{"id":90686,"date":"2025-06-01T10:33:40","date_gmt":"2025-06-01T10:33:40","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90686"},"modified":"2025-06-01T10:33:40","modified_gmt":"2025-06-01T10:33:40","slug":"a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/","title":{"rendered":"A runner’s average speed reduces by 25% every hour. If he runs 16 km i"},"content":{"rendered":"

A runner’s average speed reduces by 25% every hour. If he runs 16 km in the first hour and he runs for 3 hours, then what is his overall average speed?<\/p>\n

[amp_mcq option1=”12 km\/hr” option2=”12.33 km\/hr” option3=”10.33 km\/hr” option4=”13 km\/hr” correct=”option2″]<\/p>\n

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This question was previously asked in<\/div>\n
UPSC CAPF – 2022<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
The runner runs for 3 hours. In the first hour, the speed is 16 km\/hr, so the distance covered is $16 \\times 1 = 16$ km. The speed reduces by 25% every hour. Speed in the second hour = $16 \\times (1 – 0.25) = 16 \\times 0.75 = 12$ km\/hr. Distance covered in the second hour = $12 \\times 1 = 12$ km. Speed in the third hour = $12 \\times (1 – 0.25) = 12 \\times 0.75 = 9$ km\/hr. Distance covered in the third hour = $9 \\times 1 = 9$ km. The total distance covered in 3 hours is $16 + 12 + 9 = 37$ km. The total time taken is 3 hours. The overall average speed is Total Distance \/ Total Time = $\\frac{37}{3}$ km\/hr. $\\frac{37}{3} \\approx 12.333$ km\/hr.<\/section>\n
Average speed is calculated as total distance divided by total time. The speed changes each hour, so we must calculate the distance covered in each hour and sum them up.<\/section>\n
Note that average speed is not simply the average of the speeds in each hour (which would be $(16+12+9)\/3 = 37\/3 \\approx 12.33$ km\/hr in this specific case because each speed was maintained for one hour). The formula for average speed is always Total Distance \/ Total Time, which is the correct approach here.<\/section>\n","protected":false},"excerpt":{"rendered":"

A runner’s average speed reduces by 25% every hour. If he runs 16 km in the first hour and he runs for 3 hours, then what is his overall average speed? [amp_mcq option1=”12 km\/hr” option2=”12.33 km\/hr” option3=”10.33 km\/hr” option4=”13 km\/hr” correct=”option2″] This question was previously asked in UPSC CAPF – 2022 Download PDFAttempt Online The … <\/p>\n

Detailed SolutionA runner’s average speed reduces by 25% every hour. If he runs 16 km i<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1108,1102],"class_list":["post-90686","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1108","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nA runner's average speed reduces by 25% every hour. If he runs 16 km i<\/title>\n<meta name=\"description\" content=\"The runner runs for 3 hours. In the first hour, the speed is 16 km\/hr, so the distance covered is $16 times 1 = 16$ km. The speed reduces by 25% every hour. Speed in the second hour = $16 times (1 - 0.25) = 16 times 0.75 = 12$ km\/hr. Distance covered in the second hour = $12 times 1 = 12$ km. Speed in the third hour = $12 times (1 - 0.25) = 12 times 0.75 = 9$ km\/hr. Distance covered in the third hour = $9 times 1 = 9$ km. The total distance covered in 3 hours is $16 + 12 + 9 = 37$ km. The total time taken is 3 hours. The overall average speed is Total Distance \/ Total Time = $frac{37}{3}$ km\/hr. $frac{37}{3} approx 12.333$ km\/hr. Average speed is calculated as total distance divided by total time. The speed changes each hour, so we must calculate the distance covered in each hour and sum them up.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A runner's average speed reduces by 25% every hour. If he runs 16 km i\" \/>\n<meta property=\"og:description\" content=\"The runner runs for 3 hours. In the first hour, the speed is 16 km\/hr, so the distance covered is $16 times 1 = 16$ km. The speed reduces by 25% every hour. Speed in the second hour = $16 times (1 - 0.25) = 16 times 0.75 = 12$ km\/hr. Distance covered in the second hour = $12 times 1 = 12$ km. Speed in the third hour = $12 times (1 - 0.25) = 12 times 0.75 = 9$ km\/hr. Distance covered in the third hour = $9 times 1 = 9$ km. The total distance covered in 3 hours is $16 + 12 + 9 = 37$ km. The total time taken is 3 hours. The overall average speed is Total Distance \/ Total Time = $frac{37}{3}$ km\/hr. $frac{37}{3} approx 12.333$ km\/hr. Average speed is calculated as total distance divided by total time. The speed changes each hour, so we must calculate the distance covered in each hour and sum them up.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:33:40+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A runner's average speed reduces by 25% every hour. If he runs 16 km i","description":"The runner runs for 3 hours. In the first hour, the speed is 16 km\/hr, so the distance covered is $16 times 1 = 16$ km. The speed reduces by 25% every hour. Speed in the second hour = $16 times (1 - 0.25) = 16 times 0.75 = 12$ km\/hr. Distance covered in the second hour = $12 times 1 = 12$ km. Speed in the third hour = $12 times (1 - 0.25) = 12 times 0.75 = 9$ km\/hr. Distance covered in the third hour = $9 times 1 = 9$ km. The total distance covered in 3 hours is $16 + 12 + 9 = 37$ km. The total time taken is 3 hours. The overall average speed is Total Distance \/ Total Time = $frac{37}{3}$ km\/hr. $frac{37}{3} approx 12.333$ km\/hr. Average speed is calculated as total distance divided by total time. The speed changes each hour, so we must calculate the distance covered in each hour and sum them up.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/","og_locale":"en_US","og_type":"article","og_title":"A runner's average speed reduces by 25% every hour. If he runs 16 km i","og_description":"The runner runs for 3 hours. In the first hour, the speed is 16 km\/hr, so the distance covered is $16 times 1 = 16$ km. The speed reduces by 25% every hour. Speed in the second hour = $16 times (1 - 0.25) = 16 times 0.75 = 12$ km\/hr. Distance covered in the second hour = $12 times 1 = 12$ km. Speed in the third hour = $12 times (1 - 0.25) = 12 times 0.75 = 9$ km\/hr. Distance covered in the third hour = $9 times 1 = 9$ km. The total distance covered in 3 hours is $16 + 12 + 9 = 37$ km. The total time taken is 3 hours. The overall average speed is Total Distance \/ Total Time = $frac{37}{3}$ km\/hr. $frac{37}{3} approx 12.333$ km\/hr. Average speed is calculated as total distance divided by total time. The speed changes each hour, so we must calculate the distance covered in each hour and sum them up.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:33:40+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/","name":"A runner's average speed reduces by 25% every hour. If he runs 16 km i","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:33:40+00:00","dateModified":"2025-06-01T10:33:40+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The runner runs for 3 hours. In the first hour, the speed is 16 km\/hr, so the distance covered is $16 \\times 1 = 16$ km. The speed reduces by 25% every hour. Speed in the second hour = $16 \\times (1 - 0.25) = 16 \\times 0.75 = 12$ km\/hr. Distance covered in the second hour = $12 \\times 1 = 12$ km. Speed in the third hour = $12 \\times (1 - 0.25) = 12 \\times 0.75 = 9$ km\/hr. Distance covered in the third hour = $9 \\times 1 = 9$ km. The total distance covered in 3 hours is $16 + 12 + 9 = 37$ km. The total time taken is 3 hours. The overall average speed is Total Distance \/ Total Time = $\\frac{37}{3}$ km\/hr. $\\frac{37}{3} \\approx 12.333$ km\/hr. Average speed is calculated as total distance divided by total time. The speed changes each hour, so we must calculate the distance covered in each hour and sum them up.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-runners-average-speed-reduces-by-25-every-hour-if-he-runs-16-km-i\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"A runner’s average speed reduces by 25% every hour. If he runs 16 km i"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90686","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=90686"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90686\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=90686"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=90686"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=90686"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}