{"id":89789,"date":"2025-06-01T10:12:43","date_gmt":"2025-06-01T10:12:43","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=89789"},"modified":"2025-06-01T10:12:43","modified_gmt":"2025-06-01T10:12:43","slug":"if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/","title":{"rendered":"If a scientist reads an ambient temperature 273 K in the laboratory, w"},"content":{"rendered":"<p>If a scientist reads an ambient temperature 273 K in the laboratory, what will a doctor&#8217;s thermometer read it ?<\/p>\n<p>[amp_mcq option1=&#8221;0 degree Fahrenheit&#8221; option2=&#8221;32 degrees Fahrenheit&#8221; option3=&#8221;99 degrees Fahrenheit&#8221; option4=&#8221;\u2013 100 degrees Fahrenheit&#8221; correct=&#8221;option2&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CAPF &#8211; 2014<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-capf-2014.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-capf-2014\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe correct answer is 32 degrees Fahrenheit.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nTo convert temperature from Kelvin (K) to Fahrenheit (\u00b0F), we first convert Kelvin to Celsius (\u00b0C) and then Celsius to Fahrenheit.<br \/>\nThe formula for converting Kelvin to Celsius is:<br \/>\n\u00b0C = K &#8211; 273.15<br \/>\nGiven temperature is 273 K.<br \/>\n\u00b0C = 273 &#8211; 273.15 = -0.15 \u00b0C.<br \/>\nHowever, in many contexts, 273 K is treated as approximately 0\u00b0C, especially in simplified problems like this. Let&#8217;s use 0\u00b0C.<\/p>\n<p>The formula for converting Celsius to Fahrenheit is:<br \/>\n\u00b0F = (\u00b0C \u00d7 9\/5) + 32<br \/>\nUsing \u00b0C = 0:<br \/>\n\u00b0F = (0 \u00d7 9\/5) + 32<br \/>\n\u00b0F = 0 + 32<br \/>\n\u00b0F = 32.<\/p>\n<p>So, 273 K is equivalent to 32\u00b0F. This corresponds to the freezing point of water.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nThe exact freezing point of water is 273.15 K or 0\u00b0C or 32\u00b0F. The value 273 K is a common approximation used in many problems.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>If a scientist reads an ambient temperature 273 K in the laboratory, what will a doctor&#8217;s thermometer read it ? [amp_mcq option1=&#8221;0 degree Fahrenheit&#8221; option2=&#8221;32 degrees Fahrenheit&#8221; option3=&#8221;99 degrees Fahrenheit&#8221; option4=&#8221;\u2013 100 degrees Fahrenheit&#8221; correct=&#8221;option2&#8243;] This question was previously asked in UPSC CAPF &#8211; 2014 Download PDFAttempt Online The correct answer is 32 degrees Fahrenheit. &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"If a scientist reads an ambient temperature 273 K in the laboratory, w\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/#more-89789\">Detailed Solution<span class=\"screen-reader-text\">If a scientist reads an ambient temperature 273 K in the laboratory, w<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1468,1236,1128],"class_list":["post-89789","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1468","tag-measuring-instruments-and-scales","tag-physics","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If a scientist reads an ambient temperature 273 K in the laboratory, w<\/title>\n<meta name=\"description\" content=\"The correct answer is 32 degrees Fahrenheit. To convert temperature from Kelvin (K) to Fahrenheit (\u00b0F), we first convert Kelvin to Celsius (\u00b0C) and then Celsius to Fahrenheit. The formula for converting Kelvin to Celsius is: \u00b0C = K - 273.15 Given temperature is 273 K. \u00b0C = 273 - 273.15 = -0.15 \u00b0C. However, in many contexts, 273 K is treated as approximately 0\u00b0C, especially in simplified problems like this. Let&#039;s use 0\u00b0C. The formula for converting Celsius to Fahrenheit is: \u00b0F = (\u00b0C \u00d7 9\/5) + 32 Using \u00b0C = 0: \u00b0F = (0 \u00d7 9\/5) + 32 \u00b0F = 0 + 32 \u00b0F = 32. So, 273 K is equivalent to 32\u00b0F. This corresponds to the freezing point of water.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If a scientist reads an ambient temperature 273 K in the laboratory, w\" \/>\n<meta property=\"og:description\" content=\"The correct answer is 32 degrees Fahrenheit. To convert temperature from Kelvin (K) to Fahrenheit (\u00b0F), we first convert Kelvin to Celsius (\u00b0C) and then Celsius to Fahrenheit. The formula for converting Kelvin to Celsius is: \u00b0C = K - 273.15 Given temperature is 273 K. \u00b0C = 273 - 273.15 = -0.15 \u00b0C. However, in many contexts, 273 K is treated as approximately 0\u00b0C, especially in simplified problems like this. Let&#039;s use 0\u00b0C. The formula for converting Celsius to Fahrenheit is: \u00b0F = (\u00b0C \u00d7 9\/5) + 32 Using \u00b0C = 0: \u00b0F = (0 \u00d7 9\/5) + 32 \u00b0F = 0 + 32 \u00b0F = 32. So, 273 K is equivalent to 32\u00b0F. This corresponds to the freezing point of water.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:12:43+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If a scientist reads an ambient temperature 273 K in the laboratory, w","description":"The correct answer is 32 degrees Fahrenheit. To convert temperature from Kelvin (K) to Fahrenheit (\u00b0F), we first convert Kelvin to Celsius (\u00b0C) and then Celsius to Fahrenheit. The formula for converting Kelvin to Celsius is: \u00b0C = K - 273.15 Given temperature is 273 K. \u00b0C = 273 - 273.15 = -0.15 \u00b0C. However, in many contexts, 273 K is treated as approximately 0\u00b0C, especially in simplified problems like this. Let's use 0\u00b0C. The formula for converting Celsius to Fahrenheit is: \u00b0F = (\u00b0C \u00d7 9\/5) + 32 Using \u00b0C = 0: \u00b0F = (0 \u00d7 9\/5) + 32 \u00b0F = 0 + 32 \u00b0F = 32. So, 273 K is equivalent to 32\u00b0F. This corresponds to the freezing point of water.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/","og_locale":"en_US","og_type":"article","og_title":"If a scientist reads an ambient temperature 273 K in the laboratory, w","og_description":"The correct answer is 32 degrees Fahrenheit. To convert temperature from Kelvin (K) to Fahrenheit (\u00b0F), we first convert Kelvin to Celsius (\u00b0C) and then Celsius to Fahrenheit. The formula for converting Kelvin to Celsius is: \u00b0C = K - 273.15 Given temperature is 273 K. \u00b0C = 273 - 273.15 = -0.15 \u00b0C. However, in many contexts, 273 K is treated as approximately 0\u00b0C, especially in simplified problems like this. Let's use 0\u00b0C. The formula for converting Celsius to Fahrenheit is: \u00b0F = (\u00b0C \u00d7 9\/5) + 32 Using \u00b0C = 0: \u00b0F = (0 \u00d7 9\/5) + 32 \u00b0F = 0 + 32 \u00b0F = 32. So, 273 K is equivalent to 32\u00b0F. This corresponds to the freezing point of water.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:12:43+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/","name":"If a scientist reads an ambient temperature 273 K in the laboratory, w","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:12:43+00:00","dateModified":"2025-06-01T10:12:43+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct answer is 32 degrees Fahrenheit. To convert temperature from Kelvin (K) to Fahrenheit (\u00b0F), we first convert Kelvin to Celsius (\u00b0C) and then Celsius to Fahrenheit. The formula for converting Kelvin to Celsius is: \u00b0C = K - 273.15 Given temperature is 273 K. \u00b0C = 273 - 273.15 = -0.15 \u00b0C. However, in many contexts, 273 K is treated as approximately 0\u00b0C, especially in simplified problems like this. Let's use 0\u00b0C. The formula for converting Celsius to Fahrenheit is: \u00b0F = (\u00b0C \u00d7 9\/5) + 32 Using \u00b0C = 0: \u00b0F = (0 \u00d7 9\/5) + 32 \u00b0F = 0 + 32 \u00b0F = 32. So, 273 K is equivalent to 32\u00b0F. This corresponds to the freezing point of water.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-scientist-reads-an-ambient-temperature-273-k-in-the-laboratory-w\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"If a scientist reads an ambient temperature 273 K in the laboratory, w"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89789","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=89789"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89789\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=89789"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=89789"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=89789"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}