{"id":90236,"date":"2025-06-01T10:23:39","date_gmt":"2025-06-01T10:23:39","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90236"},"modified":"2025-06-01T10:23:39","modified_gmt":"2025-06-01T10:23:39","slug":"if-the-number-2%c2%b2-x-5%e2%81%b4-x-4%e2%81%b6-x-10%e2%81%b8-x-6%c2%b9%e2%81%b0-x-15%c2%b9%c2%b2-x-8%c2%b9%e2%81%b4-x-20%c2%b9%e2%81%b6-x-10%c2%b9%e2%81%b8-x-25","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2%c2%b2-x-5%e2%81%b4-x-4%e2%81%b6-x-10%e2%81%b8-x-6%c2%b9%e2%81%b0-x-15%c2%b9%c2%b2-x-8%c2%b9%e2%81%b4-x-20%c2%b9%e2%81%b6-x-10%c2%b9%e2%81%b8-x-25\/","title":{"rendered":"If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25"},"content":{"rendered":"

If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070 is divisible by 10\u207f, then which one of the following is the maximum value of n?<\/p>\n

[amp_mcq option1=”78″ option2=”85″ option3=”89″ option4=”98″ correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CAPF – 2018<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct answer is D) 98.
\n<\/section>\n
\nA number is divisible by 10\u207f if its prime factorization contains at least n factors of 2 and n factors of 5. The maximum value of n is determined by the minimum exponent of 2 and 5 in the prime factorization of the given number.
\nThe given number is N = 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070.
\nLet’s express all terms in terms of prime factors 2, 3, 5:
\nN = 2\u00b2 * 5\u2074 * (2\u00b2)\u2076 * (2*5)\u2078 * (2*3)\u00b9\u2070 * (3*5)\u00b9\u00b2 * (2\u00b3)\u00b9\u2074 * (2\u00b2*5)\u00b9\u2076 * (2*5)\u00b9\u2078 * (5\u00b2)\u00b2\u2070
\nN = 2\u00b2 * 5\u2074 * 2\u00b9\u00b2 * 2\u2078 * 5\u2078 * 2\u00b9\u2070 * 3\u00b9\u2070 * 3\u00b9\u00b2 * 5\u00b9\u00b2 * 2\u2074\u00b2 * 2\u00b3\u00b2 * 5\u00b9\u2076 * 2\u00b9\u2078 * 5\u00b9\u2078 * 5\u2074\u2070<\/p>\n

Total power of 2: 2 + 12 + 8 + 10 + 42 + 32 + 18 = 124. So, 2\u00b9\u00b2\u2074.
\nTotal power of 5: 4 + 8 + 12 + 16 + 18 + 40 = 98. So, 5\u2079\u2078.
\nTotal power of 3: 10 + 12 = 22. So, 3\u00b2\u00b2.<\/p>\n

The number is 2\u00b9\u00b2\u2074 * 3\u00b2\u00b2 * 5\u2079\u2078.
\nFor this number to be divisible by 10\u207f = 2\u207f * 5\u207f, the maximum possible value of n is min(124, 98) = 98.
\n<\/section>\n

\nDivisibility by 10\u207f is equivalent to divisibility by (2*5)\u207f, which means divisibility by 2\u207f and 5\u207f simultaneously. The number of trailing zeros in an integer is equal to the exponent of 10 in its prime factorization, which is the minimum of the exponents of 2 and 5.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070 is divisible by 10\u207f, then which one of the following is the maximum value of n? [amp_mcq option1=”78″ option2=”85″ option3=”89″ option4=”98″ correct=”option4″] This question was previously asked in UPSC CAPF – 2018 Download … <\/p>\n

Detailed SolutionIf the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1114,1102],"class_list":["post-90236","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1114","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"\nIf the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25<\/title>\n<meta name=\"description\" content=\"The correct answer is D) 98. A number is divisible by 10\u207f if its prime factorization contains at least n factors of 2 and n factors of 5. The maximum value of n is determined by the minimum exponent of 2 and 5 in the prime factorization of the given number. The given number is N = 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070. Let's express all terms in terms of prime factors 2, 3, 5: N = 2\u00b2 * 5\u2074 * (2\u00b2)\u2076 * (2*5)\u2078 * (2*3)\u00b9\u2070 * (3*5)\u00b9\u00b2 * (2\u00b3)\u00b9\u2074 * (2\u00b2*5)\u00b9\u2076 * (2*5)\u00b9\u2078 * (5\u00b2)\u00b2\u2070 N = 2\u00b2 * 5\u2074 * 2\u00b9\u00b2 * 2\u2078 * 5\u2078 * 2\u00b9\u2070 * 3\u00b9\u2070 * 3\u00b9\u00b2 * 5\u00b9\u00b2 * 2\u2074\u00b2 * 2\u00b3\u00b2 * 5\u00b9\u2076 * 2\u00b9\u2078 * 5\u00b9\u2078 * 5\u2074\u2070 Total power of 2: 2 + 12 + 8 + 10 + 42 + 32 + 18 = 124. So, 2\u00b9\u00b2\u2074. Total power of 5: 4 + 8 + 12 + 16 + 18 + 40 = 98. So, 5\u2079\u2078. Total power of 3: 10 + 12 = 22. So, 3\u00b2\u00b2. The number is 2\u00b9\u00b2\u2074 * 3\u00b2\u00b2 * 5\u2079\u2078. For this number to be divisible by 10\u207f = 2\u207f * 5\u207f, the maximum possible value of n is min(124, 98) = 98.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2\u00b2-x-5\u2074-x-4\u2076-x-10\u2078-x-6\u00b9\u2070-x-15\u00b9\u00b2-x-8\u00b9\u2074-x-20\u00b9\u2076-x-10\u00b9\u2078-x-25\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\" \/>\n<meta property=\"og:description\" content=\"The correct answer is D) 98. A number is divisible by 10\u207f if its prime factorization contains at least n factors of 2 and n factors of 5. The maximum value of n is determined by the minimum exponent of 2 and 5 in the prime factorization of the given number. The given number is N = 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070. Let's express all terms in terms of prime factors 2, 3, 5: N = 2\u00b2 * 5\u2074 * (2\u00b2)\u2076 * (2*5)\u2078 * (2*3)\u00b9\u2070 * (3*5)\u00b9\u00b2 * (2\u00b3)\u00b9\u2074 * (2\u00b2*5)\u00b9\u2076 * (2*5)\u00b9\u2078 * (5\u00b2)\u00b2\u2070 N = 2\u00b2 * 5\u2074 * 2\u00b9\u00b2 * 2\u2078 * 5\u2078 * 2\u00b9\u2070 * 3\u00b9\u2070 * 3\u00b9\u00b2 * 5\u00b9\u00b2 * 2\u2074\u00b2 * 2\u00b3\u00b2 * 5\u00b9\u2076 * 2\u00b9\u2078 * 5\u00b9\u2078 * 5\u2074\u2070 Total power of 2: 2 + 12 + 8 + 10 + 42 + 32 + 18 = 124. So, 2\u00b9\u00b2\u2074. Total power of 5: 4 + 8 + 12 + 16 + 18 + 40 = 98. So, 5\u2079\u2078. Total power of 3: 10 + 12 = 22. So, 3\u00b2\u00b2. The number is 2\u00b9\u00b2\u2074 * 3\u00b2\u00b2 * 5\u2079\u2078. For this number to be divisible by 10\u207f = 2\u207f * 5\u207f, the maximum possible value of n is min(124, 98) = 98.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2\u00b2-x-5\u2074-x-4\u2076-x-10\u2078-x-6\u00b9\u2070-x-15\u00b9\u00b2-x-8\u00b9\u2074-x-20\u00b9\u2076-x-10\u00b9\u2078-x-25\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:23:39+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25","description":"The correct answer is D) 98. A number is divisible by 10\u207f if its prime factorization contains at least n factors of 2 and n factors of 5. The maximum value of n is determined by the minimum exponent of 2 and 5 in the prime factorization of the given number. The given number is N = 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070. Let's express all terms in terms of prime factors 2, 3, 5: N = 2\u00b2 * 5\u2074 * (2\u00b2)\u2076 * (2*5)\u2078 * (2*3)\u00b9\u2070 * (3*5)\u00b9\u00b2 * (2\u00b3)\u00b9\u2074 * (2\u00b2*5)\u00b9\u2076 * (2*5)\u00b9\u2078 * (5\u00b2)\u00b2\u2070 N = 2\u00b2 * 5\u2074 * 2\u00b9\u00b2 * 2\u2078 * 5\u2078 * 2\u00b9\u2070 * 3\u00b9\u2070 * 3\u00b9\u00b2 * 5\u00b9\u00b2 * 2\u2074\u00b2 * 2\u00b3\u00b2 * 5\u00b9\u2076 * 2\u00b9\u2078 * 5\u00b9\u2078 * 5\u2074\u2070 Total power of 2: 2 + 12 + 8 + 10 + 42 + 32 + 18 = 124. So, 2\u00b9\u00b2\u2074. Total power of 5: 4 + 8 + 12 + 16 + 18 + 40 = 98. So, 5\u2079\u2078. Total power of 3: 10 + 12 = 22. So, 3\u00b2\u00b2. The number is 2\u00b9\u00b2\u2074 * 3\u00b2\u00b2 * 5\u2079\u2078. For this number to be divisible by 10\u207f = 2\u207f * 5\u207f, the maximum possible value of n is min(124, 98) = 98.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2\u00b2-x-5\u2074-x-4\u2076-x-10\u2078-x-6\u00b9\u2070-x-15\u00b9\u00b2-x-8\u00b9\u2074-x-20\u00b9\u2076-x-10\u00b9\u2078-x-25\/","og_locale":"en_US","og_type":"article","og_title":"If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25","og_description":"The correct answer is D) 98. A number is divisible by 10\u207f if its prime factorization contains at least n factors of 2 and n factors of 5. The maximum value of n is determined by the minimum exponent of 2 and 5 in the prime factorization of the given number. The given number is N = 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070. Let's express all terms in terms of prime factors 2, 3, 5: N = 2\u00b2 * 5\u2074 * (2\u00b2)\u2076 * (2*5)\u2078 * (2*3)\u00b9\u2070 * (3*5)\u00b9\u00b2 * (2\u00b3)\u00b9\u2074 * (2\u00b2*5)\u00b9\u2076 * (2*5)\u00b9\u2078 * (5\u00b2)\u00b2\u2070 N = 2\u00b2 * 5\u2074 * 2\u00b9\u00b2 * 2\u2078 * 5\u2078 * 2\u00b9\u2070 * 3\u00b9\u2070 * 3\u00b9\u00b2 * 5\u00b9\u00b2 * 2\u2074\u00b2 * 2\u00b3\u00b2 * 5\u00b9\u2076 * 2\u00b9\u2078 * 5\u00b9\u2078 * 5\u2074\u2070 Total power of 2: 2 + 12 + 8 + 10 + 42 + 32 + 18 = 124. So, 2\u00b9\u00b2\u2074. Total power of 5: 4 + 8 + 12 + 16 + 18 + 40 = 98. So, 5\u2079\u2078. Total power of 3: 10 + 12 = 22. So, 3\u00b2\u00b2. The number is 2\u00b9\u00b2\u2074 * 3\u00b2\u00b2 * 5\u2079\u2078. For this number to be divisible by 10\u207f = 2\u207f * 5\u207f, the maximum possible value of n is min(124, 98) = 98.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2\u00b2-x-5\u2074-x-4\u2076-x-10\u2078-x-6\u00b9\u2070-x-15\u00b9\u00b2-x-8\u00b9\u2074-x-20\u00b9\u2076-x-10\u00b9\u2078-x-25\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:23:39+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2%c2%b2-x-5%e2%81%b4-x-4%e2%81%b6-x-10%e2%81%b8-x-6%c2%b9%e2%81%b0-x-15%c2%b9%c2%b2-x-8%c2%b9%e2%81%b4-x-20%c2%b9%e2%81%b6-x-10%c2%b9%e2%81%b8-x-25\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2%c2%b2-x-5%e2%81%b4-x-4%e2%81%b6-x-10%e2%81%b8-x-6%c2%b9%e2%81%b0-x-15%c2%b9%c2%b2-x-8%c2%b9%e2%81%b4-x-20%c2%b9%e2%81%b6-x-10%c2%b9%e2%81%b8-x-25\/","name":"If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:23:39+00:00","dateModified":"2025-06-01T10:23:39+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is D) 98. A number is divisible by 10\u207f if its prime factorization contains at least n factors of 2 and n factors of 5. The maximum value of n is determined by the minimum exponent of 2 and 5 in the prime factorization of the given number. The given number is N = 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25\u00b2\u2070. Let's express all terms in terms of prime factors 2, 3, 5: N = 2\u00b2 * 5\u2074 * (2\u00b2)\u2076 * (2*5)\u2078 * (2*3)\u00b9\u2070 * (3*5)\u00b9\u00b2 * (2\u00b3)\u00b9\u2074 * (2\u00b2*5)\u00b9\u2076 * (2*5)\u00b9\u2078 * (5\u00b2)\u00b2\u2070 N = 2\u00b2 * 5\u2074 * 2\u00b9\u00b2 * 2\u2078 * 5\u2078 * 2\u00b9\u2070 * 3\u00b9\u2070 * 3\u00b9\u00b2 * 5\u00b9\u00b2 * 2\u2074\u00b2 * 2\u00b3\u00b2 * 5\u00b9\u2076 * 2\u00b9\u2078 * 5\u00b9\u2078 * 5\u2074\u2070 Total power of 2: 2 + 12 + 8 + 10 + 42 + 32 + 18 = 124. So, 2\u00b9\u00b2\u2074. Total power of 5: 4 + 8 + 12 + 16 + 18 + 40 = 98. So, 5\u2079\u2078. Total power of 3: 10 + 12 = 22. So, 3\u00b2\u00b2. The number is 2\u00b9\u00b2\u2074 * 3\u00b2\u00b2 * 5\u2079\u2078. For this number to be divisible by 10\u207f = 2\u207f * 5\u207f, the maximum possible value of n is min(124, 98) = 98.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2%c2%b2-x-5%e2%81%b4-x-4%e2%81%b6-x-10%e2%81%b8-x-6%c2%b9%e2%81%b0-x-15%c2%b9%c2%b2-x-8%c2%b9%e2%81%b4-x-20%c2%b9%e2%81%b6-x-10%c2%b9%e2%81%b8-x-25\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2%c2%b2-x-5%e2%81%b4-x-4%e2%81%b6-x-10%e2%81%b8-x-6%c2%b9%e2%81%b0-x-15%c2%b9%c2%b2-x-8%c2%b9%e2%81%b4-x-20%c2%b9%e2%81%b6-x-10%c2%b9%e2%81%b8-x-25\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-number-2%c2%b2-x-5%e2%81%b4-x-4%e2%81%b6-x-10%e2%81%b8-x-6%c2%b9%e2%81%b0-x-15%c2%b9%c2%b2-x-8%c2%b9%e2%81%b4-x-20%c2%b9%e2%81%b6-x-10%c2%b9%e2%81%b8-x-25\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"If the number 2\u00b2 x 5\u2074 x 4\u2076 x 10\u2078 x 6\u00b9\u2070 x 15\u00b9\u00b2 x 8\u00b9\u2074 x 20\u00b9\u2076 x 10\u00b9\u2078 x 25"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90236","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=90236"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90236\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=90236"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=90236"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=90236"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}