{"id":90636,"date":"2025-06-01T10:32:39","date_gmt":"2025-06-01T10:32:39","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90636"},"modified":"2025-06-01T10:32:39","modified_gmt":"2025-06-01T10:32:39","slug":"how-many-different-words-with-or-without-meaning-can-be-formed-by-us","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/","title":{"rendered":"How many different words, with or without meaning, can be formed by us"},"content":{"rendered":"<p>How many different words, with or without meaning, can be formed by using the letters of the word COVID?<\/p>\n<p>[amp_mcq option1=&#8221;60&#8243; option2=&#8221;150&#8243; option3=&#8221;100&#8243; option4=&#8221;120&#8243; correct=&#8221;option4&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CAPF &#8211; 2021<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-capf-2021.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-capf-2021\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe correct answer is D) 120.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nThe word COVID has 5 letters: C, O, V, I, D. All five letters are distinct. To find the number of different words that can be formed by using all the letters, we need to find the number of permutations of these 5 distinct letters. The number of permutations of &#8216;n&#8217; distinct objects is given by n!.<br \/>\nIn this case, n = 5.<br \/>\nNumber of words = 5! = 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1.<br \/>\n5! = 20 \u00d7 6 \u00d7 1 = 120.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nThis is a basic problem involving permutations. If there were repeated letters in the word, the formula would be adjusted by dividing by the factorial of the counts of repeated letters.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>How many different words, with or without meaning, can be formed by using the letters of the word COVID? [amp_mcq option1=&#8221;60&#8243; option2=&#8221;150&#8243; option3=&#8221;100&#8243; option4=&#8221;120&#8243; correct=&#8221;option4&#8243;] This question was previously asked in UPSC CAPF &#8211; 2021 Download PDFAttempt Online The correct answer is D) 120. The word COVID has 5 letters: C, O, V, I, D. &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"How many different words, with or without meaning, can be formed by us\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/#more-90636\">Detailed Solution<span class=\"screen-reader-text\">How many different words, with or without meaning, can be formed by us<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1110,1102],"class_list":["post-90636","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1110","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>How many different words, with or without meaning, can be formed by us<\/title>\n<meta name=\"description\" content=\"The correct answer is D) 120. The word COVID has 5 letters: C, O, V, I, D. All five letters are distinct. To find the number of different words that can be formed by using all the letters, we need to find the number of permutations of these 5 distinct letters. The number of permutations of &#039;n&#039; distinct objects is given by n!. In this case, n = 5. Number of words = 5! = 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1. 5! = 20 \u00d7 6 \u00d7 1 = 120.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"How many different words, with or without meaning, can be formed by us\" \/>\n<meta property=\"og:description\" content=\"The correct answer is D) 120. The word COVID has 5 letters: C, O, V, I, D. All five letters are distinct. To find the number of different words that can be formed by using all the letters, we need to find the number of permutations of these 5 distinct letters. The number of permutations of &#039;n&#039; distinct objects is given by n!. In this case, n = 5. Number of words = 5! = 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1. 5! = 20 \u00d7 6 \u00d7 1 = 120.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:32:39+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"How many different words, with or without meaning, can be formed by us","description":"The correct answer is D) 120. The word COVID has 5 letters: C, O, V, I, D. All five letters are distinct. To find the number of different words that can be formed by using all the letters, we need to find the number of permutations of these 5 distinct letters. The number of permutations of 'n' distinct objects is given by n!. In this case, n = 5. Number of words = 5! = 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1. 5! = 20 \u00d7 6 \u00d7 1 = 120.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/","og_locale":"en_US","og_type":"article","og_title":"How many different words, with or without meaning, can be formed by us","og_description":"The correct answer is D) 120. The word COVID has 5 letters: C, O, V, I, D. All five letters are distinct. To find the number of different words that can be formed by using all the letters, we need to find the number of permutations of these 5 distinct letters. The number of permutations of 'n' distinct objects is given by n!. In this case, n = 5. Number of words = 5! = 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1. 5! = 20 \u00d7 6 \u00d7 1 = 120.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:32:39+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/","url":"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/","name":"How many different words, with or without meaning, can be formed by us","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:32:39+00:00","dateModified":"2025-06-01T10:32:39+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is D) 120. The word COVID has 5 letters: C, O, V, I, D. All five letters are distinct. To find the number of different words that can be formed by using all the letters, we need to find the number of permutations of these 5 distinct letters. The number of permutations of 'n' distinct objects is given by n!. In this case, n = 5. Number of words = 5! = 5 \u00d7 4 \u00d7 3 \u00d7 2 \u00d7 1. 5! = 20 \u00d7 6 \u00d7 1 = 120.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/how-many-different-words-with-or-without-meaning-can-be-formed-by-us\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"How many different words, with or without meaning, can be formed by us"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90636","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=90636"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90636\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=90636"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=90636"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=90636"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}