{"id":89599,"date":"2025-06-01T10:07:53","date_gmt":"2025-06-01T10:07:53","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=89599"},"modified":"2025-06-01T10:07:53","modified_gmt":"2025-06-01T10:07:53","slug":"if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/","title":{"rendered":"If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,"},"content":{"rendered":"<p>If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples, 4 apples as much as 9 pineapples and if 3 pineapples cost \u20b9 48, what will a mango cost?<\/p>\n<p>[amp_mcq option1=&#8221;\u20b9 9&#8243; option2=&#8221;\u20b9 12&#8243; option3=&#8221;\u20b9 18&#8243; option4=&#8221;\u20b9 27&#8243; correct=&#8221;option2&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CAPF &#8211; 2013<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-capf-2013.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-capf-2013\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nLet M, O, A, and P represent the cost of one mango, orange, apple, and pineapple, respectively.<br \/>\nFrom the given information, we have the following equivalences:<br \/>\n1) 9 mangoes cost as much as 5 oranges: $9M = 5O$<br \/>\n2) 5 oranges cost as much as 4 apples: $5O = 4A$<br \/>\n3) 4 apples cost as much as 9 pineapples: $4A = 9P$<br \/>\n4) 3 pineapples cost \u20b9 48: $3P = 48$<\/p>\n<p>From (4), we can find the cost of one pineapple:<br \/>\n$P = \\frac{48}{3} = \u20b9 16$.<\/p>\n<p>Now we can use the chain of equivalences to relate the cost of a mango to the cost of a pineapple.<br \/>\nFrom (3), $4A = 9P$. Substitute the value of P:<br \/>\n$4A = 9 \\times 16 = 144$.<br \/>\nSo, the cost of 4 apples is \u20b9 144. The cost of one apple is $A = \\frac{144}{4} = \u20b9 36$.<\/p>\n<p>From (2), $5O = 4A$. Substitute the value of 4A:<br \/>\n$5O = 144$.<br \/>\nSo, the cost of 5 oranges is \u20b9 144. The cost of one orange is $O = \\frac{144}{5} = \u20b9 28.8$.<\/p>\n<p>From (1), $9M = 5O$. Substitute the value of 5O:<br \/>\n$9M = 144$.<br \/>\nSo, the cost of 9 mangoes is \u20b9 144. The cost of one mango is $M = \\frac{144}{9} = \u20b9 16$.<\/p>\n<p>The calculated cost of one mango is \u20b9 16. However, \u20b9 16 is not among the given options (A) \u20b9 9, (B) \u20b9 12, (C) \u20b9 18, (D) \u20b9 27.<br \/>\nAssuming there is a typo in the question and one of the options is correct, let&#8217;s consider the possibility that 3 pineapples cost \u20b9 36 instead of \u20b9 48.<br \/>\nIf $3P = 36$, then $P = \\frac{36}{3} = \u20b9 12$.<br \/>\nUsing the equivalences:<br \/>\n$4A = 9P = 9 \\times 12 = 108 \\implies A = \\frac{108}{4} = \u20b9 27$.<br \/>\n$5O = 4A = 108 \\implies O = \\frac{108}{5} = \u20b9 21.6$.<br \/>\n$9M = 5O = 108 \\implies M = \\frac{108}{9} = \u20b9 12$.<br \/>\nIf 3 pineapples cost \u20b9 36, then one mango costs \u20b9 12, which is Option B. This suggests a likely typo in the original question&#8217;s value for the cost of pineapples. Based on the presence of option B, it is highly probable that the intended cost of 3 pineapples was \u20b9 36.<\/p>\n<p>Alternatively, we can look at the ratios: $M\/O = 5\/9$, $O\/A = 4\/5$, $A\/P = 9\/4$.<br \/>\nThe ratio $M\/P = (M\/O) \\times (O\/A) \\times (A\/P) = (5\/9) \\times (4\/5) \\times (9\/4) = \\frac{5 \\times 4 \\times 9}{9 \\times 5 \\times 4} = 1$.<br \/>\nSo, $M\/P = 1$, which means $M = P$.<br \/>\nThe cost of 1 mango is equal to the cost of 1 pineapple.<br \/>\nFrom $3P = 48$, the cost of 1 pineapple is $P = \u20b9 16$. Thus, $M = \u20b9 16$.<br \/>\nThis confirms the result \u20b9 16 from the question as written. Since this is not an option, we rely on the likely intended question that leads to one of the options. Assuming the typo $3P = 36$, we get $P = 12$, and since $M=P$, $M=12$.<\/p>\n<p>Given that Option B is provided as a choice, the intended answer is likely \u20b9 12, based on a probable typo in the question statement regarding the cost of pineapples.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nA chain of equivalences can be used to relate the cost of one item to another. If $a$ units of X cost as much as $b$ units of Y, $c$ units of Y cost as much as $d$ units of Z, etc., then the ratio of costs can be found by multiplying the inverse ratios of quantities: $(X\/Y) \\times (Y\/Z) = (b\/a) \\times (d\/c)$.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nIn the context of competitive exams like UPSC, questions may occasionally contain typos or errors. If the derived answer based on the strict reading of the question is not among the options, one might look for a plausible typo that yields one of the options. In this case, changing \u20b9 48 to \u20b9 36 makes option B the correct answer.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples, 4 apples as much as 9 pineapples and if 3 pineapples cost \u20b9 48, what will a mango cost? [amp_mcq option1=&#8221;\u20b9 9&#8243; option2=&#8221;\u20b9 12&#8243; option3=&#8221;\u20b9 18&#8243; option4=&#8221;\u20b9 27&#8243; correct=&#8221;option2&#8243;] This question was previously asked in UPSC CAPF &#8211; 2013 &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/#more-89599\">Detailed Solution<span class=\"screen-reader-text\">If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1467,1102],"class_list":["post-89599","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1467","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,<\/title>\n<meta name=\"description\" content=\"Let M, O, A, and P represent the cost of one mango, orange, apple, and pineapple, respectively. From the given information, we have the following equivalences: 1) 9 mangoes cost as much as 5 oranges: $9M = 5O$ 2) 5 oranges cost as much as 4 apples: $5O = 4A$ 3) 4 apples cost as much as 9 pineapples: $4A = 9P$ 4) 3 pineapples cost \u20b9 48: $3P = 48$ From (4), we can find the cost of one pineapple: $P = frac{48}{3} = \u20b9 16$. Now we can use the chain of equivalences to relate the cost of a mango to the cost of a pineapple. From (3), $4A = 9P$. Substitute the value of P: $4A = 9 times 16 = 144$. So, the cost of 4 apples is \u20b9 144. The cost of one apple is $A = frac{144}{4} = \u20b9 36$. From (2), $5O = 4A$. Substitute the value of 4A: $5O = 144$. So, the cost of 5 oranges is \u20b9 144. The cost of one orange is $O = frac{144}{5} = \u20b9 28.8$. From (1), $9M = 5O$. Substitute the value of 5O: $9M = 144$. So, the cost of 9 mangoes is \u20b9 144. The cost of one mango is $M = frac{144}{9} = \u20b9 16$. The calculated cost of one mango is \u20b9 16. However, \u20b9 16 is not among the given options (A) \u20b9 9, (B) \u20b9 12, (C) \u20b9 18, (D) \u20b9 27. Assuming there is a typo in the question and one of the options is correct, let&#039;s consider the possibility that 3 pineapples cost \u20b9 36 instead of \u20b9 48. If $3P = 36$, then $P = frac{36}{3} = \u20b9 12$. Using the equivalences: $4A = 9P = 9 times 12 = 108 implies A = frac{108}{4} = \u20b9 27$. $5O = 4A = 108 implies O = frac{108}{5} = \u20b9 21.6$. $9M = 5O = 108 implies M = frac{108}{9} = \u20b9 12$. If 3 pineapples cost \u20b9 36, then one mango costs \u20b9 12, which is Option B. This suggests a likely typo in the original question&#039;s value for the cost of pineapples. Based on the presence of option B, it is highly probable that the intended cost of 3 pineapples was \u20b9 36. Alternatively, we can look at the ratios: $M\/O = 5\/9$, $O\/A = 4\/5$, $A\/P = 9\/4$. The ratio $M\/P = (M\/O) times (O\/A) times (A\/P) = (5\/9) times (4\/5) times (9\/4) = frac{5 times 4 times 9}{9 times 5 times 4} = 1$. So, $M\/P = 1$, which means $M = P$. The cost of 1 mango is equal to the cost of 1 pineapple. From $3P = 48$, the cost of 1 pineapple is $P = \u20b9 16$. Thus, $M = \u20b9 16$. This confirms the result \u20b9 16 from the question as written. Since this is not an option, we rely on the likely intended question that leads to one of the options. Assuming the typo $3P = 36$, we get $P = 12$, and since $M=P$, $M=12$. Given that Option B is provided as a choice, the intended answer is likely \u20b9 12, based on a probable typo in the question statement regarding the cost of pineapples. A chain of equivalences can be used to relate the cost of one item to another. If $a$ units of X cost as much as $b$ units of Y, $c$ units of Y cost as much as $d$ units of Z, etc., then the ratio of costs can be found by multiplying the inverse ratios of quantities: $(X\/Y) times (Y\/Z) = (b\/a) times (d\/c)$.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,\" \/>\n<meta property=\"og:description\" content=\"Let M, O, A, and P represent the cost of one mango, orange, apple, and pineapple, respectively. From the given information, we have the following equivalences: 1) 9 mangoes cost as much as 5 oranges: $9M = 5O$ 2) 5 oranges cost as much as 4 apples: $5O = 4A$ 3) 4 apples cost as much as 9 pineapples: $4A = 9P$ 4) 3 pineapples cost \u20b9 48: $3P = 48$ From (4), we can find the cost of one pineapple: $P = frac{48}{3} = \u20b9 16$. Now we can use the chain of equivalences to relate the cost of a mango to the cost of a pineapple. From (3), $4A = 9P$. Substitute the value of P: $4A = 9 times 16 = 144$. So, the cost of 4 apples is \u20b9 144. The cost of one apple is $A = frac{144}{4} = \u20b9 36$. From (2), $5O = 4A$. Substitute the value of 4A: $5O = 144$. So, the cost of 5 oranges is \u20b9 144. The cost of one orange is $O = frac{144}{5} = \u20b9 28.8$. From (1), $9M = 5O$. Substitute the value of 5O: $9M = 144$. So, the cost of 9 mangoes is \u20b9 144. The cost of one mango is $M = frac{144}{9} = \u20b9 16$. The calculated cost of one mango is \u20b9 16. However, \u20b9 16 is not among the given options (A) \u20b9 9, (B) \u20b9 12, (C) \u20b9 18, (D) \u20b9 27. Assuming there is a typo in the question and one of the options is correct, let&#039;s consider the possibility that 3 pineapples cost \u20b9 36 instead of \u20b9 48. If $3P = 36$, then $P = frac{36}{3} = \u20b9 12$. Using the equivalences: $4A = 9P = 9 times 12 = 108 implies A = frac{108}{4} = \u20b9 27$. $5O = 4A = 108 implies O = frac{108}{5} = \u20b9 21.6$. $9M = 5O = 108 implies M = frac{108}{9} = \u20b9 12$. If 3 pineapples cost \u20b9 36, then one mango costs \u20b9 12, which is Option B. This suggests a likely typo in the original question&#039;s value for the cost of pineapples. Based on the presence of option B, it is highly probable that the intended cost of 3 pineapples was \u20b9 36. Alternatively, we can look at the ratios: $M\/O = 5\/9$, $O\/A = 4\/5$, $A\/P = 9\/4$. The ratio $M\/P = (M\/O) times (O\/A) times (A\/P) = (5\/9) times (4\/5) times (9\/4) = frac{5 times 4 times 9}{9 times 5 times 4} = 1$. So, $M\/P = 1$, which means $M = P$. The cost of 1 mango is equal to the cost of 1 pineapple. From $3P = 48$, the cost of 1 pineapple is $P = \u20b9 16$. Thus, $M = \u20b9 16$. This confirms the result \u20b9 16 from the question as written. Since this is not an option, we rely on the likely intended question that leads to one of the options. Assuming the typo $3P = 36$, we get $P = 12$, and since $M=P$, $M=12$. Given that Option B is provided as a choice, the intended answer is likely \u20b9 12, based on a probable typo in the question statement regarding the cost of pineapples. A chain of equivalences can be used to relate the cost of one item to another. If $a$ units of X cost as much as $b$ units of Y, $c$ units of Y cost as much as $d$ units of Z, etc., then the ratio of costs can be found by multiplying the inverse ratios of quantities: $(X\/Y) times (Y\/Z) = (b\/a) times (d\/c)$.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T10:07:53+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutes\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,","description":"Let M, O, A, and P represent the cost of one mango, orange, apple, and pineapple, respectively. From the given information, we have the following equivalences: 1) 9 mangoes cost as much as 5 oranges: $9M = 5O$ 2) 5 oranges cost as much as 4 apples: $5O = 4A$ 3) 4 apples cost as much as 9 pineapples: $4A = 9P$ 4) 3 pineapples cost \u20b9 48: $3P = 48$ From (4), we can find the cost of one pineapple: $P = frac{48}{3} = \u20b9 16$. Now we can use the chain of equivalences to relate the cost of a mango to the cost of a pineapple. From (3), $4A = 9P$. Substitute the value of P: $4A = 9 times 16 = 144$. So, the cost of 4 apples is \u20b9 144. The cost of one apple is $A = frac{144}{4} = \u20b9 36$. From (2), $5O = 4A$. Substitute the value of 4A: $5O = 144$. So, the cost of 5 oranges is \u20b9 144. The cost of one orange is $O = frac{144}{5} = \u20b9 28.8$. From (1), $9M = 5O$. Substitute the value of 5O: $9M = 144$. So, the cost of 9 mangoes is \u20b9 144. The cost of one mango is $M = frac{144}{9} = \u20b9 16$. The calculated cost of one mango is \u20b9 16. However, \u20b9 16 is not among the given options (A) \u20b9 9, (B) \u20b9 12, (C) \u20b9 18, (D) \u20b9 27. Assuming there is a typo in the question and one of the options is correct, let's consider the possibility that 3 pineapples cost \u20b9 36 instead of \u20b9 48. If $3P = 36$, then $P = frac{36}{3} = \u20b9 12$. Using the equivalences: $4A = 9P = 9 times 12 = 108 implies A = frac{108}{4} = \u20b9 27$. $5O = 4A = 108 implies O = frac{108}{5} = \u20b9 21.6$. $9M = 5O = 108 implies M = frac{108}{9} = \u20b9 12$. If 3 pineapples cost \u20b9 36, then one mango costs \u20b9 12, which is Option B. This suggests a likely typo in the original question's value for the cost of pineapples. Based on the presence of option B, it is highly probable that the intended cost of 3 pineapples was \u20b9 36. Alternatively, we can look at the ratios: $M\/O = 5\/9$, $O\/A = 4\/5$, $A\/P = 9\/4$. The ratio $M\/P = (M\/O) times (O\/A) times (A\/P) = (5\/9) times (4\/5) times (9\/4) = frac{5 times 4 times 9}{9 times 5 times 4} = 1$. So, $M\/P = 1$, which means $M = P$. The cost of 1 mango is equal to the cost of 1 pineapple. From $3P = 48$, the cost of 1 pineapple is $P = \u20b9 16$. Thus, $M = \u20b9 16$. This confirms the result \u20b9 16 from the question as written. Since this is not an option, we rely on the likely intended question that leads to one of the options. Assuming the typo $3P = 36$, we get $P = 12$, and since $M=P$, $M=12$. Given that Option B is provided as a choice, the intended answer is likely \u20b9 12, based on a probable typo in the question statement regarding the cost of pineapples. A chain of equivalences can be used to relate the cost of one item to another. If $a$ units of X cost as much as $b$ units of Y, $c$ units of Y cost as much as $d$ units of Z, etc., then the ratio of costs can be found by multiplying the inverse ratios of quantities: $(X\/Y) times (Y\/Z) = (b\/a) times (d\/c)$.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/","og_locale":"en_US","og_type":"article","og_title":"If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,","og_description":"Let M, O, A, and P represent the cost of one mango, orange, apple, and pineapple, respectively. From the given information, we have the following equivalences: 1) 9 mangoes cost as much as 5 oranges: $9M = 5O$ 2) 5 oranges cost as much as 4 apples: $5O = 4A$ 3) 4 apples cost as much as 9 pineapples: $4A = 9P$ 4) 3 pineapples cost \u20b9 48: $3P = 48$ From (4), we can find the cost of one pineapple: $P = frac{48}{3} = \u20b9 16$. Now we can use the chain of equivalences to relate the cost of a mango to the cost of a pineapple. From (3), $4A = 9P$. Substitute the value of P: $4A = 9 times 16 = 144$. So, the cost of 4 apples is \u20b9 144. The cost of one apple is $A = frac{144}{4} = \u20b9 36$. From (2), $5O = 4A$. Substitute the value of 4A: $5O = 144$. So, the cost of 5 oranges is \u20b9 144. The cost of one orange is $O = frac{144}{5} = \u20b9 28.8$. From (1), $9M = 5O$. Substitute the value of 5O: $9M = 144$. So, the cost of 9 mangoes is \u20b9 144. The cost of one mango is $M = frac{144}{9} = \u20b9 16$. The calculated cost of one mango is \u20b9 16. However, \u20b9 16 is not among the given options (A) \u20b9 9, (B) \u20b9 12, (C) \u20b9 18, (D) \u20b9 27. Assuming there is a typo in the question and one of the options is correct, let's consider the possibility that 3 pineapples cost \u20b9 36 instead of \u20b9 48. If $3P = 36$, then $P = frac{36}{3} = \u20b9 12$. Using the equivalences: $4A = 9P = 9 times 12 = 108 implies A = frac{108}{4} = \u20b9 27$. $5O = 4A = 108 implies O = frac{108}{5} = \u20b9 21.6$. $9M = 5O = 108 implies M = frac{108}{9} = \u20b9 12$. If 3 pineapples cost \u20b9 36, then one mango costs \u20b9 12, which is Option B. This suggests a likely typo in the original question's value for the cost of pineapples. Based on the presence of option B, it is highly probable that the intended cost of 3 pineapples was \u20b9 36. Alternatively, we can look at the ratios: $M\/O = 5\/9$, $O\/A = 4\/5$, $A\/P = 9\/4$. The ratio $M\/P = (M\/O) times (O\/A) times (A\/P) = (5\/9) times (4\/5) times (9\/4) = frac{5 times 4 times 9}{9 times 5 times 4} = 1$. So, $M\/P = 1$, which means $M = P$. The cost of 1 mango is equal to the cost of 1 pineapple. From $3P = 48$, the cost of 1 pineapple is $P = \u20b9 16$. Thus, $M = \u20b9 16$. This confirms the result \u20b9 16 from the question as written. Since this is not an option, we rely on the likely intended question that leads to one of the options. Assuming the typo $3P = 36$, we get $P = 12$, and since $M=P$, $M=12$. Given that Option B is provided as a choice, the intended answer is likely \u20b9 12, based on a probable typo in the question statement regarding the cost of pineapples. A chain of equivalences can be used to relate the cost of one item to another. If $a$ units of X cost as much as $b$ units of Y, $c$ units of Y cost as much as $d$ units of Z, etc., then the ratio of costs can be found by multiplying the inverse ratios of quantities: $(X\/Y) times (Y\/Z) = (b\/a) times (d\/c)$.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T10:07:53+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"3 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/","name":"If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T10:07:53+00:00","dateModified":"2025-06-01T10:07:53+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Let M, O, A, and P represent the cost of one mango, orange, apple, and pineapple, respectively. From the given information, we have the following equivalences: 1) 9 mangoes cost as much as 5 oranges: $9M = 5O$ 2) 5 oranges cost as much as 4 apples: $5O = 4A$ 3) 4 apples cost as much as 9 pineapples: $4A = 9P$ 4) 3 pineapples cost \u20b9 48: $3P = 48$ From (4), we can find the cost of one pineapple: $P = \\frac{48}{3} = \u20b9 16$. Now we can use the chain of equivalences to relate the cost of a mango to the cost of a pineapple. From (3), $4A = 9P$. Substitute the value of P: $4A = 9 \\times 16 = 144$. So, the cost of 4 apples is \u20b9 144. The cost of one apple is $A = \\frac{144}{4} = \u20b9 36$. From (2), $5O = 4A$. Substitute the value of 4A: $5O = 144$. So, the cost of 5 oranges is \u20b9 144. The cost of one orange is $O = \\frac{144}{5} = \u20b9 28.8$. From (1), $9M = 5O$. Substitute the value of 5O: $9M = 144$. So, the cost of 9 mangoes is \u20b9 144. The cost of one mango is $M = \\frac{144}{9} = \u20b9 16$. The calculated cost of one mango is \u20b9 16. However, \u20b9 16 is not among the given options (A) \u20b9 9, (B) \u20b9 12, (C) \u20b9 18, (D) \u20b9 27. Assuming there is a typo in the question and one of the options is correct, let's consider the possibility that 3 pineapples cost \u20b9 36 instead of \u20b9 48. If $3P = 36$, then $P = \\frac{36}{3} = \u20b9 12$. Using the equivalences: $4A = 9P = 9 \\times 12 = 108 \\implies A = \\frac{108}{4} = \u20b9 27$. $5O = 4A = 108 \\implies O = \\frac{108}{5} = \u20b9 21.6$. $9M = 5O = 108 \\implies M = \\frac{108}{9} = \u20b9 12$. If 3 pineapples cost \u20b9 36, then one mango costs \u20b9 12, which is Option B. This suggests a likely typo in the original question's value for the cost of pineapples. Based on the presence of option B, it is highly probable that the intended cost of 3 pineapples was \u20b9 36. Alternatively, we can look at the ratios: $M\/O = 5\/9$, $O\/A = 4\/5$, $A\/P = 9\/4$. The ratio $M\/P = (M\/O) \\times (O\/A) \\times (A\/P) = (5\/9) \\times (4\/5) \\times (9\/4) = \\frac{5 \\times 4 \\times 9}{9 \\times 5 \\times 4} = 1$. So, $M\/P = 1$, which means $M = P$. The cost of 1 mango is equal to the cost of 1 pineapple. From $3P = 48$, the cost of 1 pineapple is $P = \u20b9 16$. Thus, $M = \u20b9 16$. This confirms the result \u20b9 16 from the question as written. Since this is not an option, we rely on the likely intended question that leads to one of the options. Assuming the typo $3P = 36$, we get $P = 12$, and since $M=P$, $M=12$. Given that Option B is provided as a choice, the intended answer is likely \u20b9 12, based on a probable typo in the question statement regarding the cost of pineapples. A chain of equivalences can be used to relate the cost of one item to another. If $a$ units of X cost as much as $b$ units of Y, $c$ units of Y cost as much as $d$ units of Z, etc., then the ratio of costs can be found by multiplying the inverse ratios of quantities: $(X\/Y) \\times (Y\/Z) = (b\/a) \\times (d\/c)$.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-9-mangoes-cost-as-much-as-5-oranges-5-oranges-as-much-as-4-apples\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"If 9 mangoes cost as much as 5 oranges, 5 oranges as much as 4 apples,"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89599","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=89599"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89599\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=89599"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=89599"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=89599"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}