A block of mass 2\u00b70 kg slides on a rough horizontal plane surface. Let the speed of the block at a particular instant is 10 m\/s. It comes to rest after travelling a distance of 20 m. Which one of the following could be the magnitude of the frictional force ?<\/p>\n
[amp_mcq option1=”10 N” option2=”20 N” option3=”40 N” option4=”50 N” correct=”option1″]<\/p>\n
However, 5 N is not among the options. Let’s check the options against possible work done. If the force was 10N, the work done by friction over 20m would be -10N * 20m = -200 J. This would correspond to a change in KE of -200 J, meaning the initial KE would have to be 200 J. (1\/2) * 2kg * u\u00b2 = 200 J => u\u00b2 = 200 => u = sqrt(200) \u2248 14.14 m\/s. A block of mass 2\u00b70 kg slides on a rough horizontal plane surface. Let the speed of the block at a particular instant is 10 m\/s. It comes to rest after travelling a distance of 20 m. Which one of the following could be the magnitude of the frictional force ? [amp_mcq option1=”10 N” option2=”20 … <\/p>\n
\nIf the distance was 10m instead of 20m, and the force was 10N, the work done would be -10N * 10m = -100J, matching the initial KE calculated from u=10m\/s.
\nGiven the discrepancy between the calculated value (5 N) and the provided options, and the common structure of such problems, it is highly probable there is a typo in the question’s distance value, and it was intended to be 10 m, leading to a force of 10 N (Option A). Alternatively, the options might be based on a different initial speed or mass. Assuming the question and options are from a single source and intended to have a correct answer among the choices, and that Option A is the intended answer, the underlying scenario would involve a force of 10N. While the provided data leads to 5N, Option A (10N) is the most plausible intended answer given the multiple choices.
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