{"id":90881,"date":"2025-06-01T10:39:30","date_gmt":"2025-06-01T10:39:30","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90881"},"modified":"2025-06-01T10:39:30","modified_gmt":"2025-06-01T10:39:30","slug":"if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504\/","title":{"rendered":"If “O” and “U”, irrespective of upper or lower case, occur exactly 504"},"content":{"rendered":"

If “O” and “U”, irrespective of upper or lower case, occur exactly 5040 times, then how many times does the letter “E” occur in the book in the upper or the lower case?<\/p>\n

[amp_mcq option1=”11840″ option2=”11600″ option3=”11430″ option4=”11340″ correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CAPF – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is 11340. This question is known to be from a passage in the original paper that provided a rule for letter frequencies. Without the passage, the rule is not explicitly given. However, based on common interpretations and the correct answer from official sources for this specific question, the frequency of the vowel ‘E’ is approximately 9\/4 times the frequency of ‘O’ or ‘U’.
\n<\/section>\n
\nGiven that the letter “O” occurs exactly 5040 times and the letter “U” occurs exactly 5040 times, and assuming a relationship where N(E) \/ N(O) = 9\/4 (or N(E) \/ N(U) = 9\/4, which implies N(O)=N(U) as given), we can calculate the frequency of E.
\nN(E) = N(O) * (9\/4)
\nN(E) = 5040 * (9\/4)
\nN(E) = (5040 \/ 4) * 9
\nN(E) = 1260 * 9
\nN(E) = 11340.
\n<\/section>\n
\nThe exact rule linking vowel frequencies to letter properties (like position in the alphabet) that results in the 9\/4 ratio for E relative to O (or U) is not directly inferable from the question as presented. This implies the ratio was provided or derivable from the preceding passage in the original question paper. Common but unconfirmed postulations regarding the rule involve proportionality to (26 – alphabetical position) values or other complex relationships that are not straightforward.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

If “O” and “U”, irrespective of upper or lower case, occur exactly 5040 times, then how many times does the letter “E” occur in the book in the upper or the lower case? [amp_mcq option1=”11840″ option2=”11600″ option3=”11430″ option4=”11340″ correct=”option4″] This question was previously asked in UPSC CAPF – 2023 Download PDFAttempt Online The correct answer … <\/p>\n

Detailed SolutionIf “O” and “U”, irrespective of upper or lower case, occur exactly 504<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1105,1102],"class_list":["post-90881","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1105","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nIf "O" and "U", irrespective of upper or lower case, occur exactly 504<\/title>\n<meta name=\"description\" content=\"The correct answer is 11340. This question is known to be from a passage in the original paper that provided a rule for letter frequencies. Without the passage, the rule is not explicitly given. However, based on common interpretations and the correct answer from official sources for this specific question, the frequency of the vowel 'E' is approximately 9\/4 times the frequency of 'O' or 'U'. Given that the letter "O" occurs exactly 5040 times and the letter "U" occurs exactly 5040 times, and assuming a relationship where N(E) \/ N(O) = 9\/4 (or N(E) \/ N(U) = 9\/4, which implies N(O)=N(U) as given), we can calculate the frequency of E. N(E) = N(O) * (9\/4) N(E) = 5040 * (9\/4) N(E) = (5040 \/ 4) * 9 N(E) = 1260 * 9 N(E) = 11340.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If "O" and "U", irrespective of upper or lower case, occur exactly 504\" \/>\n<meta property=\"og:description\" content=\"The correct answer is 11340. This question is known to be from a passage in the original paper that provided a rule for letter frequencies. Without the passage, the rule is not explicitly given. However, based on common interpretations and the correct answer from official sources for this specific question, the frequency of the vowel 'E' is approximately 9\/4 times the frequency of 'O' or 'U'. Given that the letter "O" occurs exactly 5040 times and the letter "U" occurs exactly 5040 times, and assuming a relationship where N(E) \/ N(O) = 9\/4 (or N(E) \/ N(U) = 9\/4, which implies N(O)=N(U) as given), we can calculate the frequency of E. N(E) = N(O) * (9\/4) N(E) = 5040 * (9\/4) N(E) = (5040 \/ 4) * 9 N(E) = 1260 * 9 N(E) = 11340.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:39:30+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If \"O\" and \"U\", irrespective of upper or lower case, occur exactly 504","description":"The correct answer is 11340. This question is known to be from a passage in the original paper that provided a rule for letter frequencies. Without the passage, the rule is not explicitly given. However, based on common interpretations and the correct answer from official sources for this specific question, the frequency of the vowel 'E' is approximately 9\/4 times the frequency of 'O' or 'U'. Given that the letter \"O\" occurs exactly 5040 times and the letter \"U\" occurs exactly 5040 times, and assuming a relationship where N(E) \/ N(O) = 9\/4 (or N(E) \/ N(U) = 9\/4, which implies N(O)=N(U) as given), we can calculate the frequency of E. N(E) = N(O) * (9\/4) N(E) = 5040 * (9\/4) N(E) = (5040 \/ 4) * 9 N(E) = 1260 * 9 N(E) = 11340.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504\/","og_locale":"en_US","og_type":"article","og_title":"If \"O\" and \"U\", irrespective of upper or lower case, occur exactly 504","og_description":"The correct answer is 11340. This question is known to be from a passage in the original paper that provided a rule for letter frequencies. Without the passage, the rule is not explicitly given. However, based on common interpretations and the correct answer from official sources for this specific question, the frequency of the vowel 'E' is approximately 9\/4 times the frequency of 'O' or 'U'. Given that the letter \"O\" occurs exactly 5040 times and the letter \"U\" occurs exactly 5040 times, and assuming a relationship where N(E) \/ N(O) = 9\/4 (or N(E) \/ N(U) = 9\/4, which implies N(O)=N(U) as given), we can calculate the frequency of E. N(E) = N(O) * (9\/4) N(E) = 5040 * (9\/4) N(E) = (5040 \/ 4) * 9 N(E) = 1260 * 9 N(E) = 11340.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:39:30+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-o-and-u-irrespective-of-upper-or-lower-case-occur-exactly-504\/","name":"If \"O\" and \"U\", irrespective of upper or lower case, occur exactly 504","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:39:30+00:00","dateModified":"2025-06-01T10:39:30+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is 11340. This question is known to be from a passage in the original paper that provided a rule for letter frequencies. Without the passage, the rule is not explicitly given. However, based on common interpretations and the correct answer from official sources for this specific question, the frequency of the vowel 'E' is approximately 9\/4 times the frequency of 'O' or 'U'. Given that the letter \"O\" occurs exactly 5040 times and the letter \"U\" occurs exactly 5040 times, and assuming a relationship where N(E) \/ N(O) = 9\/4 (or N(E) \/ N(U) = 9\/4, which implies N(O)=N(U) as given), we can calculate the frequency of E. 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