{"id":88955,"date":"2025-06-01T07:25:30","date_gmt":"2025-06-01T07:25:30","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=88955"},"modified":"2025-06-01T07:25:30","modified_gmt":"2025-06-01T07:25:30","slug":"ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/","title":{"rendered":"Ramesh cannot see distinctly objects kept beyond 2 m. This defect can"},"content":{"rendered":"

Ramesh cannot see distinctly objects kept beyond 2 m. This defect can be corrected by using a lens of power<\/p>\n

[amp_mcq option1=”+ 0.5 D” option2=”- 0.5 D” option3=”+ 0.2 D” option4=”- 0.2 D” correct=”option2″]<\/p>\n

\n
\n
This question was previously asked in<\/div>\n
UPSC NDA-2 – 2023<\/div>\n<\/div>\n
Download PDF<\/a>Attempt Online<\/a><\/div>\n<\/div>\n
\nB) – 0.5 D is the correct power of the lens required to correct the defect.
\n<\/section>\n
\n– The person cannot see objects distinctly beyond 2 m, meaning their far point is 2 m. This is a condition of myopia (nearsightedness).
\n– In myopia, distant objects (effectively at infinity) are focused in front of the retina.
\n– A diverging lens (concave lens) is used to correct myopia, as it diverges incoming light rays slightly before they reach the eye lens, causing them to focus further back on the retina.
\n– Concave lenses have negative power.
\n– The corrective lens should form a virtual image of an object at infinity (u = \u221e) at the person’s far point (v = -2 m, as the image is virtual and on the same side as the object).
\n<\/section>\n
\n– Using the lens formula, 1\/f = 1\/v – 1\/u:
\n– 1\/f = 1\/(-2) – 1\/\u221e
\n– 1\/f = -1\/2 – 0
\n– 1\/f = -1\/2
\n– The power of the lens P is given by P = 1\/f (in meters).
\n– P = 1\/(-2 m) = -0.5 Diopters (D).
\n– Therefore, a concave lens of power -0.5 D is needed.
\n<\/section>\n","protected":false},"excerpt":{"rendered":"

Ramesh cannot see distinctly objects kept beyond 2 m. This defect can be corrected by using a lens of power [amp_mcq option1=”+ 0.5 D” option2=”- 0.5 D” option3=”+ 0.2 D” option4=”- 0.2 D” correct=”option2″] This question was previously asked in UPSC NDA-2 – 2023 Download PDFAttempt Online B) – 0.5 D is the correct power … <\/p>\n

Detailed SolutionRamesh cannot see distinctly objects kept beyond 2 m. This defect can<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1094],"tags":[1105,1153,1128],"class_list":["post-88955","post","type-post","status-publish","format-standard","hentry","category-upsc-nda-2","tag-1105","tag-optics","tag-physics","no-featured-image-padding"],"yoast_head":"\nRamesh cannot see distinctly objects kept beyond 2 m. This defect can<\/title>\n<meta name=\"description\" content=\"B) - 0.5 D is the correct power of the lens required to correct the defect. - The person cannot see objects distinctly beyond 2 m, meaning their far point is 2 m. This is a condition of myopia (nearsightedness). - In myopia, distant objects (effectively at infinity) are focused in front of the retina. - A diverging lens (concave lens) is used to correct myopia, as it diverges incoming light rays slightly before they reach the eye lens, causing them to focus further back on the retina. - Concave lenses have negative power. - The corrective lens should form a virtual image of an object at infinity (u = \u221e) at the person's far point (v = -2 m, as the image is virtual and on the same side as the object).\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ramesh cannot see distinctly objects kept beyond 2 m. This defect can\" \/>\n<meta property=\"og:description\" content=\"B) - 0.5 D is the correct power of the lens required to correct the defect. - The person cannot see objects distinctly beyond 2 m, meaning their far point is 2 m. This is a condition of myopia (nearsightedness). - In myopia, distant objects (effectively at infinity) are focused in front of the retina. - A diverging lens (concave lens) is used to correct myopia, as it diverges incoming light rays slightly before they reach the eye lens, causing them to focus further back on the retina. - Concave lenses have negative power. - The corrective lens should form a virtual image of an object at infinity (u = \u221e) at the person's far point (v = -2 m, as the image is virtual and on the same side as the object).\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2025-06-01T07:25:30+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Ramesh cannot see distinctly objects kept beyond 2 m. This defect can","description":"B) - 0.5 D is the correct power of the lens required to correct the defect. - The person cannot see objects distinctly beyond 2 m, meaning their far point is 2 m. This is a condition of myopia (nearsightedness). - In myopia, distant objects (effectively at infinity) are focused in front of the retina. - A diverging lens (concave lens) is used to correct myopia, as it diverges incoming light rays slightly before they reach the eye lens, causing them to focus further back on the retina. - Concave lenses have negative power. - The corrective lens should form a virtual image of an object at infinity (u = \u221e) at the person's far point (v = -2 m, as the image is virtual and on the same side as the object).","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/","og_locale":"en_US","og_type":"article","og_title":"Ramesh cannot see distinctly objects kept beyond 2 m. This defect can","og_description":"B) - 0.5 D is the correct power of the lens required to correct the defect. - The person cannot see objects distinctly beyond 2 m, meaning their far point is 2 m. This is a condition of myopia (nearsightedness). - In myopia, distant objects (effectively at infinity) are focused in front of the retina. - A diverging lens (concave lens) is used to correct myopia, as it diverges incoming light rays slightly before they reach the eye lens, causing them to focus further back on the retina. - Concave lenses have negative power. - The corrective lens should form a virtual image of an object at infinity (u = \u221e) at the person's far point (v = -2 m, as the image is virtual and on the same side as the object).","og_url":"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2025-06-01T07:25:30+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/","url":"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/","name":"Ramesh cannot see distinctly objects kept beyond 2 m. This defect can","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2025-06-01T07:25:30+00:00","dateModified":"2025-06-01T07:25:30+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"B) - 0.5 D is the correct power of the lens required to correct the defect. - The person cannot see objects distinctly beyond 2 m, meaning their far point is 2 m. This is a condition of myopia (nearsightedness). - In myopia, distant objects (effectively at infinity) are focused in front of the retina. - A diverging lens (concave lens) is used to correct myopia, as it diverges incoming light rays slightly before they reach the eye lens, causing them to focus further back on the retina. - Concave lenses have negative power. - The corrective lens should form a virtual image of an object at infinity (u = \u221e) at the person's far point (v = -2 m, as the image is virtual and on the same side as the object).","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/ramesh-cannot-see-distinctly-objects-kept-beyond-2-m-this-defect-can\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"UPSC NDA-2","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/upsc-nda-2\/"},{"@type":"ListItem","position":3,"name":"Ramesh cannot see distinctly objects kept beyond 2 m. This defect can"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88955","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=88955"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/88955\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=88955"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=88955"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=88955"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}