{"id":89229,"date":"2025-06-01T09:59:25","date_gmt":"2025-06-01T09:59:25","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=89229"},"modified":"2025-06-01T09:59:25","modified_gmt":"2025-06-01T09:59:25","slug":"if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4\/","title":{"rendered":"If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :\n  I 2 \u2295 x = 100  II 4"},"content":{"rendered":"<p>If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :<\/p>\n<ul>\n<li>I 2 \u2295 x = 100<\/li>\n<li>II 4 \u2295 x = 145<\/li>\n<li>III 3 \u2295 x = 145<\/li>\n<li>IV 6 \u2295 x = 100<\/li>\n<\/ul>\n<p>For which of the above, is x smallest ?<\/p>\n<p>[amp_mcq option1=&#8221;I&#8221; option2=&#8221;II&#8221; option3=&#8221;III&#8221; option4=&#8221;IV&#8221; correct=&#8221;option4&#8243;]<\/p>\n<div class=\"psc-box-pyq-exam-year-detail\">\n<div class=\"pyq-exam\">\n<div class=\"psc-heading\">This question was previously asked in<\/div>\n<div class=\"psc-title line-ellipsis\">UPSC CAPF &#8211; 2009<\/div>\n<\/div>\n<div class=\"pyq-exam-psc-buttons\"><a href=\"\/pyq\/pyq-upsc-capf-2009.pdf\" target=\"_blank\" class=\"psc-pdf-button\" rel=\"noopener\">Download PDF<\/a><a href=\"\/pyq-upsc-capf-2009\" target=\"_blank\" class=\"psc-attempt-button\" rel=\"noopener\">Attempt Online<\/a><\/div>\n<\/div>\n<section id=\"pyq-correct-answer\">\nThe operation a \u2295 b is defined as a\u1d47 + b\u1d43. We need to find the value of x in each given equation and then find the smallest x.<br \/>\nI: 2 \u2295 x = 100 => 2\u02e3 + x\u00b2 = 100.<br \/>\nTesting integer values for x:<br \/>\nIf x=1, 2\u00b9 + 1\u00b2 = 2 + 1 = 3<br \/>\nIf x=2, 2\u00b2 + 2\u00b2 = 4 + 4 = 8<br \/>\nIf x=3, 2\u00b3 + 3\u00b2 = 8 + 9 = 17<br \/>\nIf x=4, 2\u2074 + 4\u00b2 = 16 + 16 = 32<br \/>\nIf x=5, 2\u2075 + 5\u00b2 = 32 + 25 = 57<br \/>\nIf x=6, 2\u2076 + 6\u00b2 = 64 + 36 = 100. So, x = 6 for I.<\/p>\n<p>II: 4 \u2295 x = 145 => 4\u02e3 + x\u2074 = 145.<br \/>\nTesting integer values for x:<br \/>\nIf x=1, 4\u00b9 + 1\u2074 = 4 + 1 = 5<br \/>\nIf x=2, 4\u00b2 + 2\u2074 = 16 + 16 = 32<br \/>\nIf x=3, 4\u00b3 + 3\u2074 = 64 + 81 = 145. So, x = 3 for II.<\/p>\n<p>III: 3 \u2295 x = 145 => 3\u02e3 + x\u00b3 = 145.<br \/>\nTesting integer values for x:<br \/>\nIf x=1, 3\u00b9 + 1\u00b3 = 3 + 1 = 4<br \/>\nIf x=2, 3\u00b2 + 2\u00b3 = 9 + 8 = 17<br \/>\nIf x=3, 3\u00b3 + 3\u00b3 = 27 + 27 = 54<br \/>\nIf x=4, 3\u2074 + 4\u00b3 = 81 + 64 = 145. So, x = 4 for III.<\/p>\n<p>IV: 6 \u2295 x = 100 => 6\u02e3 + x\u2076 = 100.<br \/>\nTesting integer values for x:<br \/>\nIf x=1, 6\u00b9 + 1\u2076 = 6 + 1 = 7<br \/>\nIf x=2, 6\u00b2 + 2\u2076 = 36 + 64 = 100. So, x = 2 for IV.<\/p>\n<p>The values of x are 6 (for I), 3 (for II), 4 (for III), and 2 (for IV). The smallest value of x is 2, which occurs in case IV.<br \/>\n<\/section>\n<section id=\"pyq-key-points\">\nThe problem requires evaluating a custom-defined binary operation and solving equations involving it by testing values, likely integers or simple fractions, as the structure of the equations (exponential and polynomial terms) makes analytical solutions difficult.<br \/>\n<\/section>\n<section id=\"pyq-additional-information\">\nFor these types of equations (mixtures of exponential and polynomial terms), finding exact solutions analytically is generally not possible. Integer solutions can often be found by inspection or testing small values, which is common in competitive exams like UPSC CSAT.<br \/>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider : I 2 \u2295 x = 100 II 4 \u2295 x = 145 III 3 \u2295 x = 145 IV 6 \u2295 x = 100 For which of the above, is x smallest ? [amp_mcq option1=&#8221;I&#8221; option2=&#8221;II&#8221; option3=&#8221;III&#8221; option4=&#8221;IV&#8221; correct=&#8221;option4&#8243;] This question was &#8230; <\/p>\n<p class=\"read-more-container\"><a title=\"If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :\n  I 2 \u2295 x = 100  II 4\" class=\"read-more button\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4\/#more-89229\">Detailed Solution<span class=\"screen-reader-text\">If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :<br \/>\n  I 2 \u2295 x = 100  II 4<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1462,1102],"class_list":["post-89229","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1462","tag-quantitative-aptitude-and-reasoning","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :  I 2 \u2295 x = 100 II 4<\/title>\n<meta name=\"description\" content=\"The operation a \u2295 b is defined as a\u1d47 + b\u1d43. We need to find the value of x in each given equation and then find the smallest x. I: 2 \u2295 x = 100 =&gt; 2\u02e3 + x\u00b2 = 100. Testing integer values for x: If x=1, 2\u00b9 + 1\u00b2 = 2 + 1 = 3 If x=2, 2\u00b2 + 2\u00b2 = 4 + 4 = 8 If x=3, 2\u00b3 + 3\u00b2 = 8 + 9 = 17 If x=4, 2\u2074 + 4\u00b2 = 16 + 16 = 32 If x=5, 2\u2075 + 5\u00b2 = 32 + 25 = 57 If x=6, 2\u2076 + 6\u00b2 = 64 + 36 = 100. So, x = 6 for I. II: 4 \u2295 x = 145 =&gt; 4\u02e3 + x\u2074 = 145. Testing integer values for x: If x=1, 4\u00b9 + 1\u2074 = 4 + 1 = 5 If x=2, 4\u00b2 + 2\u2074 = 16 + 16 = 32 If x=3, 4\u00b3 + 3\u2074 = 64 + 81 = 145. So, x = 3 for II. III: 3 \u2295 x = 145 =&gt; 3\u02e3 + x\u00b3 = 145. Testing integer values for x: If x=1, 3\u00b9 + 1\u00b3 = 3 + 1 = 4 If x=2, 3\u00b2 + 2\u00b3 = 9 + 8 = 17 If x=3, 3\u00b3 + 3\u00b3 = 27 + 27 = 54 If x=4, 3\u2074 + 4\u00b3 = 81 + 64 = 145. So, x = 4 for III. IV: 6 \u2295 x = 100 =&gt; 6\u02e3 + x\u2076 = 100. Testing integer values for x: If x=1, 6\u00b9 + 1\u2076 = 6 + 1 = 7 If x=2, 6\u00b2 + 2\u2076 = 36 + 64 = 100. So, x = 2 for IV. The values of x are 6 (for I), 3 (for II), 4 (for III), and 2 (for IV). The smallest value of x is 2, which occurs in case IV. The problem requires evaluating a custom-defined binary operation and solving equations involving it by testing values, likely integers or simple fractions, as the structure of the equations (exponential and polynomial terms) makes analytical solutions difficult.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-\u2295-b-is-defined-as-a\u1d47-b\u1d43-then-consider-i-2-\u2295-x-100-ii-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :  I 2 \u2295 x = 100 II 4\" \/>\n<meta property=\"og:description\" content=\"The operation a \u2295 b is defined as a\u1d47 + b\u1d43. We need to find the value of x in each given equation and then find the smallest x. I: 2 \u2295 x = 100 =&gt; 2\u02e3 + x\u00b2 = 100. Testing integer values for x: If x=1, 2\u00b9 + 1\u00b2 = 2 + 1 = 3 If x=2, 2\u00b2 + 2\u00b2 = 4 + 4 = 8 If x=3, 2\u00b3 + 3\u00b2 = 8 + 9 = 17 If x=4, 2\u2074 + 4\u00b2 = 16 + 16 = 32 If x=5, 2\u2075 + 5\u00b2 = 32 + 25 = 57 If x=6, 2\u2076 + 6\u00b2 = 64 + 36 = 100. So, x = 6 for I. II: 4 \u2295 x = 145 =&gt; 4\u02e3 + x\u2074 = 145. Testing integer values for x: If x=1, 4\u00b9 + 1\u2074 = 4 + 1 = 5 If x=2, 4\u00b2 + 2\u2074 = 16 + 16 = 32 If x=3, 4\u00b3 + 3\u2074 = 64 + 81 = 145. So, x = 3 for II. III: 3 \u2295 x = 145 =&gt; 3\u02e3 + x\u00b3 = 145. Testing integer values for x: If x=1, 3\u00b9 + 1\u00b3 = 3 + 1 = 4 If x=2, 3\u00b2 + 2\u00b3 = 9 + 8 = 17 If x=3, 3\u00b3 + 3\u00b3 = 27 + 27 = 54 If x=4, 3\u2074 + 4\u00b3 = 81 + 64 = 145. So, x = 4 for III. IV: 6 \u2295 x = 100 =&gt; 6\u02e3 + x\u2076 = 100. Testing integer values for x: If x=1, 6\u00b9 + 1\u2076 = 6 + 1 = 7 If x=2, 6\u00b2 + 2\u2076 = 36 + 64 = 100. So, x = 2 for IV. The values of x are 6 (for I), 3 (for II), 4 (for III), and 2 (for IV). The smallest value of x is 2, which occurs in case IV. The problem requires evaluating a custom-defined binary operation and solving equations involving it by testing values, likely integers or simple fractions, as the structure of the equations (exponential and polynomial terms) makes analytical solutions difficult.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-a-\u2295-b-is-defined-as-a\u1d47-b\u1d43-then-consider-i-2-\u2295-x-100-ii-4\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T09:59:25+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :  I 2 \u2295 x = 100 II 4","description":"The operation a \u2295 b is defined as a\u1d47 + b\u1d43. We need to find the value of x in each given equation and then find the smallest x. I: 2 \u2295 x = 100 => 2\u02e3 + x\u00b2 = 100. Testing integer values for x: If x=1, 2\u00b9 + 1\u00b2 = 2 + 1 = 3 If x=2, 2\u00b2 + 2\u00b2 = 4 + 4 = 8 If x=3, 2\u00b3 + 3\u00b2 = 8 + 9 = 17 If x=4, 2\u2074 + 4\u00b2 = 16 + 16 = 32 If x=5, 2\u2075 + 5\u00b2 = 32 + 25 = 57 If x=6, 2\u2076 + 6\u00b2 = 64 + 36 = 100. So, x = 6 for I. II: 4 \u2295 x = 145 => 4\u02e3 + x\u2074 = 145. Testing integer values for x: If x=1, 4\u00b9 + 1\u2074 = 4 + 1 = 5 If x=2, 4\u00b2 + 2\u2074 = 16 + 16 = 32 If x=3, 4\u00b3 + 3\u2074 = 64 + 81 = 145. So, x = 3 for II. III: 3 \u2295 x = 145 => 3\u02e3 + x\u00b3 = 145. Testing integer values for x: If x=1, 3\u00b9 + 1\u00b3 = 3 + 1 = 4 If x=2, 3\u00b2 + 2\u00b3 = 9 + 8 = 17 If x=3, 3\u00b3 + 3\u00b3 = 27 + 27 = 54 If x=4, 3\u2074 + 4\u00b3 = 81 + 64 = 145. So, x = 4 for III. IV: 6 \u2295 x = 100 => 6\u02e3 + x\u2076 = 100. Testing integer values for x: If x=1, 6\u00b9 + 1\u2076 = 6 + 1 = 7 If x=2, 6\u00b2 + 2\u2076 = 36 + 64 = 100. So, x = 2 for IV. The values of x are 6 (for I), 3 (for II), 4 (for III), and 2 (for IV). The smallest value of x is 2, which occurs in case IV. The problem requires evaluating a custom-defined binary operation and solving equations involving it by testing values, likely integers or simple fractions, as the structure of the equations (exponential and polynomial terms) makes analytical solutions difficult.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-a-\u2295-b-is-defined-as-a\u1d47-b\u1d43-then-consider-i-2-\u2295-x-100-ii-4\/","og_locale":"en_US","og_type":"article","og_title":"If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider :  I 2 \u2295 x = 100 II 4","og_description":"The operation a \u2295 b is defined as a\u1d47 + b\u1d43. We need to find the value of x in each given equation and then find the smallest x. I: 2 \u2295 x = 100 => 2\u02e3 + x\u00b2 = 100. Testing integer values for x: If x=1, 2\u00b9 + 1\u00b2 = 2 + 1 = 3 If x=2, 2\u00b2 + 2\u00b2 = 4 + 4 = 8 If x=3, 2\u00b3 + 3\u00b2 = 8 + 9 = 17 If x=4, 2\u2074 + 4\u00b2 = 16 + 16 = 32 If x=5, 2\u2075 + 5\u00b2 = 32 + 25 = 57 If x=6, 2\u2076 + 6\u00b2 = 64 + 36 = 100. So, x = 6 for I. II: 4 \u2295 x = 145 => 4\u02e3 + x\u2074 = 145. Testing integer values for x: If x=1, 4\u00b9 + 1\u2074 = 4 + 1 = 5 If x=2, 4\u00b2 + 2\u2074 = 16 + 16 = 32 If x=3, 4\u00b3 + 3\u2074 = 64 + 81 = 145. So, x = 3 for II. III: 3 \u2295 x = 145 => 3\u02e3 + x\u00b3 = 145. Testing integer values for x: If x=1, 3\u00b9 + 1\u00b3 = 3 + 1 = 4 If x=2, 3\u00b2 + 2\u00b3 = 9 + 8 = 17 If x=3, 3\u00b3 + 3\u00b3 = 27 + 27 = 54 If x=4, 3\u2074 + 4\u00b3 = 81 + 64 = 145. So, x = 4 for III. IV: 6 \u2295 x = 100 => 6\u02e3 + x\u2076 = 100. Testing integer values for x: If x=1, 6\u00b9 + 1\u2076 = 6 + 1 = 7 If x=2, 6\u00b2 + 2\u2076 = 36 + 64 = 100. So, x = 2 for IV. The values of x are 6 (for I), 3 (for II), 4 (for III), and 2 (for IV). The smallest value of x is 2, which occurs in case IV. The problem requires evaluating a custom-defined binary operation and solving equations involving it by testing values, likely integers or simple fractions, as the structure of the equations (exponential and polynomial terms) makes analytical solutions difficult.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-a-\u2295-b-is-defined-as-a\u1d47-b\u1d43-then-consider-i-2-\u2295-x-100-ii-4\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T09:59:25+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4\/","name":"If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider : I 2 \u2295 x = 100 II 4","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T09:59:25+00:00","dateModified":"2025-06-01T09:59:25+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The operation a \u2295 b is defined as a\u1d47 + b\u1d43. We need to find the value of x in each given equation and then find the smallest x. I: 2 \u2295 x = 100 => 2\u02e3 + x\u00b2 = 100. Testing integer values for x: If x=1, 2\u00b9 + 1\u00b2 = 2 + 1 = 3 If x=2, 2\u00b2 + 2\u00b2 = 4 + 4 = 8 If x=3, 2\u00b3 + 3\u00b2 = 8 + 9 = 17 If x=4, 2\u2074 + 4\u00b2 = 16 + 16 = 32 If x=5, 2\u2075 + 5\u00b2 = 32 + 25 = 57 If x=6, 2\u2076 + 6\u00b2 = 64 + 36 = 100. So, x = 6 for I. II: 4 \u2295 x = 145 => 4\u02e3 + x\u2074 = 145. Testing integer values for x: If x=1, 4\u00b9 + 1\u2074 = 4 + 1 = 5 If x=2, 4\u00b2 + 2\u2074 = 16 + 16 = 32 If x=3, 4\u00b3 + 3\u2074 = 64 + 81 = 145. So, x = 3 for II. III: 3 \u2295 x = 145 => 3\u02e3 + x\u00b3 = 145. Testing integer values for x: If x=1, 3\u00b9 + 1\u00b3 = 3 + 1 = 4 If x=2, 3\u00b2 + 2\u00b3 = 9 + 8 = 17 If x=3, 3\u00b3 + 3\u00b3 = 27 + 27 = 54 If x=4, 3\u2074 + 4\u00b3 = 81 + 64 = 145. So, x = 4 for III. IV: 6 \u2295 x = 100 => 6\u02e3 + x\u2076 = 100. Testing integer values for x: If x=1, 6\u00b9 + 1\u2076 = 6 + 1 = 7 If x=2, 6\u00b2 + 2\u2076 = 36 + 64 = 100. So, x = 2 for IV. The values of x are 6 (for I), 3 (for II), 4 (for III), and 2 (for IV). The smallest value of x is 2, which occurs in case IV. The problem requires evaluating a custom-defined binary operation and solving equations involving it by testing values, likely integers or simple fractions, as the structure of the equations (exponential and polynomial terms) makes analytical solutions difficult.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-a-%e2%8a%95-b-is-defined-as-a%e1%b5%87-b%e1%b5%83-then-consider-i-2-%e2%8a%95-x-100-ii-4\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"If a \u2295 b is defined as a\u1d47 + b\u1d43, then consider : I 2 \u2295 x = 100 II 4"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89229","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=89229"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89229\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=89229"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=89229"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=89229"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}