{"id":90007,"date":"2025-06-01T10:19:00","date_gmt":"2025-06-01T10:19:00","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=90007"},"modified":"2025-06-01T10:19:00","modified_gmt":"2025-06-01T10:19:00","slug":"let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/","title":{"rendered":"Let a resistor having 4 ohm resistance be connected across the termina"},"content":{"rendered":"

Let a resistor having 4 ohm resistance be connected across the terminals of a 12 volt battery. Then the charge in coulomb passing through the resistor per second is:<\/p>\n

[amp_mcq option1=”12″ option2=”4″ option3=”3″ option4=”0.33″ correct=”option3″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CAPF – 2016<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is C) 3.
\n<\/section>\n
\nAccording to Ohm’s Law, the current (I) flowing through a resistor is directly proportional to the voltage (V) across it and inversely proportional to its resistance (R). The relationship is given by the formula V = IR. The current (I) is also defined as the amount of electric charge (Q) passing through a point per unit time (t), i.e., I = Q\/t. The question asks for the charge passing through the resistor *per second*, which means we need to find Q when t = 1 second. From I = Q\/t, we get Q = I * t. If t = 1 second, then Q = I * 1 = I. Therefore, the charge passing through the resistor per second is equal to the current flowing through it.
\n<\/section>\n
\nGiven: Voltage (V) = 12 volts, Resistance (R) = 4 ohm.
\nUsing Ohm’s Law, I = V \/ R = 12 V \/ 4 ohm = 3 Amperes.
\nThe current is 3 Amperes, which means 3 Coulombs of charge flow through the resistor every second.
\nCharge passing per second = Current (I) = 3 Coulombs.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Let a resistor having 4 ohm resistance be connected across the terminals of a 12 volt battery. Then the charge in coulomb passing through the resistor per second is: [amp_mcq option1=”12″ option2=”4″ option3=”3″ option4=”0.33″ correct=”option3″] This question was previously asked in UPSC CAPF – 2016 Download PDFAttempt Online The correct option is C) 3. According … <\/p>\n

Detailed SolutionLet a resistor having 4 ohm resistance be connected across the termina<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1098,1201,1128],"class_list":["post-90007","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1098","tag-electric-current","tag-physics","no-featured-image-padding"],"yoast_head":"\nLet a resistor having 4 ohm resistance be connected across the termina<\/title>\n<meta name=\"description\" content=\"The correct option is C) 3. According to Ohm's Law, the current (I) flowing through a resistor is directly proportional to the voltage (V) across it and inversely proportional to its resistance (R). The relationship is given by the formula V = IR. The current (I) is also defined as the amount of electric charge (Q) passing through a point per unit time (t), i.e., I = Q\/t. The question asks for the charge passing through the resistor *per second*, which means we need to find Q when t = 1 second. From I = Q\/t, we get Q = I * t. If t = 1 second, then Q = I * 1 = I. Therefore, the charge passing through the resistor per second is equal to the current flowing through it.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Let a resistor having 4 ohm resistance be connected across the termina\" \/>\n<meta property=\"og:description\" content=\"The correct option is C) 3. According to Ohm's Law, the current (I) flowing through a resistor is directly proportional to the voltage (V) across it and inversely proportional to its resistance (R). The relationship is given by the formula V = IR. The current (I) is also defined as the amount of electric charge (Q) passing through a point per unit time (t), i.e., I = Q\/t. The question asks for the charge passing through the resistor *per second*, which means we need to find Q when t = 1 second. From I = Q\/t, we get Q = I * t. If t = 1 second, then Q = I * 1 = I. Therefore, the charge passing through the resistor per second is equal to the current flowing through it.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:19:00+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Let a resistor having 4 ohm resistance be connected across the termina","description":"The correct option is C) 3. According to Ohm's Law, the current (I) flowing through a resistor is directly proportional to the voltage (V) across it and inversely proportional to its resistance (R). The relationship is given by the formula V = IR. The current (I) is also defined as the amount of electric charge (Q) passing through a point per unit time (t), i.e., I = Q\/t. The question asks for the charge passing through the resistor *per second*, which means we need to find Q when t = 1 second. From I = Q\/t, we get Q = I * t. If t = 1 second, then Q = I * 1 = I. Therefore, the charge passing through the resistor per second is equal to the current flowing through it.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/","og_locale":"en_US","og_type":"article","og_title":"Let a resistor having 4 ohm resistance be connected across the termina","og_description":"The correct option is C) 3. According to Ohm's Law, the current (I) flowing through a resistor is directly proportional to the voltage (V) across it and inversely proportional to its resistance (R). The relationship is given by the formula V = IR. The current (I) is also defined as the amount of electric charge (Q) passing through a point per unit time (t), i.e., I = Q\/t. The question asks for the charge passing through the resistor *per second*, which means we need to find Q when t = 1 second. From I = Q\/t, we get Q = I * t. If t = 1 second, then Q = I * 1 = I. Therefore, the charge passing through the resistor per second is equal to the current flowing through it.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:19:00+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/","url":"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/","name":"Let a resistor having 4 ohm resistance be connected across the termina","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:19:00+00:00","dateModified":"2025-06-01T10:19:00+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct option is C) 3. According to Ohm's Law, the current (I) flowing through a resistor is directly proportional to the voltage (V) across it and inversely proportional to its resistance (R). The relationship is given by the formula V = IR. The current (I) is also defined as the amount of electric charge (Q) passing through a point per unit time (t), i.e., I = Q\/t. The question asks for the charge passing through the resistor *per second*, which means we need to find Q when t = 1 second. From I = Q\/t, we get Q = I * t. If t = 1 second, then Q = I * 1 = I. Therefore, the charge passing through the resistor per second is equal to the current flowing through it.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/let-a-resistor-having-4-ohm-resistance-be-connected-across-the-termina\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"Let a resistor having 4 ohm resistance be connected across the termina"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90007","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=90007"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/90007\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=90007"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=90007"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=90007"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}