{"id":90835,"date":"2025-06-01T10:38:38","date_gmt":"2025-06-01T10:38:38","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90835"},"modified":"2025-06-01T10:38:38","modified_gmt":"2025-06-01T10:38:38","slug":"a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give\/","title":{"rendered":"A sound wave of frequency of 2 kHz has a wavelength of 35 cm in a give"},"content":{"rendered":"

A sound wave of frequency of 2 kHz has a wavelength of 35 cm in a given medium. How long will it take to travel a distance of 2\u22c51 km through the medium ?<\/p>\n

[amp_mcq option1=”30 s” option2=”2\u22c51 s” option3=”3\u22c50 s” option4=”4\u22c51 s” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CAPF – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is C. We need to calculate the time taken using the relationship between speed, distance, and time, after first determining the speed of the sound wave.
\n<\/section>\n
\n– The speed of a wave ($v$) is given by the product of its frequency ($f$) and wavelength ($\\lambda$): $v = f \\times \\lambda$.
\n– Given $f = 2 \\text{ kHz} = 2000 \\text{ Hz}$ and $\\lambda = 35 \\text{ cm} = 0.35 \\text{ m}$.
\n– Speed $v = 2000 \\text{ Hz} \\times 0.35 \\text{ m} = 700 \\text{ m\/s}$.
\n– The time ($t$) taken to travel a distance ($d$) is given by $t = d \/ v$.
\n– Given $d = 2.1 \\text{ km} = 2100 \\text{ m}$.
\n– Time $t = 2100 \\text{ m} \/ 700 \\text{ m\/s} = 3 \\text{ seconds}$.
\n<\/section>\n
\nThe units were carefully converted to meters and seconds before calculation to ensure consistency in the final answer. The frequency is given in kilohertz (kHz) and the wavelength in centimeters (cm), requiring conversion to standard SI units (Hz and m). The distance is given in kilometers (km), also requiring conversion to meters.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A sound wave of frequency of 2 kHz has a wavelength of 35 cm in a given medium. How long will it take to travel a distance of 2\u22c51 km through the medium ? [amp_mcq option1=”30 s” option2=”2\u22c51 s” option3=”3\u22c50 s” option4=”4\u22c51 s” correct=”option3″] This question was previously asked in UPSC CAPF – 2023 Download … <\/p>\n

Detailed SolutionA sound wave of frequency of 2 kHz has a wavelength of 35 cm in a give<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1105,1128,1147],"class_list":["post-90835","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1105","tag-physics","tag-sound","no-featured-image-padding"],"yoast_head":"\nA sound wave of frequency of 2 kHz has a wavelength of 35 cm in a give<\/title>\n<meta name=\"description\" content=\"The correct answer is C. We need to calculate the time taken using the relationship between speed, distance, and time, after first determining the speed of the sound wave. - The speed of a wave ($v$) is given by the product of its frequency ($f$) and wavelength ($lambda$): $v = f times lambda$. - Given $f = 2 text{ kHz} = 2000 text{ Hz}$ and $lambda = 35 text{ cm} = 0.35 text{ m}$. - Speed $v = 2000 text{ Hz} times 0.35 text{ m} = 700 text{ m\/s}$. - The time ($t$) taken to travel a distance ($d$) is given by $t = d \/ v$. - Given $d = 2.1 text{ km} = 2100 text{ m}$. - Time $t = 2100 text{ m} \/ 700 text{ m\/s} = 3 text{ seconds}$.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A sound wave of frequency of 2 kHz has a wavelength of 35 cm in a give\" \/>\n<meta property=\"og:description\" content=\"The correct answer is C. We need to calculate the time taken using the relationship between speed, distance, and time, after first determining the speed of the sound wave. - The speed of a wave ($v$) is given by the product of its frequency ($f$) and wavelength ($lambda$): $v = f times lambda$. - Given $f = 2 text{ kHz} = 2000 text{ Hz}$ and $lambda = 35 text{ cm} = 0.35 text{ m}$. - Speed $v = 2000 text{ Hz} times 0.35 text{ m} = 700 text{ m\/s}$. - The time ($t$) taken to travel a distance ($d$) is given by $t = d \/ v$. - Given $d = 2.1 text{ km} = 2100 text{ m}$. - Time $t = 2100 text{ m} \/ 700 text{ m\/s} = 3 text{ seconds}$.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:38:38+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A sound wave of frequency of 2 kHz has a wavelength of 35 cm in a give","description":"The correct answer is C. We need to calculate the time taken using the relationship between speed, distance, and time, after first determining the speed of the sound wave. - The speed of a wave ($v$) is given by the product of its frequency ($f$) and wavelength ($lambda$): $v = f times lambda$. - Given $f = 2 text{ kHz} = 2000 text{ Hz}$ and $lambda = 35 text{ cm} = 0.35 text{ m}$. - Speed $v = 2000 text{ Hz} times 0.35 text{ m} = 700 text{ m\/s}$. - The time ($t$) taken to travel a distance ($d$) is given by $t = d \/ v$. - Given $d = 2.1 text{ km} = 2100 text{ m}$. - Time $t = 2100 text{ m} \/ 700 text{ m\/s} = 3 text{ seconds}$.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give\/","og_locale":"en_US","og_type":"article","og_title":"A sound wave of frequency of 2 kHz has a wavelength of 35 cm in a give","og_description":"The correct answer is C. We need to calculate the time taken using the relationship between speed, distance, and time, after first determining the speed of the sound wave. - The speed of a wave ($v$) is given by the product of its frequency ($f$) and wavelength ($lambda$): $v = f times lambda$. - Given $f = 2 text{ kHz} = 2000 text{ Hz}$ and $lambda = 35 text{ cm} = 0.35 text{ m}$. - Speed $v = 2000 text{ Hz} times 0.35 text{ m} = 700 text{ m\/s}$. - The time ($t$) taken to travel a distance ($d$) is given by $t = d \/ v$. - Given $d = 2.1 text{ km} = 2100 text{ m}$. - Time $t = 2100 text{ m} \/ 700 text{ m\/s} = 3 text{ seconds}$.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:38:38+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-sound-wave-of-frequency-of-2-khz-has-a-wavelength-of-35-cm-in-a-give\/","name":"A sound wave of frequency of 2 kHz has a wavelength of 35 cm in a give","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:38:38+00:00","dateModified":"2025-06-01T10:38:38+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is C. 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