\nThe blocks are of the same material, so their weight is directly proportional to their volume. The heaviest block is the one with the largest volume. We assume the blocks are made up of unit cubes based on the visible grid lines.
\nBlock A: Appears to be a $2 \\times 1 \\times 1$ block. Volume $V_A = 2 \\times 1 \\times 1 = 2$ cubic units. (Composed of 2 unit cubes).
\nBlock B: Appears to have a $2 \\times 2$ base (4 unit cubes) and a $1 \\times 1$ block (1 unit cube) stacked on top. Total volume $V_B = (2 \\times 2 \\times 1) + (1 \\times 1 \\times 1) = 4 + 1 = 5$ cubic units. (Composed of 5 unit cubes).
\nBlock C: Appears to have an L-shaped base and a height of 2 units. The L-shaped base is a $2 \\times 2$ square with a $1 \\times 1$ corner removed, so the area of the base is $2 \\times 2 – 1 \\times 1 = 4 – 1 = 3$ square units. The height is 2 units. Total volume $V_C = \\text{Area of base} \\times \\text{Height} = 3 \\times 2 = 6$ cubic units. (Composed of 6 unit cubes).<\/p>\nComparing the volumes: $V_A = 2$, $V_B = 5$, $V_C = 6$.
\nBlock C has the largest volume (6 cubic units) and is therefore the heaviest.
\n<\/section>\n