{"id":90366,"date":"2025-06-01T10:27:08","date_gmt":"2025-06-01T10:27:08","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90366"},"modified":"2025-06-01T10:27:08","modified_gmt":"2025-06-01T10:27:08","slug":"a-walks-10-metres-in-front-and-10-metres-to-the-right-then-every-time","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-walks-10-metres-in-front-and-10-metres-to-the-right-then-every-time\/","title":{"rendered":"A walks 10 metres in front and 10 metres to the right. Then every time"},"content":{"rendered":"

A walks 10 metres in front and 10 metres to the right. Then every time turning to his left he walks 5, 15 and 15 metres respectively. How far is he now from his starting point ?<\/p>\n

[amp_mcq option1=”55 metres” option2=”23 metres” option3=”5 metres” option4=”None of these” correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CAPF – 2019<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe person is 5 metres away from their starting point.
\n<\/section>\n
\nThe problem can be solved by tracking the person’s displacement in two perpendicular directions (e.g., North-South and East-West).
\n<\/section>\n
\nAssume ‘front’ is North.
\n1. 10 metres in front (North): Displacement (0, +10)
\n2. 10 metres to the right (East from the North direction): Displacement (+10, 0)
\nTotal displacement so far: (+10, +10) from start. Current position is (10, 10) relative to start (0, 0). Direction is East.
\n3. Turning left (now facing North) walks 5 metres: Displacement (0, +5).
\nTotal displacement: (+10, +10) + (0, +5) = (+10, +15). Current position (10, 15). Direction is North.
\n4. Turning left (now facing West) walks 15 metres: Displacement (-15, 0).
\nTotal displacement: (+10, +15) + (-15, 0) = (-5, +15). Current position (-5, 15). Direction is West.
\n5. Turning left (now facing South) walks 15 metres: Displacement (0, -15).
\nTotal displacement: (-5, +15) + (0, -15) = (-5, 0). Current position (-5, 0).
\nThe starting point is (0, 0). The final position is (-5, 0).
\nThe distance from the starting point is the straight-line distance between (0, 0) and (-5, 0), which is 5 metres.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

A walks 10 metres in front and 10 metres to the right. Then every time turning to his left he walks 5, 15 and 15 metres respectively. How far is he now from his starting point ? [amp_mcq option1=”55 metres” option2=”23 metres” option3=”5 metres” option4=”None of these” correct=”option3″] This question was previously asked in UPSC … <\/p>\n

Detailed SolutionA walks 10 metres in front and 10 metres to the right. Then every time<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1119,1102],"class_list":["post-90366","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1119","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nA walks 10 metres in front and 10 metres to the right. Then every time<\/title>\n<meta name=\"description\" content=\"The person is 5 metres away from their starting point. 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