP1 + \u20b9150. Also, SP2 represents a 10% profit on the cost price. SP2 = CP + 10% of CP = CP + 0.10 * CP = 1.10 * CP. So, we have the equation: 0.70 * CP + 150 = 1.10 * CP. Subtract 0.70 * CP from both sides: 150 = 1.10 * CP - 0.70 * CP 150 = 0.40 * CP. To find CP, divide 150 by 0.40: CP = $\\frac{150}{0.40} = \\frac{150}{\\frac{4}{10}} = \\frac{150 \\times 10}{4} = \\frac{1500}{4}$. CP = 375.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-shopkeeper-sold-a-product-at-30-loss-had-his-selling-price-been-%e2%82%b91\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"A shopkeeper sold a product at 30% loss. Had his selling price been \u20b91"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90972","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=90972"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90972\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=90972"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=90972"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=90972"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}