{"id":902,"date":"2024-03-05T15:07:26","date_gmt":"2024-03-05T15:07:26","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=902"},"modified":"2024-03-05T15:07:26","modified_gmt":"2024-03-05T15:07:26","slug":"a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution\/","title":{"rendered":"A distribution consists of three groups having 40, 50 and 60 item. The means of the group are 20,26 and 15 respectively, What will be the mean of the distribution ?"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a97907368fef\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    20                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    18                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"true\">\r\n                    25                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    22                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is (c) 25.<\/p>\n<p>The mean of a distribution is the sum of the values in the distribution divided by the number of values. In this case, the distribution consists of three <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> groups with 40, 50, and 60 items, respectively. The means of the groups are 20, 26, and 15, respectively. Therefore, the sum of the values in the distribution is $40 \\times 20 + 50 \\times 26 + 60 \\times 15 = 2400$. The number of values in the distribution is $40 + 50 + 60 = 150$. Therefore, the mean of the distribution is $\\frac{2400}{150} = 25$.<\/p>\n<p>Option (a) is incorrect because <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> it is the mean of the first group only. Option (b) is incorrect because it is the mean of the second group only. Option (d) is incorrect because it is the mean of the third group only.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[28],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A distribution consists of three groups having 40, 50 and 60 item. The means of the group are 20,26 and 15 respectively, What will be the mean of the distribution ?<\/title>\n<meta name=\"description\" content=\"The mean of a distribution is the sum of the values in the distribution divided by the number of values. In this case, the distribution consists of three groups with 40, 50, and 60 items, respectively. The means of the groups are 20, 26, and 15, respectively. Therefore, the sum of the values in the distribution is $40 times 20 + 50 times 26 + 60 times 15 = 2400$. The number of values in the distribution is $40 + 50 + 60 = 150$. Therefore, the mean of the distribution is $frac{2400}{150} = 25$.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A distribution consists of three groups having 40, 50 and 60 item. The means of the group are 20,26 and 15 respectively, What will be the mean of the distribution ?\" \/>\n<meta property=\"og:description\" content=\"The mean of a distribution is the sum of the values in the distribution divided by the number of values. In this case, the distribution consists of three groups with 40, 50, and 60 items, respectively. The means of the groups are 20, 26, and 15, respectively. Therefore, the sum of the values in the distribution is $40 times 20 + 50 times 26 + 60 times 15 = 2400$. The number of values in the distribution is $40 + 50 + 60 = 150$. Therefore, the mean of the distribution is $frac{2400}{150} = 25$.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2024-03-05T15:07:26+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A distribution consists of three groups having 40, 50 and 60 item. The means of the group are 20,26 and 15 respectively, What will be the mean of the distribution ?","description":"The mean of a distribution is the sum of the values in the distribution divided by the number of values. In this case, the distribution consists of three groups with 40, 50, and 60 items, respectively. The means of the groups are 20, 26, and 15, respectively. Therefore, the sum of the values in the distribution is $40 times 20 + 50 times 26 + 60 times 15 = 2400$. The number of values in the distribution is $40 + 50 + 60 = 150$. Therefore, the mean of the distribution is $frac{2400}{150} = 25$.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution\/","og_locale":"en_US","og_type":"article","og_title":"A distribution consists of three groups having 40, 50 and 60 item. The means of the group are 20,26 and 15 respectively, What will be the mean of the distribution ?","og_description":"The mean of a distribution is the sum of the values in the distribution divided by the number of values. In this case, the distribution consists of three groups with 40, 50, and 60 items, respectively. The means of the groups are 20, 26, and 15, respectively. Therefore, the sum of the values in the distribution is $40 times 20 + 50 times 26 + 60 times 15 = 2400$. The number of values in the distribution is $40 + 50 + 60 = 150$. Therefore, the mean of the distribution is $frac{2400}{150} = 25$.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2024-03-05T15:07:26+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-distribution-consists-of-three-groups-having-40-50-and-60-item-the-means-of-the-group-are-2026-and-15-respectively-what-will-be-the-mean-of-the-distribution\/","name":"A distribution consists of three groups having 40, 50 and 60 item. The means of the group are 20,26 and 15 respectively, What will be the mean of the distribution ?","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2024-03-05T15:07:26+00:00","dateModified":"2024-03-05T15:07:26+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The mean of a distribution is the sum of the values in the distribution divided by the number of values. In this case, the distribution consists of three groups with 40, 50, and 60 items, respectively. The means of the groups are 20, 26, and 15, respectively. Therefore, the sum of the values in the distribution is $40 \\times 20 + 50 \\times 26 + 60 \\times 15 = 2400$. The number of values in the distribution is $40 + 50 + 60 = 150$. 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The means of the group are 20,26 and 15 respectively, What will be the mean of the distribution ?"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/902"}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=902"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/902\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=902"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=902"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=902"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}