{"id":89219,"date":"2025-06-01T09:59:14","date_gmt":"2025-06-01T09:59:14","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=89219"},"modified":"2025-06-01T09:59:14","modified_gmt":"2025-06-01T09:59:14","slug":"the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/","title":{"rendered":"The following figure shows the displacement time (x-t) graph of a body"},"content":{"rendered":"

The following figure shows the displacement time (x-t) graph of a body in motion. The ratio of the speed in first second and that in next two seconds is :<\/p>\n

[amp_mcq option1=”1 : 2″ option2=”1 : 3″ option3=”3 : 1″ option4=”2 : 1″ correct=”option4″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC CAPF – 2009<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nThe correct option is D) 2 : 1.
\n<\/section>\n
\nThe speed of the body is given by the magnitude of the slope of the displacement-time (x-t) graph.
\nIn the first second (from t=0 to t=1), the displacement changes from 0 to 3. The velocity is `(3 – 0) \/ (1 – 0) = 3\/1 = 3` units\/second. The speed in the first second (v1) is `|3| = 3`.
\nIn the next two seconds (from t=1 to t=3), the displacement changes from 3 to 0. The velocity is `(0 – 3) \/ (3 – 1) = -3\/2` units\/second. The speed in the next two seconds (v2) is `|-3\/2| = 3\/2`.
\nThe ratio of the speed in the first second and that in the next two seconds is `v1 : v2 = 3 : (3\/2)`. To express this ratio in integers, we can multiply both parts by 2: `(3 * 2) : (3\/2 * 2) = 6 : 3`. Dividing by 3, we get the simplified ratio `2 : 1`.
\n<\/section>\n
\nThe displacement-time graph provides information about the position of the body over time. Velocity is the rate of change of displacement, and speed is the magnitude of velocity. A positive slope indicates movement in one direction, while a negative slope indicates movement in the opposite direction. In this graph, the body moves from x=0 to x=3 in the first second and then back from x=3 to x=0 in the subsequent two seconds.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

The following figure shows the displacement time (x-t) graph of a body in motion. The ratio of the speed in first second and that in next two seconds is : [amp_mcq option1=”1 : 2″ option2=”1 : 3″ option3=”3 : 1″ option4=”2 : 1″ correct=”option4″] This question was previously asked in UPSC CAPF – 2009 Download … <\/p>\n

Detailed SolutionThe following figure shows the displacement time (x-t) graph of a body<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1085],"tags":[1462,1129,1128],"class_list":["post-89219","post","type-post","status-publish","format-standard","hentry","category-upsc-capf","tag-1462","tag-mechanics","tag-physics","no-featured-image-padding"],"yoast_head":"\nThe following figure shows the displacement time (x-t) graph of a body<\/title>\n<meta name=\"description\" content=\"The correct option is D) 2 : 1. The speed of the body is given by the magnitude of the slope of the displacement-time (x-t) graph. In the first second (from t=0 to t=1), the displacement changes from 0 to 3. The velocity is `(3 - 0) \/ (1 - 0) = 3\/1 = 3` units\/second. The speed in the first second (v1) is `|3| = 3`. In the next two seconds (from t=1 to t=3), the displacement changes from 3 to 0. The velocity is `(0 - 3) \/ (3 - 1) = -3\/2` units\/second. The speed in the next two seconds (v2) is `|-3\/2| = 3\/2`. The ratio of the speed in the first second and that in the next two seconds is `v1 : v2 = 3 : (3\/2)`. To express this ratio in integers, we can multiply both parts by 2: `(3 * 2) : (3\/2 * 2) = 6 : 3`. Dividing by 3, we get the simplified ratio `2 : 1`.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The following figure shows the displacement time (x-t) graph of a body\" \/>\n<meta property=\"og:description\" content=\"The correct option is D) 2 : 1. The speed of the body is given by the magnitude of the slope of the displacement-time (x-t) graph. In the first second (from t=0 to t=1), the displacement changes from 0 to 3. The velocity is `(3 - 0) \/ (1 - 0) = 3\/1 = 3` units\/second. The speed in the first second (v1) is `|3| = 3`. In the next two seconds (from t=1 to t=3), the displacement changes from 3 to 0. The velocity is `(0 - 3) \/ (3 - 1) = -3\/2` units\/second. The speed in the next two seconds (v2) is `|-3\/2| = 3\/2`. The ratio of the speed in the first second and that in the next two seconds is `v1 : v2 = 3 : (3\/2)`. To express this ratio in integers, we can multiply both parts by 2: `(3 * 2) : (3\/2 * 2) = 6 : 3`. Dividing by 3, we get the simplified ratio `2 : 1`.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T09:59:14+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"The following figure shows the displacement time (x-t) graph of a body","description":"The correct option is D) 2 : 1. The speed of the body is given by the magnitude of the slope of the displacement-time (x-t) graph. In the first second (from t=0 to t=1), the displacement changes from 0 to 3. The velocity is `(3 - 0) \/ (1 - 0) = 3\/1 = 3` units\/second. The speed in the first second (v1) is `|3| = 3`. In the next two seconds (from t=1 to t=3), the displacement changes from 3 to 0. The velocity is `(0 - 3) \/ (3 - 1) = -3\/2` units\/second. The speed in the next two seconds (v2) is `|-3\/2| = 3\/2`. The ratio of the speed in the first second and that in the next two seconds is `v1 : v2 = 3 : (3\/2)`. To express this ratio in integers, we can multiply both parts by 2: `(3 * 2) : (3\/2 * 2) = 6 : 3`. Dividing by 3, we get the simplified ratio `2 : 1`.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/","og_locale":"en_US","og_type":"article","og_title":"The following figure shows the displacement time (x-t) graph of a body","og_description":"The correct option is D) 2 : 1. The speed of the body is given by the magnitude of the slope of the displacement-time (x-t) graph. In the first second (from t=0 to t=1), the displacement changes from 0 to 3. The velocity is `(3 - 0) \/ (1 - 0) = 3\/1 = 3` units\/second. The speed in the first second (v1) is `|3| = 3`. In the next two seconds (from t=1 to t=3), the displacement changes from 3 to 0. The velocity is `(0 - 3) \/ (3 - 1) = -3\/2` units\/second. The speed in the next two seconds (v2) is `|-3\/2| = 3\/2`. The ratio of the speed in the first second and that in the next two seconds is `v1 : v2 = 3 : (3\/2)`. To express this ratio in integers, we can multiply both parts by 2: `(3 * 2) : (3\/2 * 2) = 6 : 3`. Dividing by 3, we get the simplified ratio `2 : 1`.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T09:59:14+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/","url":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/","name":"The following figure shows the displacement time (x-t) graph of a body","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T09:59:14+00:00","dateModified":"2025-06-01T09:59:14+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"The correct option is D) 2 : 1. The speed of the body is given by the magnitude of the slope of the displacement-time (x-t) graph. In the first second (from t=0 to t=1), the displacement changes from 0 to 3. The velocity is `(3 - 0) \/ (1 - 0) = 3\/1 = 3` units\/second. The speed in the first second (v1) is `|3| = 3`. In the next two seconds (from t=1 to t=3), the displacement changes from 3 to 0. The velocity is `(0 - 3) \/ (3 - 1) = -3\/2` units\/second. The speed in the next two seconds (v2) is `|-3\/2| = 3\/2`. The ratio of the speed in the first second and that in the next two seconds is `v1 : v2 = 3 : (3\/2)`. To express this ratio in integers, we can multiply both parts by 2: `(3 * 2) : (3\/2 * 2) = 6 : 3`. Dividing by 3, we get the simplified ratio `2 : 1`.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/the-following-figure-shows-the-displacement-time-x-t-graph-of-a-body\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC CAPF","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-capf\/"},{"@type":"ListItem","position":3,"name":"The following figure shows the displacement time (x-t) graph of a body"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89219","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=89219"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/89219\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=89219"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=89219"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=89219"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}